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Show file and directory permissons from umask value



The 2019 Stack Overflow Developer Survey Results Are InHow to set umask so that directories to be `r-x` and files to be `---`What is the effect of ACLs/umask on the permissions of the executable file generated by gcc?Setting umask of libvirt/virt-manager for proper permissions in a directory shared by host and guestHow can I backup directory and files including all sub directory and files using shell script?Delete Photos from My Pics DirectoryHow to extract a value (in a specific row and column) from a file and assign it to a new variablerun .jar program to read from 2 file and calculat the result to another fileSame Linux command with different resultsFind and rm command deleted the files inside the directory and the directory itselfhow to read value from awk command?



.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








0















I have homeword about use umask value to make default file and directory permissons, but I got a problem in the following:



If I have umask = 0541



  • 0666 - 0541 = 0125, File permisson: ---x-w-r-x

  • 0777 - 0541 = 0236, Directory permisson: d-w--wxrw-

But the actual result on linux terminal:




  • d-w--wxrw for the directory


  • --w--w-rw- for the file
    Please explain to me!





linux command







share|improve this question









New contributor




jason momoa is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.


























    0















    I have homeword about use umask value to make default file and directory permissons, but I got a problem in the following:



    If I have umask = 0541



    • 0666 - 0541 = 0125, File permisson: ---x-w-r-x

    • 0777 - 0541 = 0236, Directory permisson: d-w--wxrw-

    But the actual result on linux terminal:




    • d-w--wxrw for the directory


    • --w--w-rw- for the file
      Please explain to me!





    linux command







    share|improve this question









    New contributor




    jason momoa is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.






















      0












      0








      0








      I have homeword about use umask value to make default file and directory permissons, but I got a problem in the following:



      If I have umask = 0541



      • 0666 - 0541 = 0125, File permisson: ---x-w-r-x

      • 0777 - 0541 = 0236, Directory permisson: d-w--wxrw-

      But the actual result on linux terminal:




      • d-w--wxrw for the directory


      • --w--w-rw- for the file
        Please explain to me!





      linux command







      share|improve this question









      New contributor




      jason momoa is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.












      I have homeword about use umask value to make default file and directory permissons, but I got a problem in the following:



      If I have umask = 0541



      • 0666 - 0541 = 0125, File permisson: ---x-w-r-x

      • 0777 - 0541 = 0236, Directory permisson: d-w--wxrw-

      But the actual result on linux terminal:




      • d-w--wxrw for the directory


      • --w--w-rw- for the file
        Please explain to me!





      linux command




      linux command






      share|improve this question









      New contributor




      jason momoa is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      share|improve this question









      New contributor




      jason momoa is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.









      share|improve this question




      share|improve this question








      edited 2 days ago









      Kusalananda♦

      140k17261436




      140k17261436






      New contributor




      jason momoa is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.









      asked 2 days ago









      jason momoajason momoa

      32




      32




      New contributor




      jason momoa is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.





      New contributor





      jason momoa is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.






      jason momoa is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.




















          2 Answers
          2






          active

          oldest

          votes


















          1














          Note that umask's are not a subtraction, but a logical AND operation based on the umask.



          Think of permissions in binary:



          So a permission of 0666 would be



          110 110 110


          Now a umask of 0541 would be



          101 100 001


          To calculate the results we negate the umask:



          010 011 110


          and then AND that with the permission.



          So



          110 110 110 AND
          010 011 110
          === === ===
          010 010 110


          And that maps to -w- -w- rw-






          share|improve this answer























          • thanks you so much @Stephen ^^!, you saved my time.

            – jason momoa
            2 days ago


















          0














          Consider it like this, if you have default permissions 666 means that you have only r+w for user, group and others, and by umask 541 you want to remove permissions r+x,r,x.



          For user:



          By default you can read+write and by umask you want to remove read+executable 
          permissions, but it will never happen because initially file has no executable 
          permissions. So only read permission will be removed.


          For group:



          read permission will removed


          For others:



          There is no executable permission in the file, so there will be no change.


          Same concept applies for directories.






          share|improve this answer























          • thanks for your answer ^^, I found a trick and I think it's right:

            – jason momoa
            2 days ago











          • Please add it as answer, if it solves your problem.

            – Prvt_Yadv
            2 days ago











          • default file=0666 => -rw-rw-rw- here Umask = 0541 => -r-xr----x substract them => --w--w-rw- for the file

            – jason momoa
            2 days ago











          • I was checked any value and it's always return a true value

            – jason momoa
            2 days ago











          Your Answer








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          2 Answers
          2






          active

          oldest

          votes








          2 Answers
          2






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          1














          Note that umask's are not a subtraction, but a logical AND operation based on the umask.



          Think of permissions in binary:



          So a permission of 0666 would be



          110 110 110


          Now a umask of 0541 would be



          101 100 001


          To calculate the results we negate the umask:



          010 011 110


          and then AND that with the permission.



          So



          110 110 110 AND
          010 011 110
          === === ===
          010 010 110


          And that maps to -w- -w- rw-






          share|improve this answer























          • thanks you so much @Stephen ^^!, you saved my time.

            – jason momoa
            2 days ago















          1














          Note that umask's are not a subtraction, but a logical AND operation based on the umask.



          Think of permissions in binary:



          So a permission of 0666 would be



          110 110 110


          Now a umask of 0541 would be



          101 100 001


          To calculate the results we negate the umask:



          010 011 110


          and then AND that with the permission.



          So



          110 110 110 AND
          010 011 110
          === === ===
          010 010 110


          And that maps to -w- -w- rw-






          share|improve this answer























          • thanks you so much @Stephen ^^!, you saved my time.

            – jason momoa
            2 days ago













          1












          1








          1







          Note that umask's are not a subtraction, but a logical AND operation based on the umask.



          Think of permissions in binary:



          So a permission of 0666 would be



          110 110 110


          Now a umask of 0541 would be



          101 100 001


          To calculate the results we negate the umask:



          010 011 110


          and then AND that with the permission.



          So



          110 110 110 AND
          010 011 110
          === === ===
          010 010 110


          And that maps to -w- -w- rw-






          share|improve this answer













          Note that umask's are not a subtraction, but a logical AND operation based on the umask.



          Think of permissions in binary:



          So a permission of 0666 would be



          110 110 110


          Now a umask of 0541 would be



          101 100 001


          To calculate the results we negate the umask:



          010 011 110


          and then AND that with the permission.



          So



          110 110 110 AND
          010 011 110
          === === ===
          010 010 110


          And that maps to -w- -w- rw-







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered 2 days ago









          Stephen HarrisStephen Harris

          27.4k35383




          27.4k35383












          • thanks you so much @Stephen ^^!, you saved my time.

            – jason momoa
            2 days ago

















          • thanks you so much @Stephen ^^!, you saved my time.

            – jason momoa
            2 days ago
















          thanks you so much @Stephen ^^!, you saved my time.

          – jason momoa
          2 days ago





          thanks you so much @Stephen ^^!, you saved my time.

          – jason momoa
          2 days ago













          0














          Consider it like this, if you have default permissions 666 means that you have only r+w for user, group and others, and by umask 541 you want to remove permissions r+x,r,x.



          For user:



          By default you can read+write and by umask you want to remove read+executable 
          permissions, but it will never happen because initially file has no executable 
          permissions. So only read permission will be removed.


          For group:



          read permission will removed


          For others:



          There is no executable permission in the file, so there will be no change.


          Same concept applies for directories.






          share|improve this answer























          • thanks for your answer ^^, I found a trick and I think it's right:

            – jason momoa
            2 days ago











          • Please add it as answer, if it solves your problem.

            – Prvt_Yadv
            2 days ago











          • default file=0666 => -rw-rw-rw- here Umask = 0541 => -r-xr----x substract them => --w--w-rw- for the file

            – jason momoa
            2 days ago











          • I was checked any value and it's always return a true value

            – jason momoa
            2 days ago















          0














          Consider it like this, if you have default permissions 666 means that you have only r+w for user, group and others, and by umask 541 you want to remove permissions r+x,r,x.



          For user:



          By default you can read+write and by umask you want to remove read+executable 
          permissions, but it will never happen because initially file has no executable 
          permissions. So only read permission will be removed.


          For group:



          read permission will removed


          For others:



          There is no executable permission in the file, so there will be no change.


          Same concept applies for directories.






          share|improve this answer























          • thanks for your answer ^^, I found a trick and I think it's right:

            – jason momoa
            2 days ago











          • Please add it as answer, if it solves your problem.

            – Prvt_Yadv
            2 days ago











          • default file=0666 => -rw-rw-rw- here Umask = 0541 => -r-xr----x substract them => --w--w-rw- for the file

            – jason momoa
            2 days ago











          • I was checked any value and it's always return a true value

            – jason momoa
            2 days ago













          0












          0








          0







          Consider it like this, if you have default permissions 666 means that you have only r+w for user, group and others, and by umask 541 you want to remove permissions r+x,r,x.



          For user:



          By default you can read+write and by umask you want to remove read+executable 
          permissions, but it will never happen because initially file has no executable 
          permissions. So only read permission will be removed.


          For group:



          read permission will removed


          For others:



          There is no executable permission in the file, so there will be no change.


          Same concept applies for directories.






          share|improve this answer













          Consider it like this, if you have default permissions 666 means that you have only r+w for user, group and others, and by umask 541 you want to remove permissions r+x,r,x.



          For user:



          By default you can read+write and by umask you want to remove read+executable 
          permissions, but it will never happen because initially file has no executable 
          permissions. So only read permission will be removed.


          For group:



          read permission will removed


          For others:



          There is no executable permission in the file, so there will be no change.


          Same concept applies for directories.







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered 2 days ago









          Prvt_YadvPrvt_Yadv

          3,29631430




          3,29631430












          • thanks for your answer ^^, I found a trick and I think it's right:

            – jason momoa
            2 days ago











          • Please add it as answer, if it solves your problem.

            – Prvt_Yadv
            2 days ago











          • default file=0666 => -rw-rw-rw- here Umask = 0541 => -r-xr----x substract them => --w--w-rw- for the file

            – jason momoa
            2 days ago











          • I was checked any value and it's always return a true value

            – jason momoa
            2 days ago

















          • thanks for your answer ^^, I found a trick and I think it's right:

            – jason momoa
            2 days ago











          • Please add it as answer, if it solves your problem.

            – Prvt_Yadv
            2 days ago











          • default file=0666 => -rw-rw-rw- here Umask = 0541 => -r-xr----x substract them => --w--w-rw- for the file

            – jason momoa
            2 days ago











          • I was checked any value and it's always return a true value

            – jason momoa
            2 days ago
















          thanks for your answer ^^, I found a trick and I think it's right:

          – jason momoa
          2 days ago





          thanks for your answer ^^, I found a trick and I think it's right:

          – jason momoa
          2 days ago













          Please add it as answer, if it solves your problem.

          – Prvt_Yadv
          2 days ago





          Please add it as answer, if it solves your problem.

          – Prvt_Yadv
          2 days ago













          default file=0666 => -rw-rw-rw- here Umask = 0541 => -r-xr----x substract them => --w--w-rw- for the file

          – jason momoa
          2 days ago





          default file=0666 => -rw-rw-rw- here Umask = 0541 => -r-xr----x substract them => --w--w-rw- for the file

          – jason momoa
          2 days ago













          I was checked any value and it's always return a true value

          – jason momoa
          2 days ago





          I was checked any value and it's always return a true value

          – jason momoa
          2 days ago










          jason momoa is a new contributor. Be nice, and check out our Code of Conduct.









          draft saved

          draft discarded


















          jason momoa is a new contributor. Be nice, and check out our Code of Conduct.












          jason momoa is a new contributor. Be nice, and check out our Code of Conduct.











          jason momoa is a new contributor. Be nice, and check out our Code of Conduct.














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