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Check whether an IP belongs to a specific range



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.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








0















I have a log file that lists whitelisted IP ranges in this manner:



"217.29.0.0-217.29.255.255",
"204.12.0.0-204.12.255.255",
"198.54.223.0-198.54.223.255",


I am also working on a bash script which, amongst other things, needs to check this logfile and determine if a specified IP is whitelisted.



In the case of IP 204.12.5.10, for instance, how would I use the log file with the specified ranges to determine whether that IP is part of a range in that file?










share|improve this question
























  • Does it have to be bash? And do you need to support different address formats?

    – Sobrique
    Oct 5 '15 at 12:17











  • It has to be bash, or something called from bash (such as the ipcalc utility). The only format I will need to do this for is the above-given [range-start]-[range-end] format, as that is the format this specific logfile uses.

    – wbruan
    Oct 5 '15 at 12:19











  • Nopte that the aaa.bbb.ccc.ddd format is just custom, but you can trivially convert that to any other format. And if you convert it to decimal then you can simply check with the larger than and small than operators. (actually => and =<, since you probably want to include the edges).

    – Hennes
    Oct 5 '15 at 12:28

















0















I have a log file that lists whitelisted IP ranges in this manner:



"217.29.0.0-217.29.255.255",
"204.12.0.0-204.12.255.255",
"198.54.223.0-198.54.223.255",


I am also working on a bash script which, amongst other things, needs to check this logfile and determine if a specified IP is whitelisted.



In the case of IP 204.12.5.10, for instance, how would I use the log file with the specified ranges to determine whether that IP is part of a range in that file?










share|improve this question
























  • Does it have to be bash? And do you need to support different address formats?

    – Sobrique
    Oct 5 '15 at 12:17











  • It has to be bash, or something called from bash (such as the ipcalc utility). The only format I will need to do this for is the above-given [range-start]-[range-end] format, as that is the format this specific logfile uses.

    – wbruan
    Oct 5 '15 at 12:19











  • Nopte that the aaa.bbb.ccc.ddd format is just custom, but you can trivially convert that to any other format. And if you convert it to decimal then you can simply check with the larger than and small than operators. (actually => and =<, since you probably want to include the edges).

    – Hennes
    Oct 5 '15 at 12:28













0












0








0








I have a log file that lists whitelisted IP ranges in this manner:



"217.29.0.0-217.29.255.255",
"204.12.0.0-204.12.255.255",
"198.54.223.0-198.54.223.255",


I am also working on a bash script which, amongst other things, needs to check this logfile and determine if a specified IP is whitelisted.



In the case of IP 204.12.5.10, for instance, how would I use the log file with the specified ranges to determine whether that IP is part of a range in that file?










share|improve this question
















I have a log file that lists whitelisted IP ranges in this manner:



"217.29.0.0-217.29.255.255",
"204.12.0.0-204.12.255.255",
"198.54.223.0-198.54.223.255",


I am also working on a bash script which, amongst other things, needs to check this logfile and determine if a specified IP is whitelisted.



In the case of IP 204.12.5.10, for instance, how would I use the log file with the specified ranges to determine whether that IP is part of a range in that file?







bash scripting ip






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Oct 5 '15 at 12:20







wbruan

















asked Oct 5 '15 at 12:11









wbruanwbruan

335139




335139












  • Does it have to be bash? And do you need to support different address formats?

    – Sobrique
    Oct 5 '15 at 12:17











  • It has to be bash, or something called from bash (such as the ipcalc utility). The only format I will need to do this for is the above-given [range-start]-[range-end] format, as that is the format this specific logfile uses.

    – wbruan
    Oct 5 '15 at 12:19











  • Nopte that the aaa.bbb.ccc.ddd format is just custom, but you can trivially convert that to any other format. And if you convert it to decimal then you can simply check with the larger than and small than operators. (actually => and =<, since you probably want to include the edges).

    – Hennes
    Oct 5 '15 at 12:28

















  • Does it have to be bash? And do you need to support different address formats?

    – Sobrique
    Oct 5 '15 at 12:17











  • It has to be bash, or something called from bash (such as the ipcalc utility). The only format I will need to do this for is the above-given [range-start]-[range-end] format, as that is the format this specific logfile uses.

    – wbruan
    Oct 5 '15 at 12:19











  • Nopte that the aaa.bbb.ccc.ddd format is just custom, but you can trivially convert that to any other format. And if you convert it to decimal then you can simply check with the larger than and small than operators. (actually => and =<, since you probably want to include the edges).

    – Hennes
    Oct 5 '15 at 12:28
















Does it have to be bash? And do you need to support different address formats?

– Sobrique
Oct 5 '15 at 12:17





Does it have to be bash? And do you need to support different address formats?

– Sobrique
Oct 5 '15 at 12:17













It has to be bash, or something called from bash (such as the ipcalc utility). The only format I will need to do this for is the above-given [range-start]-[range-end] format, as that is the format this specific logfile uses.

– wbruan
Oct 5 '15 at 12:19





It has to be bash, or something called from bash (such as the ipcalc utility). The only format I will need to do this for is the above-given [range-start]-[range-end] format, as that is the format this specific logfile uses.

– wbruan
Oct 5 '15 at 12:19













Nopte that the aaa.bbb.ccc.ddd format is just custom, but you can trivially convert that to any other format. And if you convert it to decimal then you can simply check with the larger than and small than operators. (actually => and =<, since you probably want to include the edges).

– Hennes
Oct 5 '15 at 12:28





Nopte that the aaa.bbb.ccc.ddd format is just custom, but you can trivially convert that to any other format. And if you convert it to decimal then you can simply check with the larger than and small than operators. (actually => and =<, since you probably want to include the edges).

– Hennes
Oct 5 '15 at 12:28










2 Answers
2






active

oldest

votes


















2














The useful thing to remember with IP addresses is that they're actually just representations of a 32bit number.



So you can convert them to a decimal by multiplying the octets as base 256.



E.g.:



217.29.0.0 == 216 * 256 ^ 3 + 29 * 256 ^2 + 0 * 256 ^1 + 0 * 256 ^ 0
== 3640655872


So given a range like the above - first convert them both, such that you've got a start and end. Then compare any incoming IPs to see if they 'fit'.



So something like this (illustrating algorithm):



#!/usr/bin/env perl
use strict;
use warnings;

my $ip_to_check = "204.12.5.10";
my $dword = 0;
for ( split( '.', $ip_to_check ) ) $dword *= 256; $dword += $_
print "Checking $dwordn";

while (<DATA>)
my ( $start, $finish ) = m/([d.]+)/g;
my $start_dword = 0;
for ( split '.', $start ) $start_dword *= 256; $start_dword += $_
my $end_dword = 0;
for ( split '.', $finish ) $end_dword *= 256; $end_dword += $_
print "Range:n";
print "t$start t=> $start_dwordn";
print "t$finish t=> $end_dwordn";

print "$ip_to_check is in $_n" if $dword >= $start_dword and $dword <= $end_dword;


__DATA__
"217.29.0.0-217.29.255.255",
"204.12.0.0-204.12.255.255",
"198.54.223.0-198.54.223.255",


Could quite easily do that as a 'check script' - by reading a file (rather than DATA) and getting $ip_to_check from STDIN).



(note - as pure perl could be turned into a one liner fairly easily, or a script to call. Or re-written - I daresay you could do this with expr easily enough).






share|improve this answer























  • Though perl and not bash, this did work for my purposes. Thank you.

    – wbruan
    Oct 7 '15 at 5:08











  • Yes, I'm afraid I defected to perl many years ago when I started to stretch the limits of what could be done in bash. Fortunately, it's almost as ubiquitous, so you're not really inhibiting yourself much. (And in some cases - it's more common, for example if you're ever having to interact with AIX or another OS that doesn't do bash by default)

    – Sobrique
    Oct 7 '15 at 9:09


















1














Here's an awk version:



want=204.12.77.5
awk -v want=$want -F- '
function canon(ip)
split(" "ip,x,/[^0-9]+/)
return sprintf("%03d%03d%03d%03d",x[2],x[3],x[4],x[5])

BEGIN val = canon(want)
low = canon($1); high = canon($2);
if(val>=low && val<=high)print "in range " $0
' mylogfile


The function canon takes an ip address, splits out the number fields,
then extends each to 3 digits and returns the string.
It is called for the 2 values on each line, and these are
compared with the wanted ip address (set at the start), which
has also been "canonified".






share|improve this answer























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    2 Answers
    2






    active

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    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    2














    The useful thing to remember with IP addresses is that they're actually just representations of a 32bit number.



    So you can convert them to a decimal by multiplying the octets as base 256.



    E.g.:



    217.29.0.0 == 216 * 256 ^ 3 + 29 * 256 ^2 + 0 * 256 ^1 + 0 * 256 ^ 0
    == 3640655872


    So given a range like the above - first convert them both, such that you've got a start and end. Then compare any incoming IPs to see if they 'fit'.



    So something like this (illustrating algorithm):



    #!/usr/bin/env perl
    use strict;
    use warnings;

    my $ip_to_check = "204.12.5.10";
    my $dword = 0;
    for ( split( '.', $ip_to_check ) ) $dword *= 256; $dword += $_
    print "Checking $dwordn";

    while (<DATA>)
    my ( $start, $finish ) = m/([d.]+)/g;
    my $start_dword = 0;
    for ( split '.', $start ) $start_dword *= 256; $start_dword += $_
    my $end_dword = 0;
    for ( split '.', $finish ) $end_dword *= 256; $end_dword += $_
    print "Range:n";
    print "t$start t=> $start_dwordn";
    print "t$finish t=> $end_dwordn";

    print "$ip_to_check is in $_n" if $dword >= $start_dword and $dword <= $end_dword;


    __DATA__
    "217.29.0.0-217.29.255.255",
    "204.12.0.0-204.12.255.255",
    "198.54.223.0-198.54.223.255",


    Could quite easily do that as a 'check script' - by reading a file (rather than DATA) and getting $ip_to_check from STDIN).



    (note - as pure perl could be turned into a one liner fairly easily, or a script to call. Or re-written - I daresay you could do this with expr easily enough).






    share|improve this answer























    • Though perl and not bash, this did work for my purposes. Thank you.

      – wbruan
      Oct 7 '15 at 5:08











    • Yes, I'm afraid I defected to perl many years ago when I started to stretch the limits of what could be done in bash. Fortunately, it's almost as ubiquitous, so you're not really inhibiting yourself much. (And in some cases - it's more common, for example if you're ever having to interact with AIX or another OS that doesn't do bash by default)

      – Sobrique
      Oct 7 '15 at 9:09















    2














    The useful thing to remember with IP addresses is that they're actually just representations of a 32bit number.



    So you can convert them to a decimal by multiplying the octets as base 256.



    E.g.:



    217.29.0.0 == 216 * 256 ^ 3 + 29 * 256 ^2 + 0 * 256 ^1 + 0 * 256 ^ 0
    == 3640655872


    So given a range like the above - first convert them both, such that you've got a start and end. Then compare any incoming IPs to see if they 'fit'.



    So something like this (illustrating algorithm):



    #!/usr/bin/env perl
    use strict;
    use warnings;

    my $ip_to_check = "204.12.5.10";
    my $dword = 0;
    for ( split( '.', $ip_to_check ) ) $dword *= 256; $dword += $_
    print "Checking $dwordn";

    while (<DATA>)
    my ( $start, $finish ) = m/([d.]+)/g;
    my $start_dword = 0;
    for ( split '.', $start ) $start_dword *= 256; $start_dword += $_
    my $end_dword = 0;
    for ( split '.', $finish ) $end_dword *= 256; $end_dword += $_
    print "Range:n";
    print "t$start t=> $start_dwordn";
    print "t$finish t=> $end_dwordn";

    print "$ip_to_check is in $_n" if $dword >= $start_dword and $dword <= $end_dword;


    __DATA__
    "217.29.0.0-217.29.255.255",
    "204.12.0.0-204.12.255.255",
    "198.54.223.0-198.54.223.255",


    Could quite easily do that as a 'check script' - by reading a file (rather than DATA) and getting $ip_to_check from STDIN).



    (note - as pure perl could be turned into a one liner fairly easily, or a script to call. Or re-written - I daresay you could do this with expr easily enough).






    share|improve this answer























    • Though perl and not bash, this did work for my purposes. Thank you.

      – wbruan
      Oct 7 '15 at 5:08











    • Yes, I'm afraid I defected to perl many years ago when I started to stretch the limits of what could be done in bash. Fortunately, it's almost as ubiquitous, so you're not really inhibiting yourself much. (And in some cases - it's more common, for example if you're ever having to interact with AIX or another OS that doesn't do bash by default)

      – Sobrique
      Oct 7 '15 at 9:09













    2












    2








    2







    The useful thing to remember with IP addresses is that they're actually just representations of a 32bit number.



    So you can convert them to a decimal by multiplying the octets as base 256.



    E.g.:



    217.29.0.0 == 216 * 256 ^ 3 + 29 * 256 ^2 + 0 * 256 ^1 + 0 * 256 ^ 0
    == 3640655872


    So given a range like the above - first convert them both, such that you've got a start and end. Then compare any incoming IPs to see if they 'fit'.



    So something like this (illustrating algorithm):



    #!/usr/bin/env perl
    use strict;
    use warnings;

    my $ip_to_check = "204.12.5.10";
    my $dword = 0;
    for ( split( '.', $ip_to_check ) ) $dword *= 256; $dword += $_
    print "Checking $dwordn";

    while (<DATA>)
    my ( $start, $finish ) = m/([d.]+)/g;
    my $start_dword = 0;
    for ( split '.', $start ) $start_dword *= 256; $start_dword += $_
    my $end_dword = 0;
    for ( split '.', $finish ) $end_dword *= 256; $end_dword += $_
    print "Range:n";
    print "t$start t=> $start_dwordn";
    print "t$finish t=> $end_dwordn";

    print "$ip_to_check is in $_n" if $dword >= $start_dword and $dword <= $end_dword;


    __DATA__
    "217.29.0.0-217.29.255.255",
    "204.12.0.0-204.12.255.255",
    "198.54.223.0-198.54.223.255",


    Could quite easily do that as a 'check script' - by reading a file (rather than DATA) and getting $ip_to_check from STDIN).



    (note - as pure perl could be turned into a one liner fairly easily, or a script to call. Or re-written - I daresay you could do this with expr easily enough).






    share|improve this answer













    The useful thing to remember with IP addresses is that they're actually just representations of a 32bit number.



    So you can convert them to a decimal by multiplying the octets as base 256.



    E.g.:



    217.29.0.0 == 216 * 256 ^ 3 + 29 * 256 ^2 + 0 * 256 ^1 + 0 * 256 ^ 0
    == 3640655872


    So given a range like the above - first convert them both, such that you've got a start and end. Then compare any incoming IPs to see if they 'fit'.



    So something like this (illustrating algorithm):



    #!/usr/bin/env perl
    use strict;
    use warnings;

    my $ip_to_check = "204.12.5.10";
    my $dword = 0;
    for ( split( '.', $ip_to_check ) ) $dword *= 256; $dword += $_
    print "Checking $dwordn";

    while (<DATA>)
    my ( $start, $finish ) = m/([d.]+)/g;
    my $start_dword = 0;
    for ( split '.', $start ) $start_dword *= 256; $start_dword += $_
    my $end_dword = 0;
    for ( split '.', $finish ) $end_dword *= 256; $end_dword += $_
    print "Range:n";
    print "t$start t=> $start_dwordn";
    print "t$finish t=> $end_dwordn";

    print "$ip_to_check is in $_n" if $dword >= $start_dword and $dword <= $end_dword;


    __DATA__
    "217.29.0.0-217.29.255.255",
    "204.12.0.0-204.12.255.255",
    "198.54.223.0-198.54.223.255",


    Could quite easily do that as a 'check script' - by reading a file (rather than DATA) and getting $ip_to_check from STDIN).



    (note - as pure perl could be turned into a one liner fairly easily, or a script to call. Or re-written - I daresay you could do this with expr easily enough).







    share|improve this answer












    share|improve this answer



    share|improve this answer










    answered Oct 5 '15 at 12:31









    SobriqueSobrique

    3,839519




    3,839519












    • Though perl and not bash, this did work for my purposes. Thank you.

      – wbruan
      Oct 7 '15 at 5:08











    • Yes, I'm afraid I defected to perl many years ago when I started to stretch the limits of what could be done in bash. Fortunately, it's almost as ubiquitous, so you're not really inhibiting yourself much. (And in some cases - it's more common, for example if you're ever having to interact with AIX or another OS that doesn't do bash by default)

      – Sobrique
      Oct 7 '15 at 9:09

















    • Though perl and not bash, this did work for my purposes. Thank you.

      – wbruan
      Oct 7 '15 at 5:08











    • Yes, I'm afraid I defected to perl many years ago when I started to stretch the limits of what could be done in bash. Fortunately, it's almost as ubiquitous, so you're not really inhibiting yourself much. (And in some cases - it's more common, for example if you're ever having to interact with AIX or another OS that doesn't do bash by default)

      – Sobrique
      Oct 7 '15 at 9:09
















    Though perl and not bash, this did work for my purposes. Thank you.

    – wbruan
    Oct 7 '15 at 5:08





    Though perl and not bash, this did work for my purposes. Thank you.

    – wbruan
    Oct 7 '15 at 5:08













    Yes, I'm afraid I defected to perl many years ago when I started to stretch the limits of what could be done in bash. Fortunately, it's almost as ubiquitous, so you're not really inhibiting yourself much. (And in some cases - it's more common, for example if you're ever having to interact with AIX or another OS that doesn't do bash by default)

    – Sobrique
    Oct 7 '15 at 9:09





    Yes, I'm afraid I defected to perl many years ago when I started to stretch the limits of what could be done in bash. Fortunately, it's almost as ubiquitous, so you're not really inhibiting yourself much. (And in some cases - it's more common, for example if you're ever having to interact with AIX or another OS that doesn't do bash by default)

    – Sobrique
    Oct 7 '15 at 9:09













    1














    Here's an awk version:



    want=204.12.77.5
    awk -v want=$want -F- '
    function canon(ip)
    split(" "ip,x,/[^0-9]+/)
    return sprintf("%03d%03d%03d%03d",x[2],x[3],x[4],x[5])

    BEGIN val = canon(want)
    low = canon($1); high = canon($2);
    if(val>=low && val<=high)print "in range " $0
    ' mylogfile


    The function canon takes an ip address, splits out the number fields,
    then extends each to 3 digits and returns the string.
    It is called for the 2 values on each line, and these are
    compared with the wanted ip address (set at the start), which
    has also been "canonified".






    share|improve this answer



























      1














      Here's an awk version:



      want=204.12.77.5
      awk -v want=$want -F- '
      function canon(ip)
      split(" "ip,x,/[^0-9]+/)
      return sprintf("%03d%03d%03d%03d",x[2],x[3],x[4],x[5])

      BEGIN val = canon(want)
      low = canon($1); high = canon($2);
      if(val>=low && val<=high)print "in range " $0
      ' mylogfile


      The function canon takes an ip address, splits out the number fields,
      then extends each to 3 digits and returns the string.
      It is called for the 2 values on each line, and these are
      compared with the wanted ip address (set at the start), which
      has also been "canonified".






      share|improve this answer

























        1












        1








        1







        Here's an awk version:



        want=204.12.77.5
        awk -v want=$want -F- '
        function canon(ip)
        split(" "ip,x,/[^0-9]+/)
        return sprintf("%03d%03d%03d%03d",x[2],x[3],x[4],x[5])

        BEGIN val = canon(want)
        low = canon($1); high = canon($2);
        if(val>=low && val<=high)print "in range " $0
        ' mylogfile


        The function canon takes an ip address, splits out the number fields,
        then extends each to 3 digits and returns the string.
        It is called for the 2 values on each line, and these are
        compared with the wanted ip address (set at the start), which
        has also been "canonified".






        share|improve this answer













        Here's an awk version:



        want=204.12.77.5
        awk -v want=$want -F- '
        function canon(ip)
        split(" "ip,x,/[^0-9]+/)
        return sprintf("%03d%03d%03d%03d",x[2],x[3],x[4],x[5])

        BEGIN val = canon(want)
        low = canon($1); high = canon($2);
        if(val>=low && val<=high)print "in range " $0
        ' mylogfile


        The function canon takes an ip address, splits out the number fields,
        then extends each to 3 digits and returns the string.
        It is called for the 2 values on each line, and these are
        compared with the wanted ip address (set at the start), which
        has also been "canonified".







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Oct 5 '15 at 13:27









        meuhmeuh

        32.5k12255




        32.5k12255



























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