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Check whether an IP belongs to a specific range
The 2019 Stack Overflow Developer Survey Results Are Inbc command unexpected resultsQuickly check whether many network hosts are up-and-runningIn a Bash if condition, how to check whether any files matching a simple wildcard expression exist?bash script to check file ownershipCheck if $REPLY is in a range of numbersgrep (/sed/awk) month rangeScript to remove IPs or network ranges from an IP spaceCheck in bash if make has done somethingI want to measure the time between two jobs in a logfileextract time range from log file using AWKHow do I check if I am in a graphical environment on a Mac using bash?
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;
I have a log file that lists whitelisted IP ranges in this manner:
"217.29.0.0-217.29.255.255",
"204.12.0.0-204.12.255.255",
"198.54.223.0-198.54.223.255",
I am also working on a bash script which, amongst other things, needs to check this logfile and determine if a specified IP is whitelisted.
In the case of IP 204.12.5.10
, for instance, how would I use the log file with the specified ranges to determine whether that IP is part of a range in that file?
bash scripting ip
add a comment |
I have a log file that lists whitelisted IP ranges in this manner:
"217.29.0.0-217.29.255.255",
"204.12.0.0-204.12.255.255",
"198.54.223.0-198.54.223.255",
I am also working on a bash script which, amongst other things, needs to check this logfile and determine if a specified IP is whitelisted.
In the case of IP 204.12.5.10
, for instance, how would I use the log file with the specified ranges to determine whether that IP is part of a range in that file?
bash scripting ip
Does it have to be bash? And do you need to support different address formats?
– Sobrique
Oct 5 '15 at 12:17
It has to be bash, or something called from bash (such as theipcalc
utility). The only format I will need to do this for is the above-given [range-start]-[range-end] format, as that is the format this specific logfile uses.
– wbruan
Oct 5 '15 at 12:19
Nopte that the aaa.bbb.ccc.ddd format is just custom, but you can trivially convert that to any other format. And if you convert it to decimal then you can simply check with the larger than and small than operators. (actually=>
and=<
, since you probably want to include the edges).
– Hennes
Oct 5 '15 at 12:28
add a comment |
I have a log file that lists whitelisted IP ranges in this manner:
"217.29.0.0-217.29.255.255",
"204.12.0.0-204.12.255.255",
"198.54.223.0-198.54.223.255",
I am also working on a bash script which, amongst other things, needs to check this logfile and determine if a specified IP is whitelisted.
In the case of IP 204.12.5.10
, for instance, how would I use the log file with the specified ranges to determine whether that IP is part of a range in that file?
bash scripting ip
I have a log file that lists whitelisted IP ranges in this manner:
"217.29.0.0-217.29.255.255",
"204.12.0.0-204.12.255.255",
"198.54.223.0-198.54.223.255",
I am also working on a bash script which, amongst other things, needs to check this logfile and determine if a specified IP is whitelisted.
In the case of IP 204.12.5.10
, for instance, how would I use the log file with the specified ranges to determine whether that IP is part of a range in that file?
bash scripting ip
bash scripting ip
edited Oct 5 '15 at 12:20
wbruan
asked Oct 5 '15 at 12:11
wbruanwbruan
335139
335139
Does it have to be bash? And do you need to support different address formats?
– Sobrique
Oct 5 '15 at 12:17
It has to be bash, or something called from bash (such as theipcalc
utility). The only format I will need to do this for is the above-given [range-start]-[range-end] format, as that is the format this specific logfile uses.
– wbruan
Oct 5 '15 at 12:19
Nopte that the aaa.bbb.ccc.ddd format is just custom, but you can trivially convert that to any other format. And if you convert it to decimal then you can simply check with the larger than and small than operators. (actually=>
and=<
, since you probably want to include the edges).
– Hennes
Oct 5 '15 at 12:28
add a comment |
Does it have to be bash? And do you need to support different address formats?
– Sobrique
Oct 5 '15 at 12:17
It has to be bash, or something called from bash (such as theipcalc
utility). The only format I will need to do this for is the above-given [range-start]-[range-end] format, as that is the format this specific logfile uses.
– wbruan
Oct 5 '15 at 12:19
Nopte that the aaa.bbb.ccc.ddd format is just custom, but you can trivially convert that to any other format. And if you convert it to decimal then you can simply check with the larger than and small than operators. (actually=>
and=<
, since you probably want to include the edges).
– Hennes
Oct 5 '15 at 12:28
Does it have to be bash? And do you need to support different address formats?
– Sobrique
Oct 5 '15 at 12:17
Does it have to be bash? And do you need to support different address formats?
– Sobrique
Oct 5 '15 at 12:17
It has to be bash, or something called from bash (such as the
ipcalc
utility). The only format I will need to do this for is the above-given [range-start]-[range-end] format, as that is the format this specific logfile uses.– wbruan
Oct 5 '15 at 12:19
It has to be bash, or something called from bash (such as the
ipcalc
utility). The only format I will need to do this for is the above-given [range-start]-[range-end] format, as that is the format this specific logfile uses.– wbruan
Oct 5 '15 at 12:19
Nopte that the aaa.bbb.ccc.ddd format is just custom, but you can trivially convert that to any other format. And if you convert it to decimal then you can simply check with the larger than and small than operators. (actually
=>
and =<
, since you probably want to include the edges).– Hennes
Oct 5 '15 at 12:28
Nopte that the aaa.bbb.ccc.ddd format is just custom, but you can trivially convert that to any other format. And if you convert it to decimal then you can simply check with the larger than and small than operators. (actually
=>
and =<
, since you probably want to include the edges).– Hennes
Oct 5 '15 at 12:28
add a comment |
2 Answers
2
active
oldest
votes
The useful thing to remember with IP addresses is that they're actually just representations of a 32bit number.
So you can convert them to a decimal by multiplying the octets as base 256.
E.g.:
217.29.0.0 == 216 * 256 ^ 3 + 29 * 256 ^2 + 0 * 256 ^1 + 0 * 256 ^ 0
== 3640655872
So given a range like the above - first convert them both, such that you've got a start and end. Then compare any incoming IPs to see if they 'fit'.
So something like this (illustrating algorithm):
#!/usr/bin/env perl
use strict;
use warnings;
my $ip_to_check = "204.12.5.10";
my $dword = 0;
for ( split( '.', $ip_to_check ) ) $dword *= 256; $dword += $_
print "Checking $dwordn";
while (<DATA>)
my ( $start, $finish ) = m/([d.]+)/g;
my $start_dword = 0;
for ( split '.', $start ) $start_dword *= 256; $start_dword += $_
my $end_dword = 0;
for ( split '.', $finish ) $end_dword *= 256; $end_dword += $_
print "Range:n";
print "t$start t=> $start_dwordn";
print "t$finish t=> $end_dwordn";
print "$ip_to_check is in $_n" if $dword >= $start_dword and $dword <= $end_dword;
__DATA__
"217.29.0.0-217.29.255.255",
"204.12.0.0-204.12.255.255",
"198.54.223.0-198.54.223.255",
Could quite easily do that as a 'check script' - by reading a file (rather than DATA
) and getting $ip_to_check
from STDIN
).
(note - as pure perl
could be turned into a one liner fairly easily, or a script to call. Or re-written - I daresay you could do this with expr
easily enough).
Though perl and not bash, this did work for my purposes. Thank you.
– wbruan
Oct 7 '15 at 5:08
Yes, I'm afraid I defected toperl
many years ago when I started to stretch the limits of what could be done inbash
. Fortunately, it's almost as ubiquitous, so you're not really inhibiting yourself much. (And in some cases - it's more common, for example if you're ever having to interact with AIX or another OS that doesn't dobash
by default)
– Sobrique
Oct 7 '15 at 9:09
add a comment |
Here's an awk version:
want=204.12.77.5
awk -v want=$want -F- '
function canon(ip)
split(" "ip,x,/[^0-9]+/)
return sprintf("%03d%03d%03d%03d",x[2],x[3],x[4],x[5])
BEGIN val = canon(want)
low = canon($1); high = canon($2);
if(val>=low && val<=high)print "in range " $0
' mylogfile
The function canon
takes an ip address, splits out the number fields,
then extends each to 3 digits and returns the string.
It is called for the 2 values on each line, and these are
compared with the wanted ip address (set at the start), which
has also been "canonified".
add a comment |
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2 Answers
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oldest
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2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
The useful thing to remember with IP addresses is that they're actually just representations of a 32bit number.
So you can convert them to a decimal by multiplying the octets as base 256.
E.g.:
217.29.0.0 == 216 * 256 ^ 3 + 29 * 256 ^2 + 0 * 256 ^1 + 0 * 256 ^ 0
== 3640655872
So given a range like the above - first convert them both, such that you've got a start and end. Then compare any incoming IPs to see if they 'fit'.
So something like this (illustrating algorithm):
#!/usr/bin/env perl
use strict;
use warnings;
my $ip_to_check = "204.12.5.10";
my $dword = 0;
for ( split( '.', $ip_to_check ) ) $dword *= 256; $dword += $_
print "Checking $dwordn";
while (<DATA>)
my ( $start, $finish ) = m/([d.]+)/g;
my $start_dword = 0;
for ( split '.', $start ) $start_dword *= 256; $start_dword += $_
my $end_dword = 0;
for ( split '.', $finish ) $end_dword *= 256; $end_dword += $_
print "Range:n";
print "t$start t=> $start_dwordn";
print "t$finish t=> $end_dwordn";
print "$ip_to_check is in $_n" if $dword >= $start_dword and $dword <= $end_dword;
__DATA__
"217.29.0.0-217.29.255.255",
"204.12.0.0-204.12.255.255",
"198.54.223.0-198.54.223.255",
Could quite easily do that as a 'check script' - by reading a file (rather than DATA
) and getting $ip_to_check
from STDIN
).
(note - as pure perl
could be turned into a one liner fairly easily, or a script to call. Or re-written - I daresay you could do this with expr
easily enough).
Though perl and not bash, this did work for my purposes. Thank you.
– wbruan
Oct 7 '15 at 5:08
Yes, I'm afraid I defected toperl
many years ago when I started to stretch the limits of what could be done inbash
. Fortunately, it's almost as ubiquitous, so you're not really inhibiting yourself much. (And in some cases - it's more common, for example if you're ever having to interact with AIX or another OS that doesn't dobash
by default)
– Sobrique
Oct 7 '15 at 9:09
add a comment |
The useful thing to remember with IP addresses is that they're actually just representations of a 32bit number.
So you can convert them to a decimal by multiplying the octets as base 256.
E.g.:
217.29.0.0 == 216 * 256 ^ 3 + 29 * 256 ^2 + 0 * 256 ^1 + 0 * 256 ^ 0
== 3640655872
So given a range like the above - first convert them both, such that you've got a start and end. Then compare any incoming IPs to see if they 'fit'.
So something like this (illustrating algorithm):
#!/usr/bin/env perl
use strict;
use warnings;
my $ip_to_check = "204.12.5.10";
my $dword = 0;
for ( split( '.', $ip_to_check ) ) $dword *= 256; $dword += $_
print "Checking $dwordn";
while (<DATA>)
my ( $start, $finish ) = m/([d.]+)/g;
my $start_dword = 0;
for ( split '.', $start ) $start_dword *= 256; $start_dword += $_
my $end_dword = 0;
for ( split '.', $finish ) $end_dword *= 256; $end_dword += $_
print "Range:n";
print "t$start t=> $start_dwordn";
print "t$finish t=> $end_dwordn";
print "$ip_to_check is in $_n" if $dword >= $start_dword and $dword <= $end_dword;
__DATA__
"217.29.0.0-217.29.255.255",
"204.12.0.0-204.12.255.255",
"198.54.223.0-198.54.223.255",
Could quite easily do that as a 'check script' - by reading a file (rather than DATA
) and getting $ip_to_check
from STDIN
).
(note - as pure perl
could be turned into a one liner fairly easily, or a script to call. Or re-written - I daresay you could do this with expr
easily enough).
Though perl and not bash, this did work for my purposes. Thank you.
– wbruan
Oct 7 '15 at 5:08
Yes, I'm afraid I defected toperl
many years ago when I started to stretch the limits of what could be done inbash
. Fortunately, it's almost as ubiquitous, so you're not really inhibiting yourself much. (And in some cases - it's more common, for example if you're ever having to interact with AIX or another OS that doesn't dobash
by default)
– Sobrique
Oct 7 '15 at 9:09
add a comment |
The useful thing to remember with IP addresses is that they're actually just representations of a 32bit number.
So you can convert them to a decimal by multiplying the octets as base 256.
E.g.:
217.29.0.0 == 216 * 256 ^ 3 + 29 * 256 ^2 + 0 * 256 ^1 + 0 * 256 ^ 0
== 3640655872
So given a range like the above - first convert them both, such that you've got a start and end. Then compare any incoming IPs to see if they 'fit'.
So something like this (illustrating algorithm):
#!/usr/bin/env perl
use strict;
use warnings;
my $ip_to_check = "204.12.5.10";
my $dword = 0;
for ( split( '.', $ip_to_check ) ) $dword *= 256; $dword += $_
print "Checking $dwordn";
while (<DATA>)
my ( $start, $finish ) = m/([d.]+)/g;
my $start_dword = 0;
for ( split '.', $start ) $start_dword *= 256; $start_dword += $_
my $end_dword = 0;
for ( split '.', $finish ) $end_dword *= 256; $end_dword += $_
print "Range:n";
print "t$start t=> $start_dwordn";
print "t$finish t=> $end_dwordn";
print "$ip_to_check is in $_n" if $dword >= $start_dword and $dword <= $end_dword;
__DATA__
"217.29.0.0-217.29.255.255",
"204.12.0.0-204.12.255.255",
"198.54.223.0-198.54.223.255",
Could quite easily do that as a 'check script' - by reading a file (rather than DATA
) and getting $ip_to_check
from STDIN
).
(note - as pure perl
could be turned into a one liner fairly easily, or a script to call. Or re-written - I daresay you could do this with expr
easily enough).
The useful thing to remember with IP addresses is that they're actually just representations of a 32bit number.
So you can convert them to a decimal by multiplying the octets as base 256.
E.g.:
217.29.0.0 == 216 * 256 ^ 3 + 29 * 256 ^2 + 0 * 256 ^1 + 0 * 256 ^ 0
== 3640655872
So given a range like the above - first convert them both, such that you've got a start and end. Then compare any incoming IPs to see if they 'fit'.
So something like this (illustrating algorithm):
#!/usr/bin/env perl
use strict;
use warnings;
my $ip_to_check = "204.12.5.10";
my $dword = 0;
for ( split( '.', $ip_to_check ) ) $dword *= 256; $dword += $_
print "Checking $dwordn";
while (<DATA>)
my ( $start, $finish ) = m/([d.]+)/g;
my $start_dword = 0;
for ( split '.', $start ) $start_dword *= 256; $start_dword += $_
my $end_dword = 0;
for ( split '.', $finish ) $end_dword *= 256; $end_dword += $_
print "Range:n";
print "t$start t=> $start_dwordn";
print "t$finish t=> $end_dwordn";
print "$ip_to_check is in $_n" if $dword >= $start_dword and $dword <= $end_dword;
__DATA__
"217.29.0.0-217.29.255.255",
"204.12.0.0-204.12.255.255",
"198.54.223.0-198.54.223.255",
Could quite easily do that as a 'check script' - by reading a file (rather than DATA
) and getting $ip_to_check
from STDIN
).
(note - as pure perl
could be turned into a one liner fairly easily, or a script to call. Or re-written - I daresay you could do this with expr
easily enough).
answered Oct 5 '15 at 12:31
SobriqueSobrique
3,839519
3,839519
Though perl and not bash, this did work for my purposes. Thank you.
– wbruan
Oct 7 '15 at 5:08
Yes, I'm afraid I defected toperl
many years ago when I started to stretch the limits of what could be done inbash
. Fortunately, it's almost as ubiquitous, so you're not really inhibiting yourself much. (And in some cases - it's more common, for example if you're ever having to interact with AIX or another OS that doesn't dobash
by default)
– Sobrique
Oct 7 '15 at 9:09
add a comment |
Though perl and not bash, this did work for my purposes. Thank you.
– wbruan
Oct 7 '15 at 5:08
Yes, I'm afraid I defected toperl
many years ago when I started to stretch the limits of what could be done inbash
. Fortunately, it's almost as ubiquitous, so you're not really inhibiting yourself much. (And in some cases - it's more common, for example if you're ever having to interact with AIX or another OS that doesn't dobash
by default)
– Sobrique
Oct 7 '15 at 9:09
Though perl and not bash, this did work for my purposes. Thank you.
– wbruan
Oct 7 '15 at 5:08
Though perl and not bash, this did work for my purposes. Thank you.
– wbruan
Oct 7 '15 at 5:08
Yes, I'm afraid I defected to
perl
many years ago when I started to stretch the limits of what could be done in bash
. Fortunately, it's almost as ubiquitous, so you're not really inhibiting yourself much. (And in some cases - it's more common, for example if you're ever having to interact with AIX or another OS that doesn't do bash
by default)– Sobrique
Oct 7 '15 at 9:09
Yes, I'm afraid I defected to
perl
many years ago when I started to stretch the limits of what could be done in bash
. Fortunately, it's almost as ubiquitous, so you're not really inhibiting yourself much. (And in some cases - it's more common, for example if you're ever having to interact with AIX or another OS that doesn't do bash
by default)– Sobrique
Oct 7 '15 at 9:09
add a comment |
Here's an awk version:
want=204.12.77.5
awk -v want=$want -F- '
function canon(ip)
split(" "ip,x,/[^0-9]+/)
return sprintf("%03d%03d%03d%03d",x[2],x[3],x[4],x[5])
BEGIN val = canon(want)
low = canon($1); high = canon($2);
if(val>=low && val<=high)print "in range " $0
' mylogfile
The function canon
takes an ip address, splits out the number fields,
then extends each to 3 digits and returns the string.
It is called for the 2 values on each line, and these are
compared with the wanted ip address (set at the start), which
has also been "canonified".
add a comment |
Here's an awk version:
want=204.12.77.5
awk -v want=$want -F- '
function canon(ip)
split(" "ip,x,/[^0-9]+/)
return sprintf("%03d%03d%03d%03d",x[2],x[3],x[4],x[5])
BEGIN val = canon(want)
low = canon($1); high = canon($2);
if(val>=low && val<=high)print "in range " $0
' mylogfile
The function canon
takes an ip address, splits out the number fields,
then extends each to 3 digits and returns the string.
It is called for the 2 values on each line, and these are
compared with the wanted ip address (set at the start), which
has also been "canonified".
add a comment |
Here's an awk version:
want=204.12.77.5
awk -v want=$want -F- '
function canon(ip)
split(" "ip,x,/[^0-9]+/)
return sprintf("%03d%03d%03d%03d",x[2],x[3],x[4],x[5])
BEGIN val = canon(want)
low = canon($1); high = canon($2);
if(val>=low && val<=high)print "in range " $0
' mylogfile
The function canon
takes an ip address, splits out the number fields,
then extends each to 3 digits and returns the string.
It is called for the 2 values on each line, and these are
compared with the wanted ip address (set at the start), which
has also been "canonified".
Here's an awk version:
want=204.12.77.5
awk -v want=$want -F- '
function canon(ip)
split(" "ip,x,/[^0-9]+/)
return sprintf("%03d%03d%03d%03d",x[2],x[3],x[4],x[5])
BEGIN val = canon(want)
low = canon($1); high = canon($2);
if(val>=low && val<=high)print "in range " $0
' mylogfile
The function canon
takes an ip address, splits out the number fields,
then extends each to 3 digits and returns the string.
It is called for the 2 values on each line, and these are
compared with the wanted ip address (set at the start), which
has also been "canonified".
answered Oct 5 '15 at 13:27
meuhmeuh
32.5k12255
32.5k12255
add a comment |
add a comment |
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-bash, ip, scripting
Does it have to be bash? And do you need to support different address formats?
– Sobrique
Oct 5 '15 at 12:17
It has to be bash, or something called from bash (such as the
ipcalc
utility). The only format I will need to do this for is the above-given [range-start]-[range-end] format, as that is the format this specific logfile uses.– wbruan
Oct 5 '15 at 12:19
Nopte that the aaa.bbb.ccc.ddd format is just custom, but you can trivially convert that to any other format. And if you convert it to decimal then you can simply check with the larger than and small than operators. (actually
=>
and=<
, since you probably want to include the edges).– Hennes
Oct 5 '15 at 12:28