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short way to perform efsck when we have huge number of disks


How can I avoid “Run fsck manually” messages while allowing experimenting with system time changes?Linux Mint: drives' map changing at reboot brings fstab errorError mounting drivesWhat's the difference between e2fsck and fsck and which one I should use?I can see my LVM but I can't initialize it. Missing UUID of one of the disksHow to map a sata device name to a physical sata interface for RAID systems/etc/fstab and parallel filesystem check (fsck)Script to create filesystemin which cases it will be problematic to configure UUID in fstabReboot with faulty drive, devices names change, server does not boot






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








1















we need to do e2fsck on all our disks ( redhat linux - 7.2 ). Since on each machines we have 22 disks ( ext4 file-system ) it will take time to do it on each disk as all know when doing e2fsck need to umount the mount point folder and then use the e2fsck on the disk. Example:



umount /grid/sdb
fsck /dev/sdb
mount /grid/sdb


But, I found option that can be much faster. We can use the fstab for this purpose and to change the sixth field from 0 to 1 and then reboot the machine



From my understanding during boot all disk will perform 2fsck automatically. Am I right here? /etc/fstab Example:



From



UUID=6f8debb3-aac9-4dfb-877f-463f5132d055 /grid/sdb ext4 defaults,noatime 0 0
UUID=203c24b2-8c07-4a9a-b4e0-1848ac5570d6 /grid/sdc ext4 defaults,noatime 0 0
UUID=941546ac-2168-4130-b51f-f5a255a4e43c /grid/sdd ext4 defaults,noatime 0 0


To



UUID=6f8debb3-aac9-4dfb-877f-463f5132d055 /grid/sdb ext4 defaults,noatime 1 0
UUID=203c24b2-8c07-4a9a-b4e0-1848ac5570d6 /grid/sdc ext4 defaults,noatime 1 0
UUID=941546ac-2168-4130-b51f-f5a255a4e43c /grid/sdd ext4 defaults,noatime 1 0


From the fstab(5) man page:



 The sixth field (fs_passno).
This field is used by the fsck(8) program to determine the order
in which filesystem checks are done at reboot time. The root
filesystem should be specified with a fs_passno of 1, and other
filesystems should have a fs_passno of 2. Filesystems within a
drive will be checked sequentially, but filesystems on different
drives will be checked at the same time to utilize parallelism
available in the hardware. If the sixth field is not present or
zero, a value of zero is returned and fsck will assume that the
filesystem does not need to be checked.









share|improve this question






























    1















    we need to do e2fsck on all our disks ( redhat linux - 7.2 ). Since on each machines we have 22 disks ( ext4 file-system ) it will take time to do it on each disk as all know when doing e2fsck need to umount the mount point folder and then use the e2fsck on the disk. Example:



    umount /grid/sdb
    fsck /dev/sdb
    mount /grid/sdb


    But, I found option that can be much faster. We can use the fstab for this purpose and to change the sixth field from 0 to 1 and then reboot the machine



    From my understanding during boot all disk will perform 2fsck automatically. Am I right here? /etc/fstab Example:



    From



    UUID=6f8debb3-aac9-4dfb-877f-463f5132d055 /grid/sdb ext4 defaults,noatime 0 0
    UUID=203c24b2-8c07-4a9a-b4e0-1848ac5570d6 /grid/sdc ext4 defaults,noatime 0 0
    UUID=941546ac-2168-4130-b51f-f5a255a4e43c /grid/sdd ext4 defaults,noatime 0 0


    To



    UUID=6f8debb3-aac9-4dfb-877f-463f5132d055 /grid/sdb ext4 defaults,noatime 1 0
    UUID=203c24b2-8c07-4a9a-b4e0-1848ac5570d6 /grid/sdc ext4 defaults,noatime 1 0
    UUID=941546ac-2168-4130-b51f-f5a255a4e43c /grid/sdd ext4 defaults,noatime 1 0


    From the fstab(5) man page:



     The sixth field (fs_passno).
    This field is used by the fsck(8) program to determine the order
    in which filesystem checks are done at reboot time. The root
    filesystem should be specified with a fs_passno of 1, and other
    filesystems should have a fs_passno of 2. Filesystems within a
    drive will be checked sequentially, but filesystems on different
    drives will be checked at the same time to utilize parallelism
    available in the hardware. If the sixth field is not present or
    zero, a value of zero is returned and fsck will assume that the
    filesystem does not need to be checked.









    share|improve this question


























      1












      1








      1








      we need to do e2fsck on all our disks ( redhat linux - 7.2 ). Since on each machines we have 22 disks ( ext4 file-system ) it will take time to do it on each disk as all know when doing e2fsck need to umount the mount point folder and then use the e2fsck on the disk. Example:



      umount /grid/sdb
      fsck /dev/sdb
      mount /grid/sdb


      But, I found option that can be much faster. We can use the fstab for this purpose and to change the sixth field from 0 to 1 and then reboot the machine



      From my understanding during boot all disk will perform 2fsck automatically. Am I right here? /etc/fstab Example:



      From



      UUID=6f8debb3-aac9-4dfb-877f-463f5132d055 /grid/sdb ext4 defaults,noatime 0 0
      UUID=203c24b2-8c07-4a9a-b4e0-1848ac5570d6 /grid/sdc ext4 defaults,noatime 0 0
      UUID=941546ac-2168-4130-b51f-f5a255a4e43c /grid/sdd ext4 defaults,noatime 0 0


      To



      UUID=6f8debb3-aac9-4dfb-877f-463f5132d055 /grid/sdb ext4 defaults,noatime 1 0
      UUID=203c24b2-8c07-4a9a-b4e0-1848ac5570d6 /grid/sdc ext4 defaults,noatime 1 0
      UUID=941546ac-2168-4130-b51f-f5a255a4e43c /grid/sdd ext4 defaults,noatime 1 0


      From the fstab(5) man page:



       The sixth field (fs_passno).
      This field is used by the fsck(8) program to determine the order
      in which filesystem checks are done at reboot time. The root
      filesystem should be specified with a fs_passno of 1, and other
      filesystems should have a fs_passno of 2. Filesystems within a
      drive will be checked sequentially, but filesystems on different
      drives will be checked at the same time to utilize parallelism
      available in the hardware. If the sixth field is not present or
      zero, a value of zero is returned and fsck will assume that the
      filesystem does not need to be checked.









      share|improve this question
















      we need to do e2fsck on all our disks ( redhat linux - 7.2 ). Since on each machines we have 22 disks ( ext4 file-system ) it will take time to do it on each disk as all know when doing e2fsck need to umount the mount point folder and then use the e2fsck on the disk. Example:



      umount /grid/sdb
      fsck /dev/sdb
      mount /grid/sdb


      But, I found option that can be much faster. We can use the fstab for this purpose and to change the sixth field from 0 to 1 and then reboot the machine



      From my understanding during boot all disk will perform 2fsck automatically. Am I right here? /etc/fstab Example:



      From



      UUID=6f8debb3-aac9-4dfb-877f-463f5132d055 /grid/sdb ext4 defaults,noatime 0 0
      UUID=203c24b2-8c07-4a9a-b4e0-1848ac5570d6 /grid/sdc ext4 defaults,noatime 0 0
      UUID=941546ac-2168-4130-b51f-f5a255a4e43c /grid/sdd ext4 defaults,noatime 0 0


      To



      UUID=6f8debb3-aac9-4dfb-877f-463f5132d055 /grid/sdb ext4 defaults,noatime 1 0
      UUID=203c24b2-8c07-4a9a-b4e0-1848ac5570d6 /grid/sdc ext4 defaults,noatime 1 0
      UUID=941546ac-2168-4130-b51f-f5a255a4e43c /grid/sdd ext4 defaults,noatime 1 0


      From the fstab(5) man page:



       The sixth field (fs_passno).
      This field is used by the fsck(8) program to determine the order
      in which filesystem checks are done at reboot time. The root
      filesystem should be specified with a fs_passno of 1, and other
      filesystems should have a fs_passno of 2. Filesystems within a
      drive will be checked sequentially, but filesystems on different
      drives will be checked at the same time to utilize parallelism
      available in the hardware. If the sixth field is not present or
      zero, a value of zero is returned and fsck will assume that the
      filesystem does not need to be checked.






      linux filesystems rhel fstab fsck






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Mar 27 at 17:55









      nwildner

      15k34581




      15k34581










      asked Mar 27 at 17:06









      yaelyael

      2,81242979




      2,81242979




















          1 Answer
          1






          active

          oldest

          votes


















          3














          That’s nearly right; you should use a pass number of 2 (since these aren’t the root file system), and it really has to be the sixth field, so



          UUID=6f8debb3-aac9-4dfb-877f-463f5132d055 /grid/sdb ext4 defaults,noatime 0 2
          UUID=203c24b2-8c07-4a9a-b4e0-1848ac5570d6 /grid/sdc ext4 defaults,noatime 0 2
          UUID=941546ac-2168-4130-b51f-f5a255a4e43c /grid/sdd ext4 defaults,noatime 0 2

          |<-------------- field 1 -------------->| |<- 2 ->| |<>| |<- field 4 -->| ^ ^
          ^ | |
          field 3 -+ field 5 -+ |
          field 6 -+





          share|improve this answer

























          • I guess the machine it take time until boot is completed ?

            – yael
            Mar 27 at 17:28











          • Yes, checking the disks might lengthen the boot, but in most cases it won’t — if the file system is clean, fsck will only force a check at fairly lengthy intervals by default. Checks are parallelised across disks too, which will help in your case.

            – Stephen Kitt
            Mar 27 at 17:30











          Your Answer








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          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          3














          That’s nearly right; you should use a pass number of 2 (since these aren’t the root file system), and it really has to be the sixth field, so



          UUID=6f8debb3-aac9-4dfb-877f-463f5132d055 /grid/sdb ext4 defaults,noatime 0 2
          UUID=203c24b2-8c07-4a9a-b4e0-1848ac5570d6 /grid/sdc ext4 defaults,noatime 0 2
          UUID=941546ac-2168-4130-b51f-f5a255a4e43c /grid/sdd ext4 defaults,noatime 0 2

          |<-------------- field 1 -------------->| |<- 2 ->| |<>| |<- field 4 -->| ^ ^
          ^ | |
          field 3 -+ field 5 -+ |
          field 6 -+





          share|improve this answer

























          • I guess the machine it take time until boot is completed ?

            – yael
            Mar 27 at 17:28











          • Yes, checking the disks might lengthen the boot, but in most cases it won’t — if the file system is clean, fsck will only force a check at fairly lengthy intervals by default. Checks are parallelised across disks too, which will help in your case.

            – Stephen Kitt
            Mar 27 at 17:30















          3














          That’s nearly right; you should use a pass number of 2 (since these aren’t the root file system), and it really has to be the sixth field, so



          UUID=6f8debb3-aac9-4dfb-877f-463f5132d055 /grid/sdb ext4 defaults,noatime 0 2
          UUID=203c24b2-8c07-4a9a-b4e0-1848ac5570d6 /grid/sdc ext4 defaults,noatime 0 2
          UUID=941546ac-2168-4130-b51f-f5a255a4e43c /grid/sdd ext4 defaults,noatime 0 2

          |<-------------- field 1 -------------->| |<- 2 ->| |<>| |<- field 4 -->| ^ ^
          ^ | |
          field 3 -+ field 5 -+ |
          field 6 -+





          share|improve this answer

























          • I guess the machine it take time until boot is completed ?

            – yael
            Mar 27 at 17:28











          • Yes, checking the disks might lengthen the boot, but in most cases it won’t — if the file system is clean, fsck will only force a check at fairly lengthy intervals by default. Checks are parallelised across disks too, which will help in your case.

            – Stephen Kitt
            Mar 27 at 17:30













          3












          3








          3







          That’s nearly right; you should use a pass number of 2 (since these aren’t the root file system), and it really has to be the sixth field, so



          UUID=6f8debb3-aac9-4dfb-877f-463f5132d055 /grid/sdb ext4 defaults,noatime 0 2
          UUID=203c24b2-8c07-4a9a-b4e0-1848ac5570d6 /grid/sdc ext4 defaults,noatime 0 2
          UUID=941546ac-2168-4130-b51f-f5a255a4e43c /grid/sdd ext4 defaults,noatime 0 2

          |<-------------- field 1 -------------->| |<- 2 ->| |<>| |<- field 4 -->| ^ ^
          ^ | |
          field 3 -+ field 5 -+ |
          field 6 -+





          share|improve this answer















          That’s nearly right; you should use a pass number of 2 (since these aren’t the root file system), and it really has to be the sixth field, so



          UUID=6f8debb3-aac9-4dfb-877f-463f5132d055 /grid/sdb ext4 defaults,noatime 0 2
          UUID=203c24b2-8c07-4a9a-b4e0-1848ac5570d6 /grid/sdc ext4 defaults,noatime 0 2
          UUID=941546ac-2168-4130-b51f-f5a255a4e43c /grid/sdd ext4 defaults,noatime 0 2

          |<-------------- field 1 -------------->| |<- 2 ->| |<>| |<- field 4 -->| ^ ^
          ^ | |
          field 3 -+ field 5 -+ |
          field 6 -+






          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Mar 27 at 17:23

























          answered Mar 27 at 17:13









          Stephen KittStephen Kitt

          180k25409488




          180k25409488












          • I guess the machine it take time until boot is completed ?

            – yael
            Mar 27 at 17:28











          • Yes, checking the disks might lengthen the boot, but in most cases it won’t — if the file system is clean, fsck will only force a check at fairly lengthy intervals by default. Checks are parallelised across disks too, which will help in your case.

            – Stephen Kitt
            Mar 27 at 17:30

















          • I guess the machine it take time until boot is completed ?

            – yael
            Mar 27 at 17:28











          • Yes, checking the disks might lengthen the boot, but in most cases it won’t — if the file system is clean, fsck will only force a check at fairly lengthy intervals by default. Checks are parallelised across disks too, which will help in your case.

            – Stephen Kitt
            Mar 27 at 17:30
















          I guess the machine it take time until boot is completed ?

          – yael
          Mar 27 at 17:28





          I guess the machine it take time until boot is completed ?

          – yael
          Mar 27 at 17:28













          Yes, checking the disks might lengthen the boot, but in most cases it won’t — if the file system is clean, fsck will only force a check at fairly lengthy intervals by default. Checks are parallelised across disks too, which will help in your case.

          – Stephen Kitt
          Mar 27 at 17:30





          Yes, checking the disks might lengthen the boot, but in most cases it won’t — if the file system is clean, fsck will only force a check at fairly lengthy intervals by default. Checks are parallelised across disks too, which will help in your case.

          – Stephen Kitt
          Mar 27 at 17:30

















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