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How to make nested for loops with dynamically named `i` in bash


Nested loops, if conditions, and background jobs in bashHow to make Bash loopsExiting a shell script with nested loopsTrying to get the specific information from the arrayLoops: for vs while… beyond the basics. Subtle differences/pros/cons for my code?Populate array with a sed/echo combinationBash Nested loopsBASH attempting to leave nested statements/loops/functionsMySQL Bash for loopsHow to set empty array elements set to zero?






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1















So the following works to wrap the for loop and print out something for each item:



iterate() 
local array=$1

shift

for i in $array; do
$*
done


iteratecallback()
echo item: $i


data=$(ls)
iterate "$data" iteratecallback


But what I would like to do is take the echo item: $i and make i into echo item: $position for top level, then index for next level nesting, then i for third level nesting, for example. Basically, be able to arbitrarily name these index variables while passing them into the wrapping function.



So for example, something like this:



iterate() 
local customname=$1
local array=$2

shift

for $customname in $array; do
$*
done


iteratecallback()
echo item: $position

data2=$(ls)
iterate index "$data2" iteratecallback2


iteratecallback2()
echo item: $index in $position


data=$(ls)
iterate position "$data" iteratecallback


Wondering how to do such a thing in Bash.










share|improve this question

















  • 2





    Note that you're not passing an array, you are passing a string that contains newlines. The for loop iterates over the words in that string, so if you have a filename that contains a space, you're not doing what you think you are.

    – glenn jackman
    Mar 27 at 16:23






  • 1





    You'll want to investigate "nameref" in the bash manual to truly reference a variable in the calling scope.

    – glenn jackman
    Mar 27 at 16:24

















1















So the following works to wrap the for loop and print out something for each item:



iterate() 
local array=$1

shift

for i in $array; do
$*
done


iteratecallback()
echo item: $i


data=$(ls)
iterate "$data" iteratecallback


But what I would like to do is take the echo item: $i and make i into echo item: $position for top level, then index for next level nesting, then i for third level nesting, for example. Basically, be able to arbitrarily name these index variables while passing them into the wrapping function.



So for example, something like this:



iterate() 
local customname=$1
local array=$2

shift

for $customname in $array; do
$*
done


iteratecallback()
echo item: $position

data2=$(ls)
iterate index "$data2" iteratecallback2


iteratecallback2()
echo item: $index in $position


data=$(ls)
iterate position "$data" iteratecallback


Wondering how to do such a thing in Bash.










share|improve this question

















  • 2





    Note that you're not passing an array, you are passing a string that contains newlines. The for loop iterates over the words in that string, so if you have a filename that contains a space, you're not doing what you think you are.

    – glenn jackman
    Mar 27 at 16:23






  • 1





    You'll want to investigate "nameref" in the bash manual to truly reference a variable in the calling scope.

    – glenn jackman
    Mar 27 at 16:24













1












1








1








So the following works to wrap the for loop and print out something for each item:



iterate() 
local array=$1

shift

for i in $array; do
$*
done


iteratecallback()
echo item: $i


data=$(ls)
iterate "$data" iteratecallback


But what I would like to do is take the echo item: $i and make i into echo item: $position for top level, then index for next level nesting, then i for third level nesting, for example. Basically, be able to arbitrarily name these index variables while passing them into the wrapping function.



So for example, something like this:



iterate() 
local customname=$1
local array=$2

shift

for $customname in $array; do
$*
done


iteratecallback()
echo item: $position

data2=$(ls)
iterate index "$data2" iteratecallback2


iteratecallback2()
echo item: $index in $position


data=$(ls)
iterate position "$data" iteratecallback


Wondering how to do such a thing in Bash.










share|improve this question














So the following works to wrap the for loop and print out something for each item:



iterate() 
local array=$1

shift

for i in $array; do
$*
done


iteratecallback()
echo item: $i


data=$(ls)
iterate "$data" iteratecallback


But what I would like to do is take the echo item: $i and make i into echo item: $position for top level, then index for next level nesting, then i for third level nesting, for example. Basically, be able to arbitrarily name these index variables while passing them into the wrapping function.



So for example, something like this:



iterate() 
local customname=$1
local array=$2

shift

for $customname in $array; do
$*
done


iteratecallback()
echo item: $position

data2=$(ls)
iterate index "$data2" iteratecallback2


iteratecallback2()
echo item: $index in $position


data=$(ls)
iterate position "$data" iteratecallback


Wondering how to do such a thing in Bash.







bash






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Mar 27 at 16:02









Lance PollardLance Pollard

1717




1717







  • 2





    Note that you're not passing an array, you are passing a string that contains newlines. The for loop iterates over the words in that string, so if you have a filename that contains a space, you're not doing what you think you are.

    – glenn jackman
    Mar 27 at 16:23






  • 1





    You'll want to investigate "nameref" in the bash manual to truly reference a variable in the calling scope.

    – glenn jackman
    Mar 27 at 16:24












  • 2





    Note that you're not passing an array, you are passing a string that contains newlines. The for loop iterates over the words in that string, so if you have a filename that contains a space, you're not doing what you think you are.

    – glenn jackman
    Mar 27 at 16:23






  • 1





    You'll want to investigate "nameref" in the bash manual to truly reference a variable in the calling scope.

    – glenn jackman
    Mar 27 at 16:24







2




2





Note that you're not passing an array, you are passing a string that contains newlines. The for loop iterates over the words in that string, so if you have a filename that contains a space, you're not doing what you think you are.

– glenn jackman
Mar 27 at 16:23





Note that you're not passing an array, you are passing a string that contains newlines. The for loop iterates over the words in that string, so if you have a filename that contains a space, you're not doing what you think you are.

– glenn jackman
Mar 27 at 16:23




1




1





You'll want to investigate "nameref" in the bash manual to truly reference a variable in the calling scope.

– glenn jackman
Mar 27 at 16:24





You'll want to investigate "nameref" in the bash manual to truly reference a variable in the calling scope.

– glenn jackman
Mar 27 at 16:24










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