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0

0

I'm on a mac, bash version 5.0.2.

Got this:

 v="ksdjfksjkjsdf"
 v2=$v::-6

Get this:

-bash: -6: substring expression < 0

bash

share|improve this question

asked Mar 27 at 14:27

StevieDStevieD

1659

closed as off-topic by Jesse_b, ilkkachu, terdon♦ Mar 27 at 19:51

This question appears to be off-topic. The users who voted to close gave this specific reason:

• "Questions describing a problem that can't be reproduced and seemingly went away on its own (or went away when a typo was fixed) are off-topic as they are unlikely to help future readers." – ilkkachu, terdon

If this question can be reworded to fit the rules in the help center, please edit the question.

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Which version of bash? I just tried this with 4.4.12 and it worked as expected.
  
  – Panki
  Mar 27 at 14:30
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  at the top of the post: 5.0.2
  
  – StevieD
  Mar 27 at 14:31
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Are you sure you are providing us with the exact variables you are working with? It seems the way you get this error is trying to trim more characters from a string than exist. Your example should never fail but if you tried v2=$v::-14 it would
  
  – Jesse_b
  Mar 27 at 14:42
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Positive. Yes. That's all I have in my test script besides shebang.
  
  – StevieD
  Mar 27 at 14:49
  

  
  
  
  

add a comment | 

0

0

I'm on a mac, bash version 5.0.2.

Got this:

 v="ksdjfksjkjsdf"
 v2=$v::-6

Get this:

-bash: -6: substring expression < 0

bash

share|improve this question

asked Mar 27 at 14:27

StevieDStevieD

1659

closed as off-topic by Jesse_b, ilkkachu, terdon♦ Mar 27 at 19:51

This question appears to be off-topic. The users who voted to close gave this specific reason:

• "Questions describing a problem that can't be reproduced and seemingly went away on its own (or went away when a typo was fixed) are off-topic as they are unlikely to help future readers." – ilkkachu, terdon

If this question can be reworded to fit the rules in the help center, please edit the question.

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Which version of bash? I just tried this with 4.4.12 and it worked as expected.
  
  – Panki
  Mar 27 at 14:30
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  at the top of the post: 5.0.2
  
  – StevieD
  Mar 27 at 14:31
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Are you sure you are providing us with the exact variables you are working with? It seems the way you get this error is trying to trim more characters from a string than exist. Your example should never fail but if you tried v2=$v::-14 it would
  
  – Jesse_b
  Mar 27 at 14:42
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Positive. Yes. That's all I have in my test script besides shebang.
  
  – StevieD
  Mar 27 at 14:49
  

  
  
  
  

add a comment | 

I'm on a mac, bash version 5.0.2.

Got this:

 v="ksdjfksjkjsdf"
 v2=$v::-6

Get this:

-bash: -6: substring expression < 0

bash

share|improve this question

asked Mar 27 at 14:27

StevieDStevieD

1659

 v="ksdjfksjkjsdf"
 v2=$v::-6

-bash: -6: substring expression < 0

share|improve this question

asked Mar 27 at 14:27

StevieDStevieD

1659

share|improve this question

asked Mar 27 at 14:27

StevieDStevieD

1659

asked Mar 27 at 14:27

StevieDStevieD

1659

asked Mar 27 at 14:27

StevieDStevieD

1659

4 Answers
4

active

oldest

votes

1

Are you sure you are running the script with the correct bash version? Is your shebang line ok? How about calling the script with bash myscript.sh?

share|improve this answer

answered Mar 27 at 14:38

Joni LJoni L

361

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Turns out my bash --version returns different value than /bin/bash --version. OP was running with #!/bin/bash version.
  
  – StevieD
  Mar 27 at 14:59
  

  
  
  
  

add a comment | 

3

Using negative lengths was added in Bash 4.2:

$PARAMETER:OFFSET:LENGTH: Negative LENGTH values are used as offset from the end of the string 4.2-alpha

And it seems to work for me with Bash versions 4.2.53, 4.4.12 and 5.0.3. With any of those, I get:

$ s=123456; echo "$s::-2"
1234
$ s=123456; echo "$s::-8"
bash: -8: substring expression < 0

That is, it works as long as the absolute value of the negative length isn't greater than the length of the string.

share|improve this answer

answered Mar 27 at 15:04

ilkkachuilkkachu

63.2k10104181

add a comment | 

-1

This worked:

v="aksdjfkajsdkfjakdf"
length=$#v
v2=$v:0: length - 6

share|improve this answer

answered Mar 27 at 14:47

StevieDStevieD

1659

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  This will not work if the length of v is less than 6 characters, which is likely your issue in the first place.
  
  – Jesse_b
  Mar 27 at 14:49
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I know it's more than 6 characters in the code it will be used in.
  
  – StevieD
  Mar 27 at 14:50
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Why are you downvoting the correct answer? I just ran it. In this example I have a string way more than 6 characters.
  
  – StevieD
  Mar 27 at 14:51
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  You should file a bug report with bash
  
  – Jesse_b
  Mar 27 at 14:52
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I have no idea if it's a bug or not. Could work differently in bash 5.
  
  – StevieD
  Mar 27 at 14:52
  

  
  
  
  

 | 
show 4 more comments

-1

I have done by below method

v="ksdjfksjkjsdf"
echo $v| awk -F "" 'gsub("","n",$0);print $0'| sed '/^$/d'| sed -n '1,7p'| perl -pne g"/n//g"

output

 echo $v| awk -F "" 'gsub("","n",$0);print $0'| sed '/^$/d'| sed -n '1,7p'| perl -pne g"/n//g"

ksdjfks

share|improve this answer

answered Mar 27 at 18:02

Praveen Kumar BSPraveen Kumar BS

1,7391311

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Are you sure that works? I get each character on a separate line. In any case, you can do all this in a single AWK invocation, or sed, or Perl, there’s no need to run multiple programs. (As a general rule of thumb, if you’re using Perl, you don’t need AWK; if you’re using AWK, you don’t need sed.)
  
  – Stephen Kitt
  Mar 28 at 8:23
  

  
  
  
  

add a comment | 

1

Are you sure you are running the script with the correct bash version? Is your shebang line ok? How about calling the script with bash myscript.sh?

share|improve this answer

answered Mar 27 at 14:38

Joni LJoni L

361

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Turns out my bash --version returns different value than /bin/bash --version. OP was running with #!/bin/bash version.
  
  – StevieD
  Mar 27 at 14:59
  

  
  
  
  

add a comment | 

1

Are you sure you are running the script with the correct bash version? Is your shebang line ok? How about calling the script with bash myscript.sh?

share|improve this answer

answered Mar 27 at 14:38

Joni LJoni L

361

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Turns out my bash --version returns different value than /bin/bash --version. OP was running with #!/bin/bash version.
  
  – StevieD
  Mar 27 at 14:59
  

  
  
  
  

add a comment | 

Are you sure you are running the script with the correct bash version? Is your shebang line ok? How about calling the script with bash myscript.sh?

share|improve this answer

answered Mar 27 at 14:38

Joni LJoni L

361

share|improve this answer

answered Mar 27 at 14:38

Joni LJoni L

361

answered Mar 27 at 14:38

Joni LJoni L

361

answered Mar 27 at 14:38

Joni LJoni L

361

3

Using negative lengths was added in Bash 4.2:

$PARAMETER:OFFSET:LENGTH: Negative LENGTH values are used as offset from the end of the string 4.2-alpha

And it seems to work for me with Bash versions 4.2.53, 4.4.12 and 5.0.3. With any of those, I get:

$ s=123456; echo "$s::-2"
1234
$ s=123456; echo "$s::-8"
bash: -8: substring expression < 0

That is, it works as long as the absolute value of the negative length isn't greater than the length of the string.

share|improve this answer

answered Mar 27 at 15:04

ilkkachuilkkachu

63.2k10104181

add a comment | 

3

Using negative lengths was added in Bash 4.2:

$PARAMETER:OFFSET:LENGTH: Negative LENGTH values are used as offset from the end of the string 4.2-alpha

And it seems to work for me with Bash versions 4.2.53, 4.4.12 and 5.0.3. With any of those, I get:

$ s=123456; echo "$s::-2"
1234
$ s=123456; echo "$s::-8"
bash: -8: substring expression < 0

That is, it works as long as the absolute value of the negative length isn't greater than the length of the string.

share|improve this answer

answered Mar 27 at 15:04

ilkkachuilkkachu

63.2k10104181

add a comment | 

Using negative lengths was added in Bash 4.2:

$PARAMETER:OFFSET:LENGTH: Negative LENGTH values are used as offset from the end of the string 4.2-alpha

And it seems to work for me with Bash versions 4.2.53, 4.4.12 and 5.0.3. With any of those, I get:

$ s=123456; echo "$s::-2"
1234
$ s=123456; echo "$s::-8"
bash: -8: substring expression < 0

That is, it works as long as the absolute value of the negative length isn't greater than the length of the string.

share|improve this answer

answered Mar 27 at 15:04

ilkkachuilkkachu

63.2k10104181

$ s=123456; echo "$s::-2"
1234
$ s=123456; echo "$s::-8"
bash: -8: substring expression < 0

share|improve this answer

answered Mar 27 at 15:04

ilkkachuilkkachu

63.2k10104181

answered Mar 27 at 15:04

ilkkachuilkkachu

63.2k10104181

answered Mar 27 at 15:04

ilkkachuilkkachu

63.2k10104181

-1

This worked:

v="aksdjfkajsdkfjakdf"
length=$#v
v2=$v:0: length - 6

share|improve this answer

answered Mar 27 at 14:47

StevieDStevieD

1659

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  This will not work if the length of v is less than 6 characters, which is likely your issue in the first place.
  
  – Jesse_b
  Mar 27 at 14:49
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I know it's more than 6 characters in the code it will be used in.
  
  – StevieD
  Mar 27 at 14:50
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Why are you downvoting the correct answer? I just ran it. In this example I have a string way more than 6 characters.
  
  – StevieD
  Mar 27 at 14:51
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  You should file a bug report with bash
  
  – Jesse_b
  Mar 27 at 14:52
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I have no idea if it's a bug or not. Could work differently in bash 5.
  
  – StevieD
  Mar 27 at 14:52
  

  
  
  
  

 | 
show 4 more comments

-1

This worked:

v="aksdjfkajsdkfjakdf"
length=$#v
v2=$v:0: length - 6

share|improve this answer

answered Mar 27 at 14:47

StevieDStevieD

1659

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  This will not work if the length of v is less than 6 characters, which is likely your issue in the first place.
  
  – Jesse_b
  Mar 27 at 14:49
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I know it's more than 6 characters in the code it will be used in.
  
  – StevieD
  Mar 27 at 14:50
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Why are you downvoting the correct answer? I just ran it. In this example I have a string way more than 6 characters.
  
  – StevieD
  Mar 27 at 14:51
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  You should file a bug report with bash
  
  – Jesse_b
  Mar 27 at 14:52
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I have no idea if it's a bug or not. Could work differently in bash 5.
  
  – StevieD
  Mar 27 at 14:52
  

  
  
  
  

 | 
show 4 more comments

This worked:

v="aksdjfkajsdkfjakdf"
length=$#v
v2=$v:0: length - 6

share|improve this answer

answered Mar 27 at 14:47

StevieDStevieD

1659

v="aksdjfkajsdkfjakdf"
length=$#v
v2=$v:0: length - 6

share|improve this answer

answered Mar 27 at 14:47

StevieDStevieD

1659

answered Mar 27 at 14:47

StevieDStevieD

1659

answered Mar 27 at 14:47

StevieDStevieD

1659

-1

I have done by below method

v="ksdjfksjkjsdf"
echo $v| awk -F "" 'gsub("","n",$0);print $0'| sed '/^$/d'| sed -n '1,7p'| perl -pne g"/n//g"

output

 echo $v| awk -F "" 'gsub("","n",$0);print $0'| sed '/^$/d'| sed -n '1,7p'| perl -pne g"/n//g"

ksdjfks

share|improve this answer

answered Mar 27 at 18:02

Praveen Kumar BSPraveen Kumar BS

1,7391311

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Are you sure that works? I get each character on a separate line. In any case, you can do all this in a single AWK invocation, or sed, or Perl, there’s no need to run multiple programs. (As a general rule of thumb, if you’re using Perl, you don’t need AWK; if you’re using AWK, you don’t need sed.)
  
  – Stephen Kitt
  Mar 28 at 8:23
  

  
  
  
  

add a comment | 

-1

I have done by below method

v="ksdjfksjkjsdf"
echo $v| awk -F "" 'gsub("","n",$0);print $0'| sed '/^$/d'| sed -n '1,7p'| perl -pne g"/n//g"

output

 echo $v| awk -F "" 'gsub("","n",$0);print $0'| sed '/^$/d'| sed -n '1,7p'| perl -pne g"/n//g"

ksdjfks

share|improve this answer

answered Mar 27 at 18:02

Praveen Kumar BSPraveen Kumar BS

1,7391311

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Are you sure that works? I get each character on a separate line. In any case, you can do all this in a single AWK invocation, or sed, or Perl, there’s no need to run multiple programs. (As a general rule of thumb, if you’re using Perl, you don’t need AWK; if you’re using AWK, you don’t need sed.)
  
  – Stephen Kitt
  Mar 28 at 8:23
  

  
  
  
  

add a comment | 

I have done by below method

v="ksdjfksjkjsdf"
echo $v| awk -F "" 'gsub("","n",$0);print $0'| sed '/^$/d'| sed -n '1,7p'| perl -pne g"/n//g"

output

 echo $v| awk -F "" 'gsub("","n",$0);print $0'| sed '/^$/d'| sed -n '1,7p'| perl -pne g"/n//g"

ksdjfks

share|improve this answer

answered Mar 27 at 18:02

Praveen Kumar BSPraveen Kumar BS

1,7391311

v="ksdjfksjkjsdf"
echo $v| awk -F "" 'gsub("","n",$0);print $0'| sed '/^$/d'| sed -n '1,7p'| perl -pne g"/n//g"

 echo $v| awk -F "" 'gsub("","n",$0);print $0'| sed '/^$/d'| sed -n '1,7p'| perl -pne g"/n//g"

ksdjfks

share|improve this answer

answered Mar 27 at 18:02

Praveen Kumar BSPraveen Kumar BS

1,7391311

answered Mar 27 at 18:02

Praveen Kumar BSPraveen Kumar BS

1,7391311

answered Mar 27 at 18:02

Praveen Kumar BSPraveen Kumar BS

1,7391311