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Replace group of similar text in string from nth position with one string else increment the value by +1
The 2019 Stack Overflow Developer Survey Results Are Inintroduce line break at the same position based on another fileextract certain string, search and replace or keep a longer string contain the extracted valueHow can I delete everything between two markers in a file?UNIX command for replacing within delimiter based on position of the delimiterHow to extract XML data from logs using Unix shell script?Extract part of the logs to other filelog processing/entry deletion, multi-pipe (grep sed grep), log traversed twice. can this solution be improved?sed or awk for formattingText file: find string, save string field to var, find 2nd string, replace field with var, repeat to endReplace text in lines in a file with increments
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;
I have a text file with following lines for example.
Input
DD0TRANSID000019021210504250003379433005533665506656000008587201902070168304000.0AK 0000L00000.00 N 01683016832019021220190212N0000.001683065570067.000000.00000.0000000000000NAcknowledgment
DD0TRANSID000019021210504250003379433005535567606656000008587201902085381804000.0FC 0000L00000.00 N 53818538182019021220190212N0000.053818065570067.000000.00000.0000000000000NFirst Contact
DD0TRANSID000019021210510360003379433005535568006656000008587201902085381804000.0SR 0000L00000.00 N 53818538182019021220190212N0000.0
CC0TRANSID000019021210510360003379433005535568006656000008587201902085381804000.0SR 0000L00000.00 N 53818538182019021220190212N0000.0
My requirement is
If the line begins with "D" then replace string starting from 14th position to 27th Position with D00000X (X being a number with left padding)
If I come across the same value of string between 14th and 27th Position, that I encountered before in the file, I should replace with D00000X, else with D00000X+1
Output
DD0TRANSID00001902121D000006003379433005533665506656000008587201902070168304000.0AK 0000L00000.00 N 01683016832019021220190212N0000.001683065570067.000000.00000.0000000000000NAcknowledgment
DD0TRANSID00001902121D000006003379433005535567606656000008587201902085381804000.0FC 0000L00000.00 N 53818538182019021220190212N0000.053818065570067.000000.00000.0000000000000NFirst Contact
DD0TRANSID00001902121D000007003379433005535568006656000008587201902085381804000.0SR 0000L00000.00 N 53818538182019021220190212N0000.0
CC0TRANSID000019021210510360003379433005535568006656000008587201902085381804000.0SR 0000L00000.00 N 53818538182019021220190212N0000.0
awk sed perl
asked 2 days ago
Rohit PrasadRohit Prasad
11
New contributor
Rohit Prasad is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
I have a text file with following lines for example.
Input
DD0TRANSID000019021210504250003379433005533665506656000008587201902070168304000.0AK 0000L00000.00 N 01683016832019021220190212N0000.001683065570067.000000.00000.0000000000000NAcknowledgment
DD0TRANSID000019021210504250003379433005535567606656000008587201902085381804000.0FC 0000L00000.00 N 53818538182019021220190212N0000.053818065570067.000000.00000.0000000000000NFirst Contact
DD0TRANSID000019021210510360003379433005535568006656000008587201902085381804000.0SR 0000L00000.00 N 53818538182019021220190212N0000.0
CC0TRANSID000019021210510360003379433005535568006656000008587201902085381804000.0SR 0000L00000.00 N 53818538182019021220190212N0000.0
My requirement is
If the line begins with "D" then replace string starting from 14th position to 27th Position with D00000X (X being a number with left padding)
If I come across the same value of string between 14th and 27th Position, that I encountered before in the file, I should replace with D00000X, else with D00000X+1
Output
DD0TRANSID00001902121D000006003379433005533665506656000008587201902070168304000.0AK 0000L00000.00 N 01683016832019021220190212N0000.001683065570067.000000.00000.0000000000000NAcknowledgment
DD0TRANSID00001902121D000006003379433005535567606656000008587201902085381804000.0FC 0000L00000.00 N 53818538182019021220190212N0000.053818065570067.000000.00000.0000000000000NFirst Contact
DD0TRANSID00001902121D000007003379433005535568006656000008587201902085381804000.0SR 0000L00000.00 N 53818538182019021220190212N0000.0
CC0TRANSID000019021210510360003379433005535568006656000008587201902085381804000.0SR 0000L00000.00 N 53818538182019021220190212N0000.0
awk sed perl
asked 2 days ago
Rohit PrasadRohit Prasad
11
New contributor
Rohit Prasad is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
1
Are you sure the replacement happens at position 14? The output doesn't seem right - I see the change at position 21 (or 22 if 1-based).
– choroba
2 days ago
Is'nt it the same question
– ctac_
2 days ago
No, it isnt the same question. I need to repeat the replaced string, every time I encounter a duplicate string(string between 14-21 position) else keep incrementing.
– Rohit Prasad
2 days ago
add a comment |
I have a text file with following lines for example.
Input
DD0TRANSID000019021210504250003379433005533665506656000008587201902070168304000.0AK 0000L00000.00 N 01683016832019021220190212N0000.001683065570067.000000.00000.0000000000000NAcknowledgment
DD0TRANSID000019021210504250003379433005535567606656000008587201902085381804000.0FC 0000L00000.00 N 53818538182019021220190212N0000.053818065570067.000000.00000.0000000000000NFirst Contact
DD0TRANSID000019021210510360003379433005535568006656000008587201902085381804000.0SR 0000L00000.00 N 53818538182019021220190212N0000.0
CC0TRANSID000019021210510360003379433005535568006656000008587201902085381804000.0SR 0000L00000.00 N 53818538182019021220190212N0000.0
My requirement is
If the line begins with "D" then replace string starting from 14th position to 27th Position with D00000X (X being a number with left padding)
If I come across the same value of string between 14th and 27th Position, that I encountered before in the file, I should replace with D00000X, else with D00000X+1
Output
DD0TRANSID00001902121D000006003379433005533665506656000008587201902070168304000.0AK 0000L00000.00 N 01683016832019021220190212N0000.001683065570067.000000.00000.0000000000000NAcknowledgment
DD0TRANSID00001902121D000006003379433005535567606656000008587201902085381804000.0FC 0000L00000.00 N 53818538182019021220190212N0000.053818065570067.000000.00000.0000000000000NFirst Contact
DD0TRANSID00001902121D000007003379433005535568006656000008587201902085381804000.0SR 0000L00000.00 N 53818538182019021220190212N0000.0
CC0TRANSID000019021210510360003379433005535568006656000008587201902085381804000.0SR 0000L00000.00 N 53818538182019021220190212N0000.0
awk sed perl
asked 2 days ago
Rohit PrasadRohit Prasad
11
New contributor
Rohit Prasad is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
I have a text file with following lines for example.
Input
DD0TRANSID000019021210504250003379433005533665506656000008587201902070168304000.0AK 0000L00000.00 N 01683016832019021220190212N0000.001683065570067.000000.00000.0000000000000NAcknowledgment
DD0TRANSID000019021210504250003379433005535567606656000008587201902085381804000.0FC 0000L00000.00 N 53818538182019021220190212N0000.053818065570067.000000.00000.0000000000000NFirst Contact
DD0TRANSID000019021210510360003379433005535568006656000008587201902085381804000.0SR 0000L00000.00 N 53818538182019021220190212N0000.0
CC0TRANSID000019021210510360003379433005535568006656000008587201902085381804000.0SR 0000L00000.00 N 53818538182019021220190212N0000.0
My requirement is
If the line begins with "D" then replace string starting from 14th position to 27th Position with D00000X (X being a number with left padding)
If I come across the same value of string between 14th and 27th Position, that I encountered before in the file, I should replace with D00000X, else with D00000X+1
Output
DD0TRANSID00001902121D000006003379433005533665506656000008587201902070168304000.0AK 0000L00000.00 N 01683016832019021220190212N0000.001683065570067.000000.00000.0000000000000NAcknowledgment
DD0TRANSID00001902121D000006003379433005535567606656000008587201902085381804000.0FC 0000L00000.00 N 53818538182019021220190212N0000.053818065570067.000000.00000.0000000000000NFirst Contact
DD0TRANSID00001902121D000007003379433005535568006656000008587201902085381804000.0SR 0000L00000.00 N 53818538182019021220190212N0000.0
CC0TRANSID000019021210510360003379433005535568006656000008587201902085381804000.0SR 0000L00000.00 N 53818538182019021220190212N0000.0
awk sed perl
awk sed perl
asked 2 days ago
Rohit PrasadRohit Prasad
11
New contributor
Rohit Prasad is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 2 days ago
Rohit PrasadRohit Prasad
11
New contributor
Rohit Prasad is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 2 days ago
Rohit Prasad
asked 2 days ago
Rohit PrasadRohit Prasad
11
New contributor
Rohit Prasad is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 2 days ago
Rohit PrasadRohit Prasad
11
asked 2 days ago
Rohit PrasadRohit Prasad
11
11
New contributor
Rohit Prasad is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Rohit Prasad is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Rohit Prasad is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
1
Are you sure the replacement happens at position 14? The output doesn't seem right - I see the change at position 21 (or 22 if 1-based).
– choroba
2 days ago
Is'nt it the same question
– ctac_
2 days ago
No, it isnt the same question. I need to repeat the replaced string, every time I encounter a duplicate string(string between 14-21 position) else keep incrementing.
– Rohit Prasad
2 days ago
add a comment |
1
Are you sure the replacement happens at position 14? The output doesn't seem right - I see the change at position 21 (or 22 if 1-based).
– choroba
2 days ago
Is'nt it the same question
– ctac_
2 days ago
No, it isnt the same question. I need to repeat the replaced string, every time I encounter a duplicate string(string between 14-21 position) else keep incrementing.
– Rohit Prasad
2 days ago
1
1
Are you sure the replacement happens at position 14? The output doesn't seem right - I see the change at position 21 (or 22 if 1-based).
– choroba
2 days ago
Are you sure the replacement happens at position 14? The output doesn't seem right - I see the change at position 21 (or 22 if 1-based).
– choroba
2 days ago
Is'nt it the same question
– ctac_
2 days ago
Is'nt it the same question
– ctac_
2 days ago
No, it isnt the same question. I need to repeat the replaced string, every time I encounter a duplicate string(string between 14-21 position) else keep incrementing.
– Rohit Prasad
2 days ago
No, it isnt the same question. I need to repeat the replaced string, every time I encounter a duplicate string(string between 14-21 position) else keep incrementing.
– Rohit Prasad
2 days ago
add a comment |
1 Answer
1
active
oldest
votes
Assuming that these are date/time stamps and increment in sequence then
a=($(grep -Po "(?<=^D.13).13" testfile | uniq))
for ((i=0; i<$#a[@]; i+=1)); do
s=$a[$i]
sed -E -i "s/(D.13)$s/1$s:0:7D$(printf '%06d' $((i+1)))/g" testfile
done
If a stamp repeats further down the file it gets a new counter increment. If you don't want that then the uniq needs to be sort | uniq which will apply the same counter to the same stamp throughout the file.
BTW, looks like you removed the 0 at position 28 in your example.
answered 2 days ago
bu5hmanbu5hman
1,356415
add a comment |
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1 Answer
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1 Answer
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votes
Assuming that these are date/time stamps and increment in sequence then
a=($(grep -Po "(?<=^D.13).13" testfile | uniq))
for ((i=0; i<$#a[@]; i+=1)); do
s=$a[$i]
sed -E -i "s/(D.13)$s/1$s:0:7D$(printf '%06d' $((i+1)))/g" testfile
done
If a stamp repeats further down the file it gets a new counter increment. If you don't want that then the uniq needs to be sort | uniq which will apply the same counter to the same stamp throughout the file.
BTW, looks like you removed the 0 at position 28 in your example.
answered 2 days ago
bu5hmanbu5hman
1,356415
add a comment |
Assuming that these are date/time stamps and increment in sequence then
a=($(grep -Po "(?<=^D.13).13" testfile | uniq))
for ((i=0; i<$#a[@]; i+=1)); do
s=$a[$i]
sed -E -i "s/(D.13)$s/1$s:0:7D$(printf '%06d' $((i+1)))/g" testfile
done
If a stamp repeats further down the file it gets a new counter increment. If you don't want that then the uniq needs to be sort | uniq which will apply the same counter to the same stamp throughout the file.
BTW, looks like you removed the 0 at position 28 in your example.
answered 2 days ago
bu5hmanbu5hman
1,356415
add a comment |
Assuming that these are date/time stamps and increment in sequence then
a=($(grep -Po "(?<=^D.13).13" testfile | uniq))
for ((i=0; i<$#a[@]; i+=1)); do
s=$a[$i]
sed -E -i "s/(D.13)$s/1$s:0:7D$(printf '%06d' $((i+1)))/g" testfile
done
If a stamp repeats further down the file it gets a new counter increment. If you don't want that then the uniq needs to be sort | uniq which will apply the same counter to the same stamp throughout the file.
BTW, looks like you removed the 0 at position 28 in your example.
answered 2 days ago
bu5hmanbu5hman
1,356415
Assuming that these are date/time stamps and increment in sequence then
a=($(grep -Po "(?<=^D.13).13" testfile | uniq))
for ((i=0; i<$#a[@]; i+=1)); do
s=$a[$i]
sed -E -i "s/(D.13)$s/1$s:0:7D$(printf '%06d' $((i+1)))/g" testfile
done
If a stamp repeats further down the file it gets a new counter increment. If you don't want that then the uniq needs to be sort | uniq which will apply the same counter to the same stamp throughout the file.
BTW, looks like you removed the 0 at position 28 in your example.
answered 2 days ago
bu5hmanbu5hman
1,356415
answered 2 days ago
bu5hmanbu5hman
1,356415
answered 2 days ago
bu5hmanbu5hman
1,356415
answered 2 days ago
bu5hmanbu5hman
1,356415
1,356415
add a comment |
add a comment |
Rohit Prasad is a new contributor. Be nice, and check out our Code of Conduct.
Rohit Prasad is a new contributor. Be nice, and check out our Code of Conduct.
Rohit Prasad is a new contributor. Be nice, and check out our Code of Conduct.
Rohit Prasad is a new contributor. Be nice, and check out our Code of Conduct.
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-awk, perl, sed
1
Are you sure the replacement happens at position 14? The output doesn't seem right - I see the change at position 21 (or 22 if 1-based).
– choroba
2 days ago
Is'nt it the same question
– ctac_
2 days ago
No, it isnt the same question. I need to repeat the replaced string, every time I encounter a duplicate string(string between 14-21 position) else keep incrementing.
– Rohit Prasad
2 days ago