Eliminate empty elements from a list with a specific pattern The 2019 Stack Overflow Developer Survey Results Are InList operation on specific elementsSelect elements from list with given headSelecting elements from a list with nullsReplace empty list elements with patternReplacing Non-Constant Elements from List with Patternselecting elements from a list with two numbersRemoving elements of a specific length from a listEliminate types of elements from the listListPlot3D with empty matrix elementsDelete a large pattern from one list

Why can Shazam fly?

Why do we hear so much about the Trump administration deciding to impose and then remove tariffs?

Origin of "cooter" meaning "vagina"

What did it mean to "align" a radio?

Does a dangling wire really electrocute me if I'm standing in water?

How to deal with fear of taking dependencies

Geography at the pixel level

Earliest use of the term "Galois extension"?

Protecting Dualbooting Windows from dangerous code (like rm -rf)

How to answer pointed "are you quitting" questioning when I don't want them to suspect

How to save as into a customized destination on macOS?

Return to UK after being refused entry years previously

Loose spokes after only a few rides

"as much details as you can remember"

Is an up-to-date browser secure on an out-of-date OS?

Did 3000BC Egyptians use meteoric iron weapons?

Why was M87 targetted for the Event Horizon Telescope instead of Sagittarius A*?

Can we generate random numbers using irrational numbers like π and e?

Falsification in Math vs Science

Shouldn't "much" here be used instead of "more"?

What could be the right powersource for 15 seconds lifespan disposable giant chainsaw?

Landlord wants to switch my lease to a "Land contract" to "get back at the city"

How to notate time signature switching consistently every measure

How technical should a Scrum Master be to effectively remove impediments?



Eliminate empty elements from a list with a specific pattern



The 2019 Stack Overflow Developer Survey Results Are InList operation on specific elementsSelect elements from list with given headSelecting elements from a list with nullsReplace empty list elements with patternReplacing Non-Constant Elements from List with Patternselecting elements from a list with two numbersRemoving elements of a specific length from a listEliminate types of elements from the listListPlot3D with empty matrix elementsDelete a large pattern from one list










3












$begingroup$


I am really new in this patterns part of Mathematica. Basically what I need to do is eliminate null elements from a list but that has a specific name before the empty element. For example, my list is:



list="a11-b11-", "a12-b11-1", "c11-d22-", "d33-c22-2"


and I need to obtain



list="a12-b11-1", "d33-c22-2"


The list was created using



list = Flatten[Table[ ToString[namea[[i]] <> "-" <> nameb[[j]] <> "-" <> 
ToString[ Select[int[i, j, 0.5], Abs[#] == 0.5 &, 1] ]],
i, 1, 4, j, 1, 4], 1]


and for some values it writtes because there is not a value equal to $0.5$. Until now I have been able to do it term by term as



list//."a11-b11-"-> Sequence[]


but the real list contains a lot of elements and could be almost impossible to do it that way to solve the problem. I think my main problem is that I am not sure how to specify the pattern search (something like " *-name " in gnu/linux). Is there a wise way to do this?. Thanks in advance.










share|improve this question











$endgroup$











  • $begingroup$
    Have a look at DeleteCases and StringMatchQ or StringContainsQ.
    $endgroup$
    – b.gatessucks
    2 days ago










  • $begingroup$
    I think it would be more efficient to first filter out the unwanted cases in the int function, and then construct strings only from the remaining ones.
    $endgroup$
    – Roman
    2 days ago











  • $begingroup$
    @b.gatessucks Thank you, I will look those option in Mathematica.
    $endgroup$
    – mors
    2 days ago










  • $begingroup$
    @Roman You are right, but I am new ih this cases stuf in Mathematica and I did no know how to do it when I created the list.
    $endgroup$
    – mors
    2 days ago















3












$begingroup$


I am really new in this patterns part of Mathematica. Basically what I need to do is eliminate null elements from a list but that has a specific name before the empty element. For example, my list is:



list="a11-b11-", "a12-b11-1", "c11-d22-", "d33-c22-2"


and I need to obtain



list="a12-b11-1", "d33-c22-2"


The list was created using



list = Flatten[Table[ ToString[namea[[i]] <> "-" <> nameb[[j]] <> "-" <> 
ToString[ Select[int[i, j, 0.5], Abs[#] == 0.5 &, 1] ]],
i, 1, 4, j, 1, 4], 1]


and for some values it writtes because there is not a value equal to $0.5$. Until now I have been able to do it term by term as



list//."a11-b11-"-> Sequence[]


but the real list contains a lot of elements and could be almost impossible to do it that way to solve the problem. I think my main problem is that I am not sure how to specify the pattern search (something like " *-name " in gnu/linux). Is there a wise way to do this?. Thanks in advance.










share|improve this question











$endgroup$











  • $begingroup$
    Have a look at DeleteCases and StringMatchQ or StringContainsQ.
    $endgroup$
    – b.gatessucks
    2 days ago










  • $begingroup$
    I think it would be more efficient to first filter out the unwanted cases in the int function, and then construct strings only from the remaining ones.
    $endgroup$
    – Roman
    2 days ago











  • $begingroup$
    @b.gatessucks Thank you, I will look those option in Mathematica.
    $endgroup$
    – mors
    2 days ago










  • $begingroup$
    @Roman You are right, but I am new ih this cases stuf in Mathematica and I did no know how to do it when I created the list.
    $endgroup$
    – mors
    2 days ago













3












3








3


1



$begingroup$


I am really new in this patterns part of Mathematica. Basically what I need to do is eliminate null elements from a list but that has a specific name before the empty element. For example, my list is:



list="a11-b11-", "a12-b11-1", "c11-d22-", "d33-c22-2"


and I need to obtain



list="a12-b11-1", "d33-c22-2"


The list was created using



list = Flatten[Table[ ToString[namea[[i]] <> "-" <> nameb[[j]] <> "-" <> 
ToString[ Select[int[i, j, 0.5], Abs[#] == 0.5 &, 1] ]],
i, 1, 4, j, 1, 4], 1]


and for some values it writtes because there is not a value equal to $0.5$. Until now I have been able to do it term by term as



list//."a11-b11-"-> Sequence[]


but the real list contains a lot of elements and could be almost impossible to do it that way to solve the problem. I think my main problem is that I am not sure how to specify the pattern search (something like " *-name " in gnu/linux). Is there a wise way to do this?. Thanks in advance.










share|improve this question











$endgroup$




I am really new in this patterns part of Mathematica. Basically what I need to do is eliminate null elements from a list but that has a specific name before the empty element. For example, my list is:



list="a11-b11-", "a12-b11-1", "c11-d22-", "d33-c22-2"


and I need to obtain



list="a12-b11-1", "d33-c22-2"


The list was created using



list = Flatten[Table[ ToString[namea[[i]] <> "-" <> nameb[[j]] <> "-" <> 
ToString[ Select[int[i, j, 0.5], Abs[#] == 0.5 &, 1] ]],
i, 1, 4, j, 1, 4], 1]


and for some values it writtes because there is not a value equal to $0.5$. Until now I have been able to do it term by term as



list//."a11-b11-"-> Sequence[]


but the real list contains a lot of elements and could be almost impossible to do it that way to solve the problem. I think my main problem is that I am not sure how to specify the pattern search (something like " *-name " in gnu/linux). Is there a wise way to do this?. Thanks in advance.







list-manipulation filtering






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 2 days ago









Roman

4,95511130




4,95511130










asked 2 days ago









morsmors

496




496











  • $begingroup$
    Have a look at DeleteCases and StringMatchQ or StringContainsQ.
    $endgroup$
    – b.gatessucks
    2 days ago










  • $begingroup$
    I think it would be more efficient to first filter out the unwanted cases in the int function, and then construct strings only from the remaining ones.
    $endgroup$
    – Roman
    2 days ago











  • $begingroup$
    @b.gatessucks Thank you, I will look those option in Mathematica.
    $endgroup$
    – mors
    2 days ago










  • $begingroup$
    @Roman You are right, but I am new ih this cases stuf in Mathematica and I did no know how to do it when I created the list.
    $endgroup$
    – mors
    2 days ago
















  • $begingroup$
    Have a look at DeleteCases and StringMatchQ or StringContainsQ.
    $endgroup$
    – b.gatessucks
    2 days ago










  • $begingroup$
    I think it would be more efficient to first filter out the unwanted cases in the int function, and then construct strings only from the remaining ones.
    $endgroup$
    – Roman
    2 days ago











  • $begingroup$
    @b.gatessucks Thank you, I will look those option in Mathematica.
    $endgroup$
    – mors
    2 days ago










  • $begingroup$
    @Roman You are right, but I am new ih this cases stuf in Mathematica and I did no know how to do it when I created the list.
    $endgroup$
    – mors
    2 days ago















$begingroup$
Have a look at DeleteCases and StringMatchQ or StringContainsQ.
$endgroup$
– b.gatessucks
2 days ago




$begingroup$
Have a look at DeleteCases and StringMatchQ or StringContainsQ.
$endgroup$
– b.gatessucks
2 days ago












$begingroup$
I think it would be more efficient to first filter out the unwanted cases in the int function, and then construct strings only from the remaining ones.
$endgroup$
– Roman
2 days ago





$begingroup$
I think it would be more efficient to first filter out the unwanted cases in the int function, and then construct strings only from the remaining ones.
$endgroup$
– Roman
2 days ago













$begingroup$
@b.gatessucks Thank you, I will look those option in Mathematica.
$endgroup$
– mors
2 days ago




$begingroup$
@b.gatessucks Thank you, I will look those option in Mathematica.
$endgroup$
– mors
2 days ago












$begingroup$
@Roman You are right, but I am new ih this cases stuf in Mathematica and I did no know how to do it when I created the list.
$endgroup$
– mors
2 days ago




$begingroup$
@Roman You are right, but I am new ih this cases stuf in Mathematica and I did no know how to do it when I created the list.
$endgroup$
– mors
2 days ago










2 Answers
2






active

oldest

votes


















7












$begingroup$

If the list elements are strings, as it appears after your comment, you can use Select with a string pattern:



list = "a11-b11-", "a12-b11-1", "c11-d22-", "d33-c22-2";
Select[list, Not@*StringMatchQ[__ ~~ ""]]



"a12-b11-1", "d33-c22-2"




You could also Select before making the strings:



L = DeleteCases[
Flatten[
Table[
namea[[i]], nameb[[j]], Select[int[i, j, 0.5], Abs[#] == 0.5 &, 1],
i, 4, j, 4],
1],
_, _, ];


and then make these into strings:



StringRiffle[ToString /@ #, "-"] & /@ L


I can't check this because you didn't supply functioning code.






share|improve this answer











$endgroup$












  • $begingroup$
    Thank you, I forgot to specify the way the list is created. I create the list as 'list = Flatten[Table[ ToString[namea[[i]] <> "-" <> nameb[[j]] <> "-" <> ToString[ Select[int[i, j, 0.5], Abs[#] == 0.5 &, 1] ]], i, 1, 4, j, 1, 4], 1] '
    $endgroup$
    – mors
    2 days ago



















1












$begingroup$

In 10.1, two functions were added to handle a pair of very common cases: StringStartsQ and StringEndsQ which return True if the string matches a pattern at the beginning or end, respectively. So, while Roman's answer gives you the full general form, most of the pattern can be eliminated by using



list = "a11-b11-", "a12-b11-1", "c11-d22-", "d33-c22-2";
Select[list, Not@*StringEndsQ[""]]


instead.






share|improve this answer









$endgroup$













    Your Answer





    StackExchange.ifUsing("editor", function ()
    return StackExchange.using("mathjaxEditing", function ()
    StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix)
    StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
    );
    );
    , "mathjax-editing");

    StackExchange.ready(function()
    var channelOptions =
    tags: "".split(" "),
    id: "387"
    ;
    initTagRenderer("".split(" "), "".split(" "), channelOptions);

    StackExchange.using("externalEditor", function()
    // Have to fire editor after snippets, if snippets enabled
    if (StackExchange.settings.snippets.snippetsEnabled)
    StackExchange.using("snippets", function()
    createEditor();
    );

    else
    createEditor();

    );

    function createEditor()
    StackExchange.prepareEditor(
    heartbeatType: 'answer',
    autoActivateHeartbeat: false,
    convertImagesToLinks: false,
    noModals: true,
    showLowRepImageUploadWarning: true,
    reputationToPostImages: null,
    bindNavPrevention: true,
    postfix: "",
    imageUploader:
    brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
    contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
    allowUrls: true
    ,
    onDemand: true,
    discardSelector: ".discard-answer"
    ,immediatelyShowMarkdownHelp:true
    );



    );













    draft saved

    draft discarded


















    StackExchange.ready(
    function ()
    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmathematica.stackexchange.com%2fquestions%2f194815%2feliminate-empty-elements-from-a-list-with-a-specific-pattern%23new-answer', 'question_page');

    );

    Post as a guest















    Required, but never shown

























    2 Answers
    2






    active

    oldest

    votes








    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    7












    $begingroup$

    If the list elements are strings, as it appears after your comment, you can use Select with a string pattern:



    list = "a11-b11-", "a12-b11-1", "c11-d22-", "d33-c22-2";
    Select[list, Not@*StringMatchQ[__ ~~ ""]]



    "a12-b11-1", "d33-c22-2"




    You could also Select before making the strings:



    L = DeleteCases[
    Flatten[
    Table[
    namea[[i]], nameb[[j]], Select[int[i, j, 0.5], Abs[#] == 0.5 &, 1],
    i, 4, j, 4],
    1],
    _, _, ];


    and then make these into strings:



    StringRiffle[ToString /@ #, "-"] & /@ L


    I can't check this because you didn't supply functioning code.






    share|improve this answer











    $endgroup$












    • $begingroup$
      Thank you, I forgot to specify the way the list is created. I create the list as 'list = Flatten[Table[ ToString[namea[[i]] <> "-" <> nameb[[j]] <> "-" <> ToString[ Select[int[i, j, 0.5], Abs[#] == 0.5 &, 1] ]], i, 1, 4, j, 1, 4], 1] '
      $endgroup$
      – mors
      2 days ago
















    7












    $begingroup$

    If the list elements are strings, as it appears after your comment, you can use Select with a string pattern:



    list = "a11-b11-", "a12-b11-1", "c11-d22-", "d33-c22-2";
    Select[list, Not@*StringMatchQ[__ ~~ ""]]



    "a12-b11-1", "d33-c22-2"




    You could also Select before making the strings:



    L = DeleteCases[
    Flatten[
    Table[
    namea[[i]], nameb[[j]], Select[int[i, j, 0.5], Abs[#] == 0.5 &, 1],
    i, 4, j, 4],
    1],
    _, _, ];


    and then make these into strings:



    StringRiffle[ToString /@ #, "-"] & /@ L


    I can't check this because you didn't supply functioning code.






    share|improve this answer











    $endgroup$












    • $begingroup$
      Thank you, I forgot to specify the way the list is created. I create the list as 'list = Flatten[Table[ ToString[namea[[i]] <> "-" <> nameb[[j]] <> "-" <> ToString[ Select[int[i, j, 0.5], Abs[#] == 0.5 &, 1] ]], i, 1, 4, j, 1, 4], 1] '
      $endgroup$
      – mors
      2 days ago














    7












    7








    7





    $begingroup$

    If the list elements are strings, as it appears after your comment, you can use Select with a string pattern:



    list = "a11-b11-", "a12-b11-1", "c11-d22-", "d33-c22-2";
    Select[list, Not@*StringMatchQ[__ ~~ ""]]



    "a12-b11-1", "d33-c22-2"




    You could also Select before making the strings:



    L = DeleteCases[
    Flatten[
    Table[
    namea[[i]], nameb[[j]], Select[int[i, j, 0.5], Abs[#] == 0.5 &, 1],
    i, 4, j, 4],
    1],
    _, _, ];


    and then make these into strings:



    StringRiffle[ToString /@ #, "-"] & /@ L


    I can't check this because you didn't supply functioning code.






    share|improve this answer











    $endgroup$



    If the list elements are strings, as it appears after your comment, you can use Select with a string pattern:



    list = "a11-b11-", "a12-b11-1", "c11-d22-", "d33-c22-2";
    Select[list, Not@*StringMatchQ[__ ~~ ""]]



    "a12-b11-1", "d33-c22-2"




    You could also Select before making the strings:



    L = DeleteCases[
    Flatten[
    Table[
    namea[[i]], nameb[[j]], Select[int[i, j, 0.5], Abs[#] == 0.5 &, 1],
    i, 4, j, 4],
    1],
    _, _, ];


    and then make these into strings:



    StringRiffle[ToString /@ #, "-"] & /@ L


    I can't check this because you didn't supply functioning code.







    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited 2 days ago

























    answered 2 days ago









    RomanRoman

    4,95511130




    4,95511130











    • $begingroup$
      Thank you, I forgot to specify the way the list is created. I create the list as 'list = Flatten[Table[ ToString[namea[[i]] <> "-" <> nameb[[j]] <> "-" <> ToString[ Select[int[i, j, 0.5], Abs[#] == 0.5 &, 1] ]], i, 1, 4, j, 1, 4], 1] '
      $endgroup$
      – mors
      2 days ago

















    • $begingroup$
      Thank you, I forgot to specify the way the list is created. I create the list as 'list = Flatten[Table[ ToString[namea[[i]] <> "-" <> nameb[[j]] <> "-" <> ToString[ Select[int[i, j, 0.5], Abs[#] == 0.5 &, 1] ]], i, 1, 4, j, 1, 4], 1] '
      $endgroup$
      – mors
      2 days ago
















    $begingroup$
    Thank you, I forgot to specify the way the list is created. I create the list as 'list = Flatten[Table[ ToString[namea[[i]] <> "-" <> nameb[[j]] <> "-" <> ToString[ Select[int[i, j, 0.5], Abs[#] == 0.5 &, 1] ]], i, 1, 4, j, 1, 4], 1] '
    $endgroup$
    – mors
    2 days ago





    $begingroup$
    Thank you, I forgot to specify the way the list is created. I create the list as 'list = Flatten[Table[ ToString[namea[[i]] <> "-" <> nameb[[j]] <> "-" <> ToString[ Select[int[i, j, 0.5], Abs[#] == 0.5 &, 1] ]], i, 1, 4, j, 1, 4], 1] '
    $endgroup$
    – mors
    2 days ago












    1












    $begingroup$

    In 10.1, two functions were added to handle a pair of very common cases: StringStartsQ and StringEndsQ which return True if the string matches a pattern at the beginning or end, respectively. So, while Roman's answer gives you the full general form, most of the pattern can be eliminated by using



    list = "a11-b11-", "a12-b11-1", "c11-d22-", "d33-c22-2";
    Select[list, Not@*StringEndsQ[""]]


    instead.






    share|improve this answer









    $endgroup$

















      1












      $begingroup$

      In 10.1, two functions were added to handle a pair of very common cases: StringStartsQ and StringEndsQ which return True if the string matches a pattern at the beginning or end, respectively. So, while Roman's answer gives you the full general form, most of the pattern can be eliminated by using



      list = "a11-b11-", "a12-b11-1", "c11-d22-", "d33-c22-2";
      Select[list, Not@*StringEndsQ[""]]


      instead.






      share|improve this answer









      $endgroup$















        1












        1








        1





        $begingroup$

        In 10.1, two functions were added to handle a pair of very common cases: StringStartsQ and StringEndsQ which return True if the string matches a pattern at the beginning or end, respectively. So, while Roman's answer gives you the full general form, most of the pattern can be eliminated by using



        list = "a11-b11-", "a12-b11-1", "c11-d22-", "d33-c22-2";
        Select[list, Not@*StringEndsQ[""]]


        instead.






        share|improve this answer









        $endgroup$



        In 10.1, two functions were added to handle a pair of very common cases: StringStartsQ and StringEndsQ which return True if the string matches a pattern at the beginning or end, respectively. So, while Roman's answer gives you the full general form, most of the pattern can be eliminated by using



        list = "a11-b11-", "a12-b11-1", "c11-d22-", "d33-c22-2";
        Select[list, Not@*StringEndsQ[""]]


        instead.







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered 2 days ago









        rcollyerrcollyer

        28.6k674166




        28.6k674166



























            draft saved

            draft discarded
















































            Thanks for contributing an answer to Mathematica Stack Exchange!


            • Please be sure to answer the question. Provide details and share your research!

            But avoid


            • Asking for help, clarification, or responding to other answers.

            • Making statements based on opinion; back them up with references or personal experience.

            Use MathJax to format equations. MathJax reference.


            To learn more, see our tips on writing great answers.




            draft saved


            draft discarded














            StackExchange.ready(
            function ()
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmathematica.stackexchange.com%2fquestions%2f194815%2feliminate-empty-elements-from-a-list-with-a-specific-pattern%23new-answer', 'question_page');

            );

            Post as a guest















            Required, but never shown





















































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown

































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown







            -filtering, list-manipulation

            Popular posts from this blog

            Word for a person who has no opinion about whether god existsWord for having a definite opinion while simultaneously withholding judgment?What's the opposite of “newcomer? Is ”veteran" OK?What do you call an “atheist” who might believe in an afterlife?What's a word for someone who wants to voice opinions but not have them challenged?Word for someone who dismisses contrary opinions as irrational?Somone who thinks they are overly special/out of the ordinaryIs there a word, phrase or idiom for “a person who is incapable of thinking about the future”?The belief that a god is human-likeA word for a non-famous person/thing you have heard a lot aboutAdjective for a person who enjoys taking care of their appearance

            What was this official D&D 3.5e Lovecraft-flavored rulebook?What was this set of RPG tools called?As a first-time DM should I let my players play complex character classes and roles?Nymph's Kiss and the RelationshipWhat was the name of this Cleric Prestige Class that shapes metal with its bare hands?Are the 3.5e Dragonlance books third party or official works?What's up with the domain Vile Darkness?What was this 80s book about RPGs?What was the name of this Werewolf band?What book had Rituals to “upgrade” animal companions to keep them viable at higher levels?What was this RPG that had rules for player-owned businesses?

            2017 IndyCar Series Contents Series news Teams and drivers Schedule Season summary Footnotes References External links Navigation menu"INDYCAR: Initial 2018 bodywork concepts unveiled"the original"IndyCar confirms switch to Performance Friction brakes in 2017""AJ Foyt Racing will switch to Chevy"the original"Carlos Munoz, Conor Daly will drive for AJ Foyt Racing""Zach Veach's Indy 500 Debut Confirmed with Foyt""No mass exodus from Honda after Ganassi switch""Ex-F1 driver Sato joins Andretti Autosport for 2017 IndyCar season""IndyCar's Ryan Hunter-Reay, sponsor DHL paired through 2020""hhgregg and Andretti Autosport announce partnership for key races in 2016""INDYCAR: Rossi re-signs with Andretti"the original"McLaren Formula 1 - Fernando Alonso to race at Indy 500 with McLaren, Honda and Andretti Autosport""Shank will finally take part in Indy 500 with Harvey, Andretti | MotorSportsTalk""Andretti adds Jack Harvey to Indy 500 field""Ganassi switches to Honda power for 2017""INDYCAR: Chilton returns to Ganassi"the original"IndyCar silly season: Who's going where in 2017?""INDYCAR: Kanaan, NTT Data return to Ganassi"the original"Kimball to remain at Ganassi for 2017""Coyne confirms Bourdais for 2017 IndyCar season""Davison to sub for Bourdais in Indy 500"the original"Gutierrez confirmed for Detroit IndyCar debut""Gutierrez returns with Coyne for rest of 2017 season""Vautier to drive for Coyne at Texas"the original"INDYCAR: Coyne confirms Jones for 2017"the original"Pippa Mann returns to Coyne for Indy 500""Karam, Dreyer & Reinbold teaming up again for Indianapolis 500""Pigot to return to Ed Carpenter Racing""Hildebrand confirmed as full-time Ed Carpenter driver""Veach to replace injured Hildebrand at Barber"the originalNew Team Harding Racing Enters Chaves for 101st Indianapolis 500"Juncos Racing Announces Entry in 101st Running of the Indianapolis 500 :: Juncos Racing""Juncos confirms Pigot for Indy 500""Saavedra confirmed in Juncos' second 500 entry"the original"Lazier confirms Indy 500 run after son's USF2000 debut"the original"Claman DeMelo to race for RLLR at Sonoma"the original"Rahal signs Servia and ace engineer for 2017""IndyCar: Aleshin returns with Schmidt"the original"Aleshin replaced by Saavedra for Toronto""Jack Harvey will pilot SPM No. 7 car at Watkins Glen, Sonoma""Jay Howard confirmed in Tony Stewart's supported SPM Indy entry""INDYCAR: Newgarden to wave the flag at Penske"the original"Pagenaud opts for No. 1 in 2017"the original"Penske confirms Newgarden for 2017""Montoya to stay with Team Penske in 2017""Target leaving IndyCar after 27 seasons with Chip Ganassi""Cavin: IndyCar could see complete driver/team shakeup in 2017""End of the road for KV Racing?""KV Racing confirms closure, equipment sold to Juncos""Juncos confirms IndyCar Series entry"the original"Juncos readies IndyCar program, aims for '17 500"the original"Harding Racing to add Texas, Pocono to schedule"the original"Sato signs with Andretti Autosport for 2017""INDYCAR: Aleshin in Doubt at SPM"the original"Long Beach notebook: JR Hildebrand breaks hand""Hildebrand cleared to return at Phoenix"the original"Bourdais to undergo surgery on multiple fractures""Aleshin loses Schmidt Peterson IndyCar ride""Saavedra in at SPM for Pocono, Gateway"the original"Bourdais to make return at Gateway"the original"The IndyCar Grand Prix no longer is sponsored by Angie's List""2017 IndyCar Series rulebook""2017 Verizon IndyCar Series Official Rulebook"Official websiteeeeee