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Need regex to replace the whole line, but the last optional character
The 2019 Stack Overflow Developer Survey Results Are InReplace a character except last x occurrencesHow do I join the next line when a line matches a regex for whole document in VI?Why don't I need to escape a character class in sed but I need to escape the rest?Sed command that would ignore any commented matchCommand line tool for easy multiline regex search and replaceWhy doesn't the '?' regex character produce a match in sed?Regex to match beginning and end of line in Vim (quote around whole line)How to make a (sed) regex replacing all occurances of one character while deleting the last?Regex Pattern and Replace line with substitutionvim: command for removing semicolon if it is the last character of the line
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;
It sounds like it should be trivial task, but I cannot figure it out, so I decided to ask. I need to replace the whole line, but optional last character. For instance, I want:abcd to become efgh butabcd, to become efgh,
How can I create regex like that? It seems optional character cannot be back-referenced, i.e something like: s/.*(,)?$/efgh1 won't work (I tried :) )
To make it clear, the lines are arbitrary length with arbitrary characters. The only condition in my case is to preserve comma at the end of the line after the replacement if one existed there or drop it if line did not end up with comma
regular-expression
asked 2 days ago
Shimon PozinShimon Pozin
1012
New contributor
Shimon Pozin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
It sounds like it should be trivial task, but I cannot figure it out, so I decided to ask. I need to replace the whole line, but optional last character. For instance, I want:abcd to become efgh butabcd, to become efgh,
How can I create regex like that? It seems optional character cannot be back-referenced, i.e something like: s/.*(,)?$/efgh1 won't work (I tried :) )
To make it clear, the lines are arbitrary length with arbitrary characters. The only condition in my case is to preserve comma at the end of the line after the replacement if one existed there or drop it if line did not end up with comma
regular-expression
asked 2 days ago
Shimon PozinShimon Pozin
1012
New contributor
Shimon Pozin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
1
Any length lines? Alwaysabcd? Always a comma? How do we tell whether or not the last character should be kept?
– roaima
2 days ago
What tool are you using to apply the RE? Different tools use different variants (unfortunately).
– roaima
2 days ago
.*is greedy, meaning it will match the whole string first then try the rest of the match, which since the next group is optional it will never get matched. Some regex flavors have a reluctant quantifier which will try matching the least amount of characters.
– Torin
2 days ago
add a comment |
It sounds like it should be trivial task, but I cannot figure it out, so I decided to ask. I need to replace the whole line, but optional last character. For instance, I want:abcd to become efgh butabcd, to become efgh,
How can I create regex like that? It seems optional character cannot be back-referenced, i.e something like: s/.*(,)?$/efgh1 won't work (I tried :) )
To make it clear, the lines are arbitrary length with arbitrary characters. The only condition in my case is to preserve comma at the end of the line after the replacement if one existed there or drop it if line did not end up with comma
regular-expression
asked 2 days ago
Shimon PozinShimon Pozin
1012
New contributor
Shimon Pozin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
It sounds like it should be trivial task, but I cannot figure it out, so I decided to ask. I need to replace the whole line, but optional last character. For instance, I want:abcd to become efgh butabcd, to become efgh,
How can I create regex like that? It seems optional character cannot be back-referenced, i.e something like: s/.*(,)?$/efgh1 won't work (I tried :) )
To make it clear, the lines are arbitrary length with arbitrary characters. The only condition in my case is to preserve comma at the end of the line after the replacement if one existed there or drop it if line did not end up with comma
regular-expression
regular-expression
asked 2 days ago
Shimon PozinShimon Pozin
1012
New contributor
Shimon Pozin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 2 days ago
Shimon PozinShimon Pozin
1012
New contributor
Shimon Pozin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 2 days ago
Shimon Pozin
asked 2 days ago
Shimon PozinShimon Pozin
1012
New contributor
Shimon Pozin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 2 days ago
Shimon PozinShimon Pozin
1012
asked 2 days ago
Shimon PozinShimon Pozin
1012
1012
New contributor
Shimon Pozin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Shimon Pozin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Shimon Pozin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
1
Any length lines? Alwaysabcd? Always a comma? How do we tell whether or not the last character should be kept?
– roaima
2 days ago
What tool are you using to apply the RE? Different tools use different variants (unfortunately).
– roaima
2 days ago
.*is greedy, meaning it will match the whole string first then try the rest of the match, which since the next group is optional it will never get matched. Some regex flavors have a reluctant quantifier which will try matching the least amount of characters.
– Torin
2 days ago
add a comment |
1
Any length lines? Alwaysabcd? Always a comma? How do we tell whether or not the last character should be kept?
– roaima
2 days ago
What tool are you using to apply the RE? Different tools use different variants (unfortunately).
– roaima
2 days ago
.*is greedy, meaning it will match the whole string first then try the rest of the match, which since the next group is optional it will never get matched. Some regex flavors have a reluctant quantifier which will try matching the least amount of characters.
– Torin
2 days ago
1
1
Any length lines? Always
abcd? Always a comma? How do we tell whether or not the last character should be kept?– roaima
2 days ago
Any length lines? Always
abcd? Always a comma? How do we tell whether or not the last character should be kept?– roaima
2 days ago
What tool are you using to apply the RE? Different tools use different variants (unfortunately).
– roaima
2 days ago
What tool are you using to apply the RE? Different tools use different variants (unfortunately).
– roaima
2 days ago
.* is greedy, meaning it will match the whole string first then try the rest of the match, which since the next group is optional it will never get matched. Some regex flavors have a reluctant quantifier which will try matching the least amount of characters.– Torin
2 days ago
.* is greedy, meaning it will match the whole string first then try the rest of the match, which since the next group is optional it will never get matched. Some regex flavors have a reluctant quantifier which will try matching the least amount of characters.– Torin
2 days ago
add a comment |
2 Answers
2
active
oldest
votes
Another one:
$ echo -e "abcdnabcd," | sed 's/.*($|,)/efgh1/'
efgh
efgh,
This matches the end of the line $ or the comma , in the captured group.
answered 2 days ago
FreddyFreddy
1,612210
Thank you so much! That's exactly what I was looking for. I totally forgot that capturing group may have more than 1 character! I hope this solution will save time for somebody else in the future as well.
– Shimon Pozin
2 days ago
add a comment |
I believe you are referring to something like:
's/[a-z]+([^a-z]0,1)$/efgh1/g'
Complete sed commands + output:
$ echo "abcd," | sed 's/[a-z]+([^a-z]0,1)$/efgh1/g'
efgh,
$ echo "abcd" | sed 's/[a-z]+([^a-z]0,1)$/efgh1/g'
efgh
answered 2 days ago
PMartPMart
1
New contributor
PMart is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
I think this works for specific example I gave, but I am not sure about arbitrary line (i search for specific pattern in the line, but then replace it entirely, preserving only comma at the end of the line) So, if I read it correct, we capture end of line that is not a letter and appears 0 or 1 times, right? But if it's a period, it will preserve it too? I only need to preserve it if it's comma. If it's ending of json statement, for example ("xxx}") I don't want to preserve the last character. But if it's "xxx}," then I do want to transfer comma into replacement. Sorry if I was not clear.
– Shimon Pozin
2 days ago
@ShimonPozin You are correct in your comment here. You could change[^a-z]to just,in the given regular expression (and delete thegat the end as the substitution would by necessity only match once ever).
– Kusalananda♦
yesterday
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
Another one:
$ echo -e "abcdnabcd," | sed 's/.*($|,)/efgh1/'
efgh
efgh,
This matches the end of the line $ or the comma , in the captured group.
answered 2 days ago
FreddyFreddy
1,612210
Thank you so much! That's exactly what I was looking for. I totally forgot that capturing group may have more than 1 character! I hope this solution will save time for somebody else in the future as well.
– Shimon Pozin
2 days ago
add a comment |
Another one:
$ echo -e "abcdnabcd," | sed 's/.*($|,)/efgh1/'
efgh
efgh,
This matches the end of the line $ or the comma , in the captured group.
answered 2 days ago
FreddyFreddy
1,612210
Thank you so much! That's exactly what I was looking for. I totally forgot that capturing group may have more than 1 character! I hope this solution will save time for somebody else in the future as well.
– Shimon Pozin
2 days ago
add a comment |
Another one:
$ echo -e "abcdnabcd," | sed 's/.*($|,)/efgh1/'
efgh
efgh,
This matches the end of the line $ or the comma , in the captured group.
answered 2 days ago
FreddyFreddy
1,612210
Another one:
$ echo -e "abcdnabcd," | sed 's/.*($|,)/efgh1/'
efgh
efgh,
This matches the end of the line $ or the comma , in the captured group.
answered 2 days ago
FreddyFreddy
1,612210
edited 2 days ago
answered 2 days ago
FreddyFreddy
1,612210
answered 2 days ago
FreddyFreddy
1,612210
answered 2 days ago
FreddyFreddy
1,612210
1,612210
Thank you so much! That's exactly what I was looking for. I totally forgot that capturing group may have more than 1 character! I hope this solution will save time for somebody else in the future as well.
– Shimon Pozin
2 days ago
add a comment |
Thank you so much! That's exactly what I was looking for. I totally forgot that capturing group may have more than 1 character! I hope this solution will save time for somebody else in the future as well.
– Shimon Pozin
2 days ago
Thank you so much! That's exactly what I was looking for. I totally forgot that capturing group may have more than 1 character! I hope this solution will save time for somebody else in the future as well.
– Shimon Pozin
2 days ago
Thank you so much! That's exactly what I was looking for. I totally forgot that capturing group may have more than 1 character! I hope this solution will save time for somebody else in the future as well.
– Shimon Pozin
2 days ago
add a comment |
I believe you are referring to something like:
's/[a-z]+([^a-z]0,1)$/efgh1/g'
Complete sed commands + output:
$ echo "abcd," | sed 's/[a-z]+([^a-z]0,1)$/efgh1/g'
efgh,
$ echo "abcd" | sed 's/[a-z]+([^a-z]0,1)$/efgh1/g'
efgh
answered 2 days ago
PMartPMart
1
New contributor
PMart is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
I think this works for specific example I gave, but I am not sure about arbitrary line (i search for specific pattern in the line, but then replace it entirely, preserving only comma at the end of the line) So, if I read it correct, we capture end of line that is not a letter and appears 0 or 1 times, right? But if it's a period, it will preserve it too? I only need to preserve it if it's comma. If it's ending of json statement, for example ("xxx}") I don't want to preserve the last character. But if it's "xxx}," then I do want to transfer comma into replacement. Sorry if I was not clear.
– Shimon Pozin
2 days ago
@ShimonPozin You are correct in your comment here. You could change[^a-z]to just,in the given regular expression (and delete thegat the end as the substitution would by necessity only match once ever).
– Kusalananda♦
yesterday
add a comment |
I believe you are referring to something like:
's/[a-z]+([^a-z]0,1)$/efgh1/g'
Complete sed commands + output:
$ echo "abcd," | sed 's/[a-z]+([^a-z]0,1)$/efgh1/g'
efgh,
$ echo "abcd" | sed 's/[a-z]+([^a-z]0,1)$/efgh1/g'
efgh
answered 2 days ago
PMartPMart
1
New contributor
PMart is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
I think this works for specific example I gave, but I am not sure about arbitrary line (i search for specific pattern in the line, but then replace it entirely, preserving only comma at the end of the line) So, if I read it correct, we capture end of line that is not a letter and appears 0 or 1 times, right? But if it's a period, it will preserve it too? I only need to preserve it if it's comma. If it's ending of json statement, for example ("xxx}") I don't want to preserve the last character. But if it's "xxx}," then I do want to transfer comma into replacement. Sorry if I was not clear.
– Shimon Pozin
2 days ago
@ShimonPozin You are correct in your comment here. You could change[^a-z]to just,in the given regular expression (and delete thegat the end as the substitution would by necessity only match once ever).
– Kusalananda♦
yesterday
add a comment |
I believe you are referring to something like:
's/[a-z]+([^a-z]0,1)$/efgh1/g'
Complete sed commands + output:
$ echo "abcd," | sed 's/[a-z]+([^a-z]0,1)$/efgh1/g'
efgh,
$ echo "abcd" | sed 's/[a-z]+([^a-z]0,1)$/efgh1/g'
efgh
answered 2 days ago
PMartPMart
1
New contributor
PMart is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
I believe you are referring to something like:
's/[a-z]+([^a-z]0,1)$/efgh1/g'
Complete sed commands + output:
$ echo "abcd," | sed 's/[a-z]+([^a-z]0,1)$/efgh1/g'
efgh,
$ echo "abcd" | sed 's/[a-z]+([^a-z]0,1)$/efgh1/g'
efgh
answered 2 days ago
PMartPMart
1
New contributor
PMart is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered 2 days ago
PMartPMart
1
New contributor
PMart is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered 2 days ago
PMartPMart
1
answered 2 days ago
PMartPMart
1
1
New contributor
PMart is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
PMart is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
PMart is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
I think this works for specific example I gave, but I am not sure about arbitrary line (i search for specific pattern in the line, but then replace it entirely, preserving only comma at the end of the line) So, if I read it correct, we capture end of line that is not a letter and appears 0 or 1 times, right? But if it's a period, it will preserve it too? I only need to preserve it if it's comma. If it's ending of json statement, for example ("xxx}") I don't want to preserve the last character. But if it's "xxx}," then I do want to transfer comma into replacement. Sorry if I was not clear.
– Shimon Pozin
2 days ago
@ShimonPozin You are correct in your comment here. You could change[^a-z]to just,in the given regular expression (and delete thegat the end as the substitution would by necessity only match once ever).
– Kusalananda♦
yesterday
add a comment |
I think this works for specific example I gave, but I am not sure about arbitrary line (i search for specific pattern in the line, but then replace it entirely, preserving only comma at the end of the line) So, if I read it correct, we capture end of line that is not a letter and appears 0 or 1 times, right? But if it's a period, it will preserve it too? I only need to preserve it if it's comma. If it's ending of json statement, for example ("xxx}") I don't want to preserve the last character. But if it's "xxx}," then I do want to transfer comma into replacement. Sorry if I was not clear.
– Shimon Pozin
2 days ago
@ShimonPozin You are correct in your comment here. You could change[^a-z]to just,in the given regular expression (and delete thegat the end as the substitution would by necessity only match once ever).
– Kusalananda♦
yesterday
I think this works for specific example I gave, but I am not sure about arbitrary line (i search for specific pattern in the line, but then replace it entirely, preserving only comma at the end of the line) So, if I read it correct, we capture end of line that is not a letter and appears 0 or 1 times, right? But if it's a period, it will preserve it too? I only need to preserve it if it's comma. If it's ending of json statement, for example ("xxx}") I don't want to preserve the last character. But if it's "xxx}," then I do want to transfer comma into replacement. Sorry if I was not clear.
– Shimon Pozin
2 days ago
I think this works for specific example I gave, but I am not sure about arbitrary line (i search for specific pattern in the line, but then replace it entirely, preserving only comma at the end of the line) So, if I read it correct, we capture end of line that is not a letter and appears 0 or 1 times, right? But if it's a period, it will preserve it too? I only need to preserve it if it's comma. If it's ending of json statement, for example ("xxx}") I don't want to preserve the last character. But if it's "xxx}," then I do want to transfer comma into replacement. Sorry if I was not clear.
– Shimon Pozin
2 days ago
@ShimonPozin You are correct in your comment here. You could change
[^a-z] to just , in the given regular expression (and delete the g at the end as the substitution would by necessity only match once ever).– Kusalananda♦
yesterday
@ShimonPozin You are correct in your comment here. You could change
[^a-z] to just , in the given regular expression (and delete the g at the end as the substitution would by necessity only match once ever).– Kusalananda♦
yesterday
add a comment |
Shimon Pozin is a new contributor. Be nice, and check out our Code of Conduct.
Shimon Pozin is a new contributor. Be nice, and check out our Code of Conduct.
Shimon Pozin is a new contributor. Be nice, and check out our Code of Conduct.
Shimon Pozin is a new contributor. Be nice, and check out our Code of Conduct.
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-regular-expression
1
Any length lines? Always
abcd? Always a comma? How do we tell whether or not the last character should be kept?– roaima
2 days ago
What tool are you using to apply the RE? Different tools use different variants (unfortunately).
– roaima
2 days ago
.*is greedy, meaning it will match the whole string first then try the rest of the match, which since the next group is optional it will never get matched. Some regex flavors have a reluctant quantifier which will try matching the least amount of characters.– Torin
2 days ago