Truth table with logical gates for a traffic light Announcing the arrival of Valued Associate #679: Cesar Manara Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)Writing down logic of a circuitCreate a CMOS circuit from a logic functionSR Latch/Racing?What operation does this circuit perform?Output of XOR gate with high-impedance inputLogic Gates - Did I connect them correctly?NAND Gate Logic OptimizationBit counter using basic logic gatesBuild Truth Table given CircuitCreate a circuit with max 6 NAND gates

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Truth table with logical gates for a traffic light



Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)Writing down logic of a circuitCreate a CMOS circuit from a logic functionSR Latch/Racing?What operation does this circuit perform?Output of XOR gate with high-impedance inputLogic Gates - Did I connect them correctly?NAND Gate Logic OptimizationBit counter using basic logic gatesBuild Truth Table given CircuitCreate a circuit with max 6 NAND gates



.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








3












$begingroup$


I want to create this truth table:
truth table



So I tried this but I was not able to get the last row, which is:
While a =1 and b =1 ,yellow = 1 red = 0 and green = 0.

This is my design for it, but I could not make the last row.



enter image description here



Does anyone have a sample or a tip about what I can do to fix this?

Thanks!






logic-gates simulink







share|improve this question









New contributor




John wiliam is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$











  • $begingroup$
    I remember doing a traffic light problem like this in one of my school labs.
    $endgroup$
    – user4574
    11 hours ago










  • $begingroup$
    @user4574 yep it is one of my assignments
    $endgroup$
    – John wiliam
    6 hours ago

















3












$begingroup$


I want to create this truth table:
truth table



So I tried this but I was not able to get the last row, which is:
While a =1 and b =1 ,yellow = 1 red = 0 and green = 0.

This is my design for it, but I could not make the last row.



enter image description here



Does anyone have a sample or a tip about what I can do to fix this?

Thanks!






logic-gates simulink







share|improve this question









New contributor




John wiliam is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$











  • $begingroup$
    I remember doing a traffic light problem like this in one of my school labs.
    $endgroup$
    – user4574
    11 hours ago










  • $begingroup$
    @user4574 yep it is one of my assignments
    $endgroup$
    – John wiliam
    6 hours ago













3












3








3





$begingroup$


I want to create this truth table:
truth table



So I tried this but I was not able to get the last row, which is:
While a =1 and b =1 ,yellow = 1 red = 0 and green = 0.

This is my design for it, but I could not make the last row.



enter image description here



Does anyone have a sample or a tip about what I can do to fix this?

Thanks!






logic-gates simulink







share|improve this question









New contributor




John wiliam is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$




I want to create this truth table:
truth table



So I tried this but I was not able to get the last row, which is:
While a =1 and b =1 ,yellow = 1 red = 0 and green = 0.

This is my design for it, but I could not make the last row.



enter image description here



Does anyone have a sample or a tip about what I can do to fix this?

Thanks!






logic-gates simulink




logic-gates simulink






share|improve this question









New contributor




John wiliam is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|improve this question









New contributor




John wiliam is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|improve this question




share|improve this question








edited 13 hours ago









Niteesh Shanbog

513416




513416






New contributor




John wiliam is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









asked 13 hours ago









John wiliamJohn wiliam

163




163




New contributor




John wiliam is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





New contributor





John wiliam is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






John wiliam is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











  • $begingroup$
    I remember doing a traffic light problem like this in one of my school labs.
    $endgroup$
    – user4574
    11 hours ago










  • $begingroup$
    @user4574 yep it is one of my assignments
    $endgroup$
    – John wiliam
    6 hours ago
















  • $begingroup$
    I remember doing a traffic light problem like this in one of my school labs.
    $endgroup$
    – user4574
    11 hours ago










  • $begingroup$
    @user4574 yep it is one of my assignments
    $endgroup$
    – John wiliam
    6 hours ago















$begingroup$
I remember doing a traffic light problem like this in one of my school labs.
$endgroup$
– user4574
11 hours ago




$begingroup$
I remember doing a traffic light problem like this in one of my school labs.
$endgroup$
– user4574
11 hours ago












$begingroup$
@user4574 yep it is one of my assignments
$endgroup$
– John wiliam
6 hours ago




$begingroup$
@user4574 yep it is one of my assignments
$endgroup$
– John wiliam
6 hours ago










3 Answers
3






active

oldest

votes


















2












$begingroup$

You can write the equations easily from the truth table



$$Red = bar A $$
$$Yellow = B$$
$$Green = A land bar B$$



They can be built the following circuit:
enter image description here






share|improve this answer









$endgroup$








  • 1




    $begingroup$
    thanks for the picture :)
    $endgroup$
    – John wiliam
    13 hours ago


















2












$begingroup$

YELLOW = $B$.



RED = $bar A$.



GREEN = $overline RED + YELLOW$



enter image description here



Purple is the implied logic for the red light, orange is the implied logic for the yellow light and green is for the green light.



One OR gate and two inverters would do the trick.






share|improve this answer











$endgroup$












  • $begingroup$
    thanks i do not know know much about the gates i i were trying too much things thanks for helping :) i solve it
    $endgroup$
    – John wiliam
    13 hours ago



















2












$begingroup$

I do have a tip for you!



Work column by column, not row by row. First, create a circuit for the red light, ignoring the other two lights. Next, do the same for the yellow light. Finally, do the same for the green light. After you've created these three circuits, you can simply combine them into one.






share|improve this answer









$endgroup$












  • $begingroup$
    thanks for the advice :)
    $endgroup$
    – John wiliam
    6 hours ago











Your Answer






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StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2felectronics.stackexchange.com%2fquestions%2f432631%2ftruth-table-with-logical-gates-for-a-traffic-light%23new-answer', 'question_page');

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3 Answers
3






active

oldest

votes








3 Answers
3






active

oldest

votes









active

oldest

votes






active

oldest

votes









2












$begingroup$

You can write the equations easily from the truth table



$$Red = bar A $$
$$Yellow = B$$
$$Green = A land bar B$$



They can be built the following circuit:
enter image description here






share|improve this answer









$endgroup$








  • 1




    $begingroup$
    thanks for the picture :)
    $endgroup$
    – John wiliam
    13 hours ago















2












$begingroup$

You can write the equations easily from the truth table



$$Red = bar A $$
$$Yellow = B$$
$$Green = A land bar B$$



They can be built the following circuit:
enter image description here






share|improve this answer









$endgroup$








  • 1




    $begingroup$
    thanks for the picture :)
    $endgroup$
    – John wiliam
    13 hours ago













2












2








2





$begingroup$

You can write the equations easily from the truth table



$$Red = bar A $$
$$Yellow = B$$
$$Green = A land bar B$$



They can be built the following circuit:
enter image description here






share|improve this answer









$endgroup$



You can write the equations easily from the truth table



$$Red = bar A $$
$$Yellow = B$$
$$Green = A land bar B$$



They can be built the following circuit:
enter image description here







share|improve this answer












share|improve this answer



share|improve this answer










answered 13 hours ago









RenanRenan

4,35022244




4,35022244







  • 1




    $begingroup$
    thanks for the picture :)
    $endgroup$
    – John wiliam
    13 hours ago












  • 1




    $begingroup$
    thanks for the picture :)
    $endgroup$
    – John wiliam
    13 hours ago







1




1




$begingroup$
thanks for the picture :)
$endgroup$
– John wiliam
13 hours ago




$begingroup$
thanks for the picture :)
$endgroup$
– John wiliam
13 hours ago













2












$begingroup$

YELLOW = $B$.



RED = $bar A$.



GREEN = $overline RED + YELLOW$



enter image description here



Purple is the implied logic for the red light, orange is the implied logic for the yellow light and green is for the green light.



One OR gate and two inverters would do the trick.






share|improve this answer











$endgroup$












  • $begingroup$
    thanks i do not know know much about the gates i i were trying too much things thanks for helping :) i solve it
    $endgroup$
    – John wiliam
    13 hours ago
















2












$begingroup$

YELLOW = $B$.



RED = $bar A$.



GREEN = $overline RED + YELLOW$



enter image description here



Purple is the implied logic for the red light, orange is the implied logic for the yellow light and green is for the green light.



One OR gate and two inverters would do the trick.






share|improve this answer











$endgroup$












  • $begingroup$
    thanks i do not know know much about the gates i i were trying too much things thanks for helping :) i solve it
    $endgroup$
    – John wiliam
    13 hours ago














2












2








2





$begingroup$

YELLOW = $B$.



RED = $bar A$.



GREEN = $overline RED + YELLOW$



enter image description here



Purple is the implied logic for the red light, orange is the implied logic for the yellow light and green is for the green light.



One OR gate and two inverters would do the trick.






share|improve this answer











$endgroup$



YELLOW = $B$.



RED = $bar A$.



GREEN = $overline RED + YELLOW$



enter image description here



Purple is the implied logic for the red light, orange is the implied logic for the yellow light and green is for the green light.



One OR gate and two inverters would do the trick.







share|improve this answer














share|improve this answer



share|improve this answer








edited 12 hours ago

























answered 13 hours ago









Andy akaAndy aka

244k11186425




244k11186425











  • $begingroup$
    thanks i do not know know much about the gates i i were trying too much things thanks for helping :) i solve it
    $endgroup$
    – John wiliam
    13 hours ago

















  • $begingroup$
    thanks i do not know know much about the gates i i were trying too much things thanks for helping :) i solve it
    $endgroup$
    – John wiliam
    13 hours ago
















$begingroup$
thanks i do not know know much about the gates i i were trying too much things thanks for helping :) i solve it
$endgroup$
– John wiliam
13 hours ago





$begingroup$
thanks i do not know know much about the gates i i were trying too much things thanks for helping :) i solve it
$endgroup$
– John wiliam
13 hours ago












2












$begingroup$

I do have a tip for you!



Work column by column, not row by row. First, create a circuit for the red light, ignoring the other two lights. Next, do the same for the yellow light. Finally, do the same for the green light. After you've created these three circuits, you can simply combine them into one.






share|improve this answer









$endgroup$












  • $begingroup$
    thanks for the advice :)
    $endgroup$
    – John wiliam
    6 hours ago















2












$begingroup$

I do have a tip for you!



Work column by column, not row by row. First, create a circuit for the red light, ignoring the other two lights. Next, do the same for the yellow light. Finally, do the same for the green light. After you've created these three circuits, you can simply combine them into one.






share|improve this answer









$endgroup$












  • $begingroup$
    thanks for the advice :)
    $endgroup$
    – John wiliam
    6 hours ago













2












2








2





$begingroup$

I do have a tip for you!



Work column by column, not row by row. First, create a circuit for the red light, ignoring the other two lights. Next, do the same for the yellow light. Finally, do the same for the green light. After you've created these three circuits, you can simply combine them into one.






share|improve this answer









$endgroup$



I do have a tip for you!



Work column by column, not row by row. First, create a circuit for the red light, ignoring the other two lights. Next, do the same for the yellow light. Finally, do the same for the green light. After you've created these three circuits, you can simply combine them into one.







share|improve this answer












share|improve this answer



share|improve this answer










answered 10 hours ago









Tanner SwettTanner Swett

42437




42437











  • $begingroup$
    thanks for the advice :)
    $endgroup$
    – John wiliam
    6 hours ago
















  • $begingroup$
    thanks for the advice :)
    $endgroup$
    – John wiliam
    6 hours ago















$begingroup$
thanks for the advice :)
$endgroup$
– John wiliam
6 hours ago




$begingroup$
thanks for the advice :)
$endgroup$
– John wiliam
6 hours ago










John wiliam is a new contributor. Be nice, and check out our Code of Conduct.









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John wiliam is a new contributor. Be nice, and check out our Code of Conduct.












John wiliam is a new contributor. Be nice, and check out our Code of Conduct.











John wiliam is a new contributor. Be nice, and check out our Code of Conduct.














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