Bash script to loop through folders and list files to text Announcing the arrival of Valued Associate #679: Cesar Manara Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern) 2019 Community Moderator Election Results Why I closed the “Why is Kali so hard” questionSecurity implications of forgetting to quote a variable in bash/POSIX shellsUsing globbing/wildcards when Opening Files from TerminalMove files to multiple foldersUsing find and sed to copy 20th line of many files into one fileLoop in text files shell scriptFolder research taskGo through every subfolder, check for a folder and run scriptBash script to monitor file change and execute commandMoving files into folders using bash scriptCopying and pasting specific file types in folders and subfoldersHow to recursively copy only the files from folders and subfolders?

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Bash script to loop through folders and list files to text



Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)
2019 Community Moderator Election Results
Why I closed the “Why is Kali so hard” questionSecurity implications of forgetting to quote a variable in bash/POSIX shellsUsing globbing/wildcards when Opening Files from TerminalMove files to multiple foldersUsing find and sed to copy 20th line of many files into one fileLoop in text files shell scriptFolder research taskGo through every subfolder, check for a folder and run scriptBash script to monitor file change and execute commandMoving files into folders using bash scriptCopying and pasting specific file types in folders and subfoldersHow to recursively copy only the files from folders and subfolders?



.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








1















I can do this in Windows CMD scripting but now I am getting into Debian via Raspberry Pi.



What I'd like to do is...



(In current folder)



  • For each subfolder...

    • Create a file called original_filenames.txt

    • Echo the name of the folder into this original_filenames.txt

    • List all files (including any subfolders) to original_filenames.txt










share|improve this question



















  • 1





    What are you having an issue doing? Please include the script you are attempting to use in your question and any errors you are encountering.

    – kemotep
    May 30 '18 at 18:28











  • Do you want to descend into subfolders and list those files?

    – glenn jackman
    May 30 '18 at 18:57











  • Yes I want to recurse through subfolders. I think I've got something working now, I was getting an error until I added quotes to deal with spaces in folder names:#!/bin/bash; for dir in */ ; do ; tree -s "$dir">"$dir/original_filenames.txt"; done

    – Murgatroyd
    May 30 '18 at 19:24












  • That's a good lesson. You'll want to read Security implications of forgetting to quote a variable in bash/POSIX shells

    – glenn jackman
    May 30 '18 at 19:27

















1















I can do this in Windows CMD scripting but now I am getting into Debian via Raspberry Pi.



What I'd like to do is...



(In current folder)



  • For each subfolder...

    • Create a file called original_filenames.txt

    • Echo the name of the folder into this original_filenames.txt

    • List all files (including any subfolders) to original_filenames.txt










share|improve this question



















  • 1





    What are you having an issue doing? Please include the script you are attempting to use in your question and any errors you are encountering.

    – kemotep
    May 30 '18 at 18:28











  • Do you want to descend into subfolders and list those files?

    – glenn jackman
    May 30 '18 at 18:57











  • Yes I want to recurse through subfolders. I think I've got something working now, I was getting an error until I added quotes to deal with spaces in folder names:#!/bin/bash; for dir in */ ; do ; tree -s "$dir">"$dir/original_filenames.txt"; done

    – Murgatroyd
    May 30 '18 at 19:24












  • That's a good lesson. You'll want to read Security implications of forgetting to quote a variable in bash/POSIX shells

    – glenn jackman
    May 30 '18 at 19:27













1












1








1








I can do this in Windows CMD scripting but now I am getting into Debian via Raspberry Pi.



What I'd like to do is...



(In current folder)



  • For each subfolder...

    • Create a file called original_filenames.txt

    • Echo the name of the folder into this original_filenames.txt

    • List all files (including any subfolders) to original_filenames.txt










share|improve this question
















I can do this in Windows CMD scripting but now I am getting into Debian via Raspberry Pi.



What I'd like to do is...



(In current folder)



  • For each subfolder...

    • Create a file called original_filenames.txt

    • Echo the name of the folder into this original_filenames.txt

    • List all files (including any subfolders) to original_filenames.txt







bash shell-script






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 11 hours ago









Rui F Ribeiro

42.1k1483142




42.1k1483142










asked May 30 '18 at 18:23









MurgatroydMurgatroyd

62




62







  • 1





    What are you having an issue doing? Please include the script you are attempting to use in your question and any errors you are encountering.

    – kemotep
    May 30 '18 at 18:28











  • Do you want to descend into subfolders and list those files?

    – glenn jackman
    May 30 '18 at 18:57











  • Yes I want to recurse through subfolders. I think I've got something working now, I was getting an error until I added quotes to deal with spaces in folder names:#!/bin/bash; for dir in */ ; do ; tree -s "$dir">"$dir/original_filenames.txt"; done

    – Murgatroyd
    May 30 '18 at 19:24












  • That's a good lesson. You'll want to read Security implications of forgetting to quote a variable in bash/POSIX shells

    – glenn jackman
    May 30 '18 at 19:27












  • 1





    What are you having an issue doing? Please include the script you are attempting to use in your question and any errors you are encountering.

    – kemotep
    May 30 '18 at 18:28











  • Do you want to descend into subfolders and list those files?

    – glenn jackman
    May 30 '18 at 18:57











  • Yes I want to recurse through subfolders. I think I've got something working now, I was getting an error until I added quotes to deal with spaces in folder names:#!/bin/bash; for dir in */ ; do ; tree -s "$dir">"$dir/original_filenames.txt"; done

    – Murgatroyd
    May 30 '18 at 19:24












  • That's a good lesson. You'll want to read Security implications of forgetting to quote a variable in bash/POSIX shells

    – glenn jackman
    May 30 '18 at 19:27







1




1





What are you having an issue doing? Please include the script you are attempting to use in your question and any errors you are encountering.

– kemotep
May 30 '18 at 18:28





What are you having an issue doing? Please include the script you are attempting to use in your question and any errors you are encountering.

– kemotep
May 30 '18 at 18:28













Do you want to descend into subfolders and list those files?

– glenn jackman
May 30 '18 at 18:57





Do you want to descend into subfolders and list those files?

– glenn jackman
May 30 '18 at 18:57













Yes I want to recurse through subfolders. I think I've got something working now, I was getting an error until I added quotes to deal with spaces in folder names:#!/bin/bash; for dir in */ ; do ; tree -s "$dir">"$dir/original_filenames.txt"; done

– Murgatroyd
May 30 '18 at 19:24






Yes I want to recurse through subfolders. I think I've got something working now, I was getting an error until I added quotes to deal with spaces in folder names:#!/bin/bash; for dir in */ ; do ; tree -s "$dir">"$dir/original_filenames.txt"; done

– Murgatroyd
May 30 '18 at 19:24














That's a good lesson. You'll want to read Security implications of forgetting to quote a variable in bash/POSIX shells

– glenn jackman
May 30 '18 at 19:27





That's a good lesson. You'll want to read Security implications of forgetting to quote a variable in bash/POSIX shells

– glenn jackman
May 30 '18 at 19:27










2 Answers
2






active

oldest

votes


















1














Using a shell loop:



for dir in */; do
printf '%sn' "$dir"
( cd "$dir" && find . )
>"$dir/original_filenames.txt"
done


This iterates over all subdirectories in the current directory. The body of the loop outputs the name of the directory, and then a list of all files and directories, recursively, in that directory. This output goes to the original_filenames.txt file in the directory.



Shorter:



for dir in */; do
find "$dir" >"$dir/original_filenames.txt"
done


This gives slightly different output in that the pathnames that are written to the file all start with the name of the subfolder.



If you're uninterested in directory names and just want pathnames of the regular files, use find with -type f after the directory name.




Note that if you're planning on using the generate output files for anything, then this will fail (or at least be very problematic) if any of the found pathnames contain newlines (which is entirely possible on a Unix system).






share|improve this answer
































    0














    You could do this with the find command and the exec option - something like this:



    find . -type d ( ! -name . ) -exec bash -c '
    dirname=$(basename "") &&
    cd "" &&
    echo "" > original_filenames.txt &&
    ls | grep -Fv original_filenames.txt >> original_filenames.txt
    ' ;


    Here's a StackOverflow post you might find useful:



    • How to go to each directory and execute a command?





    share|improve this answer




















    • 1





      For readability, you can have newlines in a single quoted string, and && at the end of a line does not require a line continuation.

      – glenn jackman
      May 30 '18 at 19:02






    • 1





      Instead of putting in the middle of the shell script, you may want to pass it as an argument and use "$1" inside the shell script, to avoid issues with strange filenames. Also, I can't see what dirname is used for here, and you don't need ( ) around ! -name ..

      – ilkkachu
      May 30 '18 at 19:15











    • @ilkkachu Thanks for the comment. The unused dirname was a typo/mistake on my part. I'm now using it to add just the filename to the output file. The ! -name . was to ignore the current directory (i.e. to only apply the commands to proper subdirectories) - I removed it.

      – igal
      May 30 '18 at 19:21












    • @glennjackman Thanks for the comment. I've update my post as you suggested.

      – igal
      May 30 '18 at 19:22






    • 1





      @igal, I added a version I think is readable. If you don't like, please edit it out.

      – glenn jackman
      May 30 '18 at 19:24











    Your Answer








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    2 Answers
    2






    active

    oldest

    votes








    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    1














    Using a shell loop:



    for dir in */; do
    printf '%sn' "$dir"
    ( cd "$dir" && find . )
    >"$dir/original_filenames.txt"
    done


    This iterates over all subdirectories in the current directory. The body of the loop outputs the name of the directory, and then a list of all files and directories, recursively, in that directory. This output goes to the original_filenames.txt file in the directory.



    Shorter:



    for dir in */; do
    find "$dir" >"$dir/original_filenames.txt"
    done


    This gives slightly different output in that the pathnames that are written to the file all start with the name of the subfolder.



    If you're uninterested in directory names and just want pathnames of the regular files, use find with -type f after the directory name.




    Note that if you're planning on using the generate output files for anything, then this will fail (or at least be very problematic) if any of the found pathnames contain newlines (which is entirely possible on a Unix system).






    share|improve this answer





























      1














      Using a shell loop:



      for dir in */; do
      printf '%sn' "$dir"
      ( cd "$dir" && find . )
      >"$dir/original_filenames.txt"
      done


      This iterates over all subdirectories in the current directory. The body of the loop outputs the name of the directory, and then a list of all files and directories, recursively, in that directory. This output goes to the original_filenames.txt file in the directory.



      Shorter:



      for dir in */; do
      find "$dir" >"$dir/original_filenames.txt"
      done


      This gives slightly different output in that the pathnames that are written to the file all start with the name of the subfolder.



      If you're uninterested in directory names and just want pathnames of the regular files, use find with -type f after the directory name.




      Note that if you're planning on using the generate output files for anything, then this will fail (or at least be very problematic) if any of the found pathnames contain newlines (which is entirely possible on a Unix system).






      share|improve this answer



























        1












        1








        1







        Using a shell loop:



        for dir in */; do
        printf '%sn' "$dir"
        ( cd "$dir" && find . )
        >"$dir/original_filenames.txt"
        done


        This iterates over all subdirectories in the current directory. The body of the loop outputs the name of the directory, and then a list of all files and directories, recursively, in that directory. This output goes to the original_filenames.txt file in the directory.



        Shorter:



        for dir in */; do
        find "$dir" >"$dir/original_filenames.txt"
        done


        This gives slightly different output in that the pathnames that are written to the file all start with the name of the subfolder.



        If you're uninterested in directory names and just want pathnames of the regular files, use find with -type f after the directory name.




        Note that if you're planning on using the generate output files for anything, then this will fail (or at least be very problematic) if any of the found pathnames contain newlines (which is entirely possible on a Unix system).






        share|improve this answer















        Using a shell loop:



        for dir in */; do
        printf '%sn' "$dir"
        ( cd "$dir" && find . )
        >"$dir/original_filenames.txt"
        done


        This iterates over all subdirectories in the current directory. The body of the loop outputs the name of the directory, and then a list of all files and directories, recursively, in that directory. This output goes to the original_filenames.txt file in the directory.



        Shorter:



        for dir in */; do
        find "$dir" >"$dir/original_filenames.txt"
        done


        This gives slightly different output in that the pathnames that are written to the file all start with the name of the subfolder.



        If you're uninterested in directory names and just want pathnames of the regular files, use find with -type f after the directory name.




        Note that if you're planning on using the generate output files for anything, then this will fail (or at least be very problematic) if any of the found pathnames contain newlines (which is entirely possible on a Unix system).







        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited May 30 '18 at 19:32

























        answered May 30 '18 at 19:27









        KusalanandaKusalananda

        142k18265440




        142k18265440























            0














            You could do this with the find command and the exec option - something like this:



            find . -type d ( ! -name . ) -exec bash -c '
            dirname=$(basename "") &&
            cd "" &&
            echo "" > original_filenames.txt &&
            ls | grep -Fv original_filenames.txt >> original_filenames.txt
            ' ;


            Here's a StackOverflow post you might find useful:



            • How to go to each directory and execute a command?





            share|improve this answer




















            • 1





              For readability, you can have newlines in a single quoted string, and && at the end of a line does not require a line continuation.

              – glenn jackman
              May 30 '18 at 19:02






            • 1





              Instead of putting in the middle of the shell script, you may want to pass it as an argument and use "$1" inside the shell script, to avoid issues with strange filenames. Also, I can't see what dirname is used for here, and you don't need ( ) around ! -name ..

              – ilkkachu
              May 30 '18 at 19:15











            • @ilkkachu Thanks for the comment. The unused dirname was a typo/mistake on my part. I'm now using it to add just the filename to the output file. The ! -name . was to ignore the current directory (i.e. to only apply the commands to proper subdirectories) - I removed it.

              – igal
              May 30 '18 at 19:21












            • @glennjackman Thanks for the comment. I've update my post as you suggested.

              – igal
              May 30 '18 at 19:22






            • 1





              @igal, I added a version I think is readable. If you don't like, please edit it out.

              – glenn jackman
              May 30 '18 at 19:24















            0














            You could do this with the find command and the exec option - something like this:



            find . -type d ( ! -name . ) -exec bash -c '
            dirname=$(basename "") &&
            cd "" &&
            echo "" > original_filenames.txt &&
            ls | grep -Fv original_filenames.txt >> original_filenames.txt
            ' ;


            Here's a StackOverflow post you might find useful:



            • How to go to each directory and execute a command?





            share|improve this answer




















            • 1





              For readability, you can have newlines in a single quoted string, and && at the end of a line does not require a line continuation.

              – glenn jackman
              May 30 '18 at 19:02






            • 1





              Instead of putting in the middle of the shell script, you may want to pass it as an argument and use "$1" inside the shell script, to avoid issues with strange filenames. Also, I can't see what dirname is used for here, and you don't need ( ) around ! -name ..

              – ilkkachu
              May 30 '18 at 19:15











            • @ilkkachu Thanks for the comment. The unused dirname was a typo/mistake on my part. I'm now using it to add just the filename to the output file. The ! -name . was to ignore the current directory (i.e. to only apply the commands to proper subdirectories) - I removed it.

              – igal
              May 30 '18 at 19:21












            • @glennjackman Thanks for the comment. I've update my post as you suggested.

              – igal
              May 30 '18 at 19:22






            • 1





              @igal, I added a version I think is readable. If you don't like, please edit it out.

              – glenn jackman
              May 30 '18 at 19:24













            0












            0








            0







            You could do this with the find command and the exec option - something like this:



            find . -type d ( ! -name . ) -exec bash -c '
            dirname=$(basename "") &&
            cd "" &&
            echo "" > original_filenames.txt &&
            ls | grep -Fv original_filenames.txt >> original_filenames.txt
            ' ;


            Here's a StackOverflow post you might find useful:



            • How to go to each directory and execute a command?





            share|improve this answer















            You could do this with the find command and the exec option - something like this:



            find . -type d ( ! -name . ) -exec bash -c '
            dirname=$(basename "") &&
            cd "" &&
            echo "" > original_filenames.txt &&
            ls | grep -Fv original_filenames.txt >> original_filenames.txt
            ' ;


            Here's a StackOverflow post you might find useful:



            • How to go to each directory and execute a command?






            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited May 30 '18 at 19:41

























            answered May 30 '18 at 18:54









            igaligal

            6,1511638




            6,1511638







            • 1





              For readability, you can have newlines in a single quoted string, and && at the end of a line does not require a line continuation.

              – glenn jackman
              May 30 '18 at 19:02






            • 1





              Instead of putting in the middle of the shell script, you may want to pass it as an argument and use "$1" inside the shell script, to avoid issues with strange filenames. Also, I can't see what dirname is used for here, and you don't need ( ) around ! -name ..

              – ilkkachu
              May 30 '18 at 19:15











            • @ilkkachu Thanks for the comment. The unused dirname was a typo/mistake on my part. I'm now using it to add just the filename to the output file. The ! -name . was to ignore the current directory (i.e. to only apply the commands to proper subdirectories) - I removed it.

              – igal
              May 30 '18 at 19:21












            • @glennjackman Thanks for the comment. I've update my post as you suggested.

              – igal
              May 30 '18 at 19:22






            • 1





              @igal, I added a version I think is readable. If you don't like, please edit it out.

              – glenn jackman
              May 30 '18 at 19:24












            • 1





              For readability, you can have newlines in a single quoted string, and && at the end of a line does not require a line continuation.

              – glenn jackman
              May 30 '18 at 19:02






            • 1





              Instead of putting in the middle of the shell script, you may want to pass it as an argument and use "$1" inside the shell script, to avoid issues with strange filenames. Also, I can't see what dirname is used for here, and you don't need ( ) around ! -name ..

              – ilkkachu
              May 30 '18 at 19:15











            • @ilkkachu Thanks for the comment. The unused dirname was a typo/mistake on my part. I'm now using it to add just the filename to the output file. The ! -name . was to ignore the current directory (i.e. to only apply the commands to proper subdirectories) - I removed it.

              – igal
              May 30 '18 at 19:21












            • @glennjackman Thanks for the comment. I've update my post as you suggested.

              – igal
              May 30 '18 at 19:22






            • 1





              @igal, I added a version I think is readable. If you don't like, please edit it out.

              – glenn jackman
              May 30 '18 at 19:24







            1




            1





            For readability, you can have newlines in a single quoted string, and && at the end of a line does not require a line continuation.

            – glenn jackman
            May 30 '18 at 19:02





            For readability, you can have newlines in a single quoted string, and && at the end of a line does not require a line continuation.

            – glenn jackman
            May 30 '18 at 19:02




            1




            1





            Instead of putting in the middle of the shell script, you may want to pass it as an argument and use "$1" inside the shell script, to avoid issues with strange filenames. Also, I can't see what dirname is used for here, and you don't need ( ) around ! -name ..

            – ilkkachu
            May 30 '18 at 19:15





            Instead of putting in the middle of the shell script, you may want to pass it as an argument and use "$1" inside the shell script, to avoid issues with strange filenames. Also, I can't see what dirname is used for here, and you don't need ( ) around ! -name ..

            – ilkkachu
            May 30 '18 at 19:15













            @ilkkachu Thanks for the comment. The unused dirname was a typo/mistake on my part. I'm now using it to add just the filename to the output file. The ! -name . was to ignore the current directory (i.e. to only apply the commands to proper subdirectories) - I removed it.

            – igal
            May 30 '18 at 19:21






            @ilkkachu Thanks for the comment. The unused dirname was a typo/mistake on my part. I'm now using it to add just the filename to the output file. The ! -name . was to ignore the current directory (i.e. to only apply the commands to proper subdirectories) - I removed it.

            – igal
            May 30 '18 at 19:21














            @glennjackman Thanks for the comment. I've update my post as you suggested.

            – igal
            May 30 '18 at 19:22





            @glennjackman Thanks for the comment. I've update my post as you suggested.

            – igal
            May 30 '18 at 19:22




            1




            1





            @igal, I added a version I think is readable. If you don't like, please edit it out.

            – glenn jackman
            May 30 '18 at 19:24





            @igal, I added a version I think is readable. If you don't like, please edit it out.

            – glenn jackman
            May 30 '18 at 19:24

















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