What is the highest possible scrabble score for placing a single tileLowest total scrabble scoreCraft the longest Scrabble sentenceScrabble ImpossibilitiesHighest possible score my friend could earn in one Scrabble turn?What is the longest word that can be made out of all the scrabble tiles?

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What is the highest possible scrabble score for placing a single tile


Lowest total scrabble scoreCraft the longest Scrabble sentenceScrabble ImpossibilitiesHighest possible score my friend could earn in one Scrabble turn?What is the longest word that can be made out of all the scrabble tiles?













21












$begingroup$


What is the highest possible score a player can make in a turn by placing a single tile? Assume language is English, using standard North American rules.










share|improve this question











$endgroup$











  • $begingroup$
    You might be interested in reading interested in reading some of the comments on this post: recordsetter.com/world-record/…
    $endgroup$
    – Matt
    Mar 21 at 18:24










  • $begingroup$
    Can we assume that the tiles already on the board are exactly as we want them?
    $endgroup$
    – Hugh
    Mar 21 at 18:30










  • $begingroup$
    @doppelgreener Norh should you - it's been fixed now ;-)
    $endgroup$
    – Rand al'Thor
    Mar 22 at 13:24










  • $begingroup$
    @Randal'Thor Many hanks!
    $endgroup$
    – doppelgreener
    Mar 22 at 13:26















21












$begingroup$


What is the highest possible score a player can make in a turn by placing a single tile? Assume language is English, using standard North American rules.










share|improve this question











$endgroup$











  • $begingroup$
    You might be interested in reading interested in reading some of the comments on this post: recordsetter.com/world-record/…
    $endgroup$
    – Matt
    Mar 21 at 18:24










  • $begingroup$
    Can we assume that the tiles already on the board are exactly as we want them?
    $endgroup$
    – Hugh
    Mar 21 at 18:30










  • $begingroup$
    @doppelgreener Norh should you - it's been fixed now ;-)
    $endgroup$
    – Rand al'Thor
    Mar 22 at 13:24










  • $begingroup$
    @Randal'Thor Many hanks!
    $endgroup$
    – doppelgreener
    Mar 22 at 13:26













21












21








21


2



$begingroup$


What is the highest possible score a player can make in a turn by placing a single tile? Assume language is English, using standard North American rules.










share|improve this question











$endgroup$




What is the highest possible score a player can make in a turn by placing a single tile? Assume language is English, using standard North American rules.







scrabble






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Mar 22 at 11:36









noedne

7,60212160




7,60212160










asked Mar 21 at 18:21









user3294068user3294068

5,7641629




5,7641629











  • $begingroup$
    You might be interested in reading interested in reading some of the comments on this post: recordsetter.com/world-record/…
    $endgroup$
    – Matt
    Mar 21 at 18:24










  • $begingroup$
    Can we assume that the tiles already on the board are exactly as we want them?
    $endgroup$
    – Hugh
    Mar 21 at 18:30










  • $begingroup$
    @doppelgreener Norh should you - it's been fixed now ;-)
    $endgroup$
    – Rand al'Thor
    Mar 22 at 13:24










  • $begingroup$
    @Randal'Thor Many hanks!
    $endgroup$
    – doppelgreener
    Mar 22 at 13:26
















  • $begingroup$
    You might be interested in reading interested in reading some of the comments on this post: recordsetter.com/world-record/…
    $endgroup$
    – Matt
    Mar 21 at 18:24










  • $begingroup$
    Can we assume that the tiles already on the board are exactly as we want them?
    $endgroup$
    – Hugh
    Mar 21 at 18:30










  • $begingroup$
    @doppelgreener Norh should you - it's been fixed now ;-)
    $endgroup$
    – Rand al'Thor
    Mar 22 at 13:24










  • $begingroup$
    @Randal'Thor Many hanks!
    $endgroup$
    – doppelgreener
    Mar 22 at 13:26















$begingroup$
You might be interested in reading interested in reading some of the comments on this post: recordsetter.com/world-record/…
$endgroup$
– Matt
Mar 21 at 18:24




$begingroup$
You might be interested in reading interested in reading some of the comments on this post: recordsetter.com/world-record/…
$endgroup$
– Matt
Mar 21 at 18:24












$begingroup$
Can we assume that the tiles already on the board are exactly as we want them?
$endgroup$
– Hugh
Mar 21 at 18:30




$begingroup$
Can we assume that the tiles already on the board are exactly as we want them?
$endgroup$
– Hugh
Mar 21 at 18:30












$begingroup$
@doppelgreener Norh should you - it's been fixed now ;-)
$endgroup$
– Rand al'Thor
Mar 22 at 13:24




$begingroup$
@doppelgreener Norh should you - it's been fixed now ;-)
$endgroup$
– Rand al'Thor
Mar 22 at 13:24












$begingroup$
@Randal'Thor Many hanks!
$endgroup$
– doppelgreener
Mar 22 at 13:26




$begingroup$
@Randal'Thor Many hanks!
$endgroup$
– doppelgreener
Mar 22 at 13:26










2 Answers
2






active

oldest

votes


















35












$begingroup$

According to this Quora question, the best you can do using the North American Scrabble dictionary is CRYPTO(Z)OOLOGY and QUART(Z), giving a total of 171 points. The setup should look something like this:



enter image description here



...However, that's not the best you can do. We're looking at the highest possible score.



The rules of Scrabble do not prevent players from playing invalid words. There are rules for challenging someone you think has played an invalid word, and if the challenge is correct, the play will be reversed. But if players decide not to challenge, the word remains.



So, with particularly cooperative (or particularly stupid) players, the best you can do...



enter image description here



...is 303 points.






share|improve this answer









$endgroup$








  • 6




    $begingroup$
    @Brandon_J Probably, but the latter option is not against the rules of the game, no matter what language you're playing in. If nothing else, it's worth including as an option.
    $endgroup$
    – Deusovi♦
    Mar 21 at 19:20






  • 6




    $begingroup$
    (Rubio changes PSE username to QJXKFFHZHVVWWYY)
    $endgroup$
    – Rubio♦
    Mar 21 at 19:55






  • 2




    $begingroup$
    why are the E's necessary in the 2nd example? Diagonal words don't count right?
    $endgroup$
    – Aequitas
    Mar 22 at 1:05






  • 6




    $begingroup$
    @Aequitas Because otherwise, the board would have 3 disconnected pieces prior to the move (which is not possible).
    $endgroup$
    – John Doe
    Mar 22 at 1:34






  • 19




    $begingroup$
    (If anyone is wondering, "oology" is the studying of bird eggs, nests and breeding behaviour.)
    $endgroup$
    – BruceWayne
    Mar 22 at 2:09



















19












$begingroup$

In N-Tile Scrabble Records (Word Ways, May 1983, p.80), Kyle Corbin gives the following, for 231 points. All words can be found in Webster's Third.



 A B C D E F G H I J K L M N O
1 # . . + . . . # . . . + . . Q 1
2 . = . . . * . . . * . . . = U 2
3 . . = . . . + . + . . . = . I 3
4 + . . = . . . + . . . = . . C 4
5 . . . . = . . . . . = . . . K 5
6 . * . . . * . . . * . . . * S 6
7 . . + . . . + . + . . . + . I 7
8 # . . + . . . S N O W B A L L 8
9 . . + . . . + . + . . . + . V 9
10 . * . . . * . . . * . . . * E 10
11 . . . . = . . . . . = . . . R 11
12 + . . = . . . + . . . = . . I 12
13 . . = . . . + . + . . . = . N 13
14 . = . . . * . . . * . . E R G 14
15 H Y D R O X Y B E N Z E N E # 15
A B C D E F G H I J K L M N O


An S tile is placed into the # in the bottom right corner where there is a 3× word bonus.



(HYDROXYBENZENE)S/(QUICKSILVERING)S for 231 points.






share|improve this answer











$endgroup$








  • 3




    $begingroup$
    That's pretty cool, but wouldn't work for tournament scrabble according to scrabble.merriam.com
    $endgroup$
    – James
    Mar 22 at 12:21






  • 1




    $begingroup$
    @James: As noted on the other answer, it will work if nobody challenges it. One problem historically with the OSPD3 was that it didn't include words that are longer than eight letters and are not formed by adding common prefix or suffix to a words of eight letters or less. As noted in the introduction, one would have to look in another dictionary to check the validity of a word like "petroleum", since "eum" is not a common suffix. Does the aformentioned dictionary claim to exhaustively list all valid words of all lengths up to 15, regardless of stem length?
    $endgroup$
    – supercat
    Mar 22 at 15:59










  • $begingroup$
    Hi @supercat: As far as I can tell, the dictionary I linked to exhaustively lists all "valid" words, where "valid" means "legal in tournament Scrabble". I also notice that there are some 15-letter words in that dictionary, including "cryptozoologist" and "cryptozoologies".
    $endgroup$
    – James
    Mar 22 at 17:10










  • $begingroup$
    @James: Unless things have changed, any played word that is not challenged is valid, and this is actually a significant aspect of strategy. Even if one would expect one's opponent to believe a word is probably invalid, one might expect the opponent to refrain from challenging in cases where the downside risk would be too great.
    $endgroup$
    – supercat
    Mar 22 at 17:34










  • $begingroup$
    @supercat: I totally agree with your last comment. I thought when you used the word "valid" in the last sentence of your first comment above, you meant "valid if challenged". After all, you discussed using a dictionary to "... check the validity of a word ...". Why would you use a dictionary if any combination of letters were valid.
    $endgroup$
    – James
    Mar 22 at 17:38











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2 Answers
2






active

oldest

votes








2 Answers
2






active

oldest

votes









active

oldest

votes






active

oldest

votes









35












$begingroup$

According to this Quora question, the best you can do using the North American Scrabble dictionary is CRYPTO(Z)OOLOGY and QUART(Z), giving a total of 171 points. The setup should look something like this:



enter image description here



...However, that's not the best you can do. We're looking at the highest possible score.



The rules of Scrabble do not prevent players from playing invalid words. There are rules for challenging someone you think has played an invalid word, and if the challenge is correct, the play will be reversed. But if players decide not to challenge, the word remains.



So, with particularly cooperative (or particularly stupid) players, the best you can do...



enter image description here



...is 303 points.






share|improve this answer









$endgroup$








  • 6




    $begingroup$
    @Brandon_J Probably, but the latter option is not against the rules of the game, no matter what language you're playing in. If nothing else, it's worth including as an option.
    $endgroup$
    – Deusovi♦
    Mar 21 at 19:20






  • 6




    $begingroup$
    (Rubio changes PSE username to QJXKFFHZHVVWWYY)
    $endgroup$
    – Rubio♦
    Mar 21 at 19:55






  • 2




    $begingroup$
    why are the E's necessary in the 2nd example? Diagonal words don't count right?
    $endgroup$
    – Aequitas
    Mar 22 at 1:05






  • 6




    $begingroup$
    @Aequitas Because otherwise, the board would have 3 disconnected pieces prior to the move (which is not possible).
    $endgroup$
    – John Doe
    Mar 22 at 1:34






  • 19




    $begingroup$
    (If anyone is wondering, "oology" is the studying of bird eggs, nests and breeding behaviour.)
    $endgroup$
    – BruceWayne
    Mar 22 at 2:09
















35












$begingroup$

According to this Quora question, the best you can do using the North American Scrabble dictionary is CRYPTO(Z)OOLOGY and QUART(Z), giving a total of 171 points. The setup should look something like this:



enter image description here



...However, that's not the best you can do. We're looking at the highest possible score.



The rules of Scrabble do not prevent players from playing invalid words. There are rules for challenging someone you think has played an invalid word, and if the challenge is correct, the play will be reversed. But if players decide not to challenge, the word remains.



So, with particularly cooperative (or particularly stupid) players, the best you can do...



enter image description here



...is 303 points.






share|improve this answer









$endgroup$








  • 6




    $begingroup$
    @Brandon_J Probably, but the latter option is not against the rules of the game, no matter what language you're playing in. If nothing else, it's worth including as an option.
    $endgroup$
    – Deusovi♦
    Mar 21 at 19:20






  • 6




    $begingroup$
    (Rubio changes PSE username to QJXKFFHZHVVWWYY)
    $endgroup$
    – Rubio♦
    Mar 21 at 19:55






  • 2




    $begingroup$
    why are the E's necessary in the 2nd example? Diagonal words don't count right?
    $endgroup$
    – Aequitas
    Mar 22 at 1:05






  • 6




    $begingroup$
    @Aequitas Because otherwise, the board would have 3 disconnected pieces prior to the move (which is not possible).
    $endgroup$
    – John Doe
    Mar 22 at 1:34






  • 19




    $begingroup$
    (If anyone is wondering, "oology" is the studying of bird eggs, nests and breeding behaviour.)
    $endgroup$
    – BruceWayne
    Mar 22 at 2:09














35












35








35





$begingroup$

According to this Quora question, the best you can do using the North American Scrabble dictionary is CRYPTO(Z)OOLOGY and QUART(Z), giving a total of 171 points. The setup should look something like this:



enter image description here



...However, that's not the best you can do. We're looking at the highest possible score.



The rules of Scrabble do not prevent players from playing invalid words. There are rules for challenging someone you think has played an invalid word, and if the challenge is correct, the play will be reversed. But if players decide not to challenge, the word remains.



So, with particularly cooperative (or particularly stupid) players, the best you can do...



enter image description here



...is 303 points.






share|improve this answer









$endgroup$



According to this Quora question, the best you can do using the North American Scrabble dictionary is CRYPTO(Z)OOLOGY and QUART(Z), giving a total of 171 points. The setup should look something like this:



enter image description here



...However, that's not the best you can do. We're looking at the highest possible score.



The rules of Scrabble do not prevent players from playing invalid words. There are rules for challenging someone you think has played an invalid word, and if the challenge is correct, the play will be reversed. But if players decide not to challenge, the word remains.



So, with particularly cooperative (or particularly stupid) players, the best you can do...



enter image description here



...is 303 points.







share|improve this answer












share|improve this answer



share|improve this answer










answered Mar 21 at 19:13









Deusovi♦Deusovi

62.4k6215268




62.4k6215268







  • 6




    $begingroup$
    @Brandon_J Probably, but the latter option is not against the rules of the game, no matter what language you're playing in. If nothing else, it's worth including as an option.
    $endgroup$
    – Deusovi♦
    Mar 21 at 19:20






  • 6




    $begingroup$
    (Rubio changes PSE username to QJXKFFHZHVVWWYY)
    $endgroup$
    – Rubio♦
    Mar 21 at 19:55






  • 2




    $begingroup$
    why are the E's necessary in the 2nd example? Diagonal words don't count right?
    $endgroup$
    – Aequitas
    Mar 22 at 1:05






  • 6




    $begingroup$
    @Aequitas Because otherwise, the board would have 3 disconnected pieces prior to the move (which is not possible).
    $endgroup$
    – John Doe
    Mar 22 at 1:34






  • 19




    $begingroup$
    (If anyone is wondering, "oology" is the studying of bird eggs, nests and breeding behaviour.)
    $endgroup$
    – BruceWayne
    Mar 22 at 2:09













  • 6




    $begingroup$
    @Brandon_J Probably, but the latter option is not against the rules of the game, no matter what language you're playing in. If nothing else, it's worth including as an option.
    $endgroup$
    – Deusovi♦
    Mar 21 at 19:20






  • 6




    $begingroup$
    (Rubio changes PSE username to QJXKFFHZHVVWWYY)
    $endgroup$
    – Rubio♦
    Mar 21 at 19:55






  • 2




    $begingroup$
    why are the E's necessary in the 2nd example? Diagonal words don't count right?
    $endgroup$
    – Aequitas
    Mar 22 at 1:05






  • 6




    $begingroup$
    @Aequitas Because otherwise, the board would have 3 disconnected pieces prior to the move (which is not possible).
    $endgroup$
    – John Doe
    Mar 22 at 1:34






  • 19




    $begingroup$
    (If anyone is wondering, "oology" is the studying of bird eggs, nests and breeding behaviour.)
    $endgroup$
    – BruceWayne
    Mar 22 at 2:09








6




6




$begingroup$
@Brandon_J Probably, but the latter option is not against the rules of the game, no matter what language you're playing in. If nothing else, it's worth including as an option.
$endgroup$
– Deusovi♦
Mar 21 at 19:20




$begingroup$
@Brandon_J Probably, but the latter option is not against the rules of the game, no matter what language you're playing in. If nothing else, it's worth including as an option.
$endgroup$
– Deusovi♦
Mar 21 at 19:20




6




6




$begingroup$
(Rubio changes PSE username to QJXKFFHZHVVWWYY)
$endgroup$
– Rubio♦
Mar 21 at 19:55




$begingroup$
(Rubio changes PSE username to QJXKFFHZHVVWWYY)
$endgroup$
– Rubio♦
Mar 21 at 19:55




2




2




$begingroup$
why are the E's necessary in the 2nd example? Diagonal words don't count right?
$endgroup$
– Aequitas
Mar 22 at 1:05




$begingroup$
why are the E's necessary in the 2nd example? Diagonal words don't count right?
$endgroup$
– Aequitas
Mar 22 at 1:05




6




6




$begingroup$
@Aequitas Because otherwise, the board would have 3 disconnected pieces prior to the move (which is not possible).
$endgroup$
– John Doe
Mar 22 at 1:34




$begingroup$
@Aequitas Because otherwise, the board would have 3 disconnected pieces prior to the move (which is not possible).
$endgroup$
– John Doe
Mar 22 at 1:34




19




19




$begingroup$
(If anyone is wondering, "oology" is the studying of bird eggs, nests and breeding behaviour.)
$endgroup$
– BruceWayne
Mar 22 at 2:09





$begingroup$
(If anyone is wondering, "oology" is the studying of bird eggs, nests and breeding behaviour.)
$endgroup$
– BruceWayne
Mar 22 at 2:09












19












$begingroup$

In N-Tile Scrabble Records (Word Ways, May 1983, p.80), Kyle Corbin gives the following, for 231 points. All words can be found in Webster's Third.



 A B C D E F G H I J K L M N O
1 # . . + . . . # . . . + . . Q 1
2 . = . . . * . . . * . . . = U 2
3 . . = . . . + . + . . . = . I 3
4 + . . = . . . + . . . = . . C 4
5 . . . . = . . . . . = . . . K 5
6 . * . . . * . . . * . . . * S 6
7 . . + . . . + . + . . . + . I 7
8 # . . + . . . S N O W B A L L 8
9 . . + . . . + . + . . . + . V 9
10 . * . . . * . . . * . . . * E 10
11 . . . . = . . . . . = . . . R 11
12 + . . = . . . + . . . = . . I 12
13 . . = . . . + . + . . . = . N 13
14 . = . . . * . . . * . . E R G 14
15 H Y D R O X Y B E N Z E N E # 15
A B C D E F G H I J K L M N O


An S tile is placed into the # in the bottom right corner where there is a 3× word bonus.



(HYDROXYBENZENE)S/(QUICKSILVERING)S for 231 points.






share|improve this answer











$endgroup$








  • 3




    $begingroup$
    That's pretty cool, but wouldn't work for tournament scrabble according to scrabble.merriam.com
    $endgroup$
    – James
    Mar 22 at 12:21






  • 1




    $begingroup$
    @James: As noted on the other answer, it will work if nobody challenges it. One problem historically with the OSPD3 was that it didn't include words that are longer than eight letters and are not formed by adding common prefix or suffix to a words of eight letters or less. As noted in the introduction, one would have to look in another dictionary to check the validity of a word like "petroleum", since "eum" is not a common suffix. Does the aformentioned dictionary claim to exhaustively list all valid words of all lengths up to 15, regardless of stem length?
    $endgroup$
    – supercat
    Mar 22 at 15:59










  • $begingroup$
    Hi @supercat: As far as I can tell, the dictionary I linked to exhaustively lists all "valid" words, where "valid" means "legal in tournament Scrabble". I also notice that there are some 15-letter words in that dictionary, including "cryptozoologist" and "cryptozoologies".
    $endgroup$
    – James
    Mar 22 at 17:10










  • $begingroup$
    @James: Unless things have changed, any played word that is not challenged is valid, and this is actually a significant aspect of strategy. Even if one would expect one's opponent to believe a word is probably invalid, one might expect the opponent to refrain from challenging in cases where the downside risk would be too great.
    $endgroup$
    – supercat
    Mar 22 at 17:34










  • $begingroup$
    @supercat: I totally agree with your last comment. I thought when you used the word "valid" in the last sentence of your first comment above, you meant "valid if challenged". After all, you discussed using a dictionary to "... check the validity of a word ...". Why would you use a dictionary if any combination of letters were valid.
    $endgroup$
    – James
    Mar 22 at 17:38
















19












$begingroup$

In N-Tile Scrabble Records (Word Ways, May 1983, p.80), Kyle Corbin gives the following, for 231 points. All words can be found in Webster's Third.



 A B C D E F G H I J K L M N O
1 # . . + . . . # . . . + . . Q 1
2 . = . . . * . . . * . . . = U 2
3 . . = . . . + . + . . . = . I 3
4 + . . = . . . + . . . = . . C 4
5 . . . . = . . . . . = . . . K 5
6 . * . . . * . . . * . . . * S 6
7 . . + . . . + . + . . . + . I 7
8 # . . + . . . S N O W B A L L 8
9 . . + . . . + . + . . . + . V 9
10 . * . . . * . . . * . . . * E 10
11 . . . . = . . . . . = . . . R 11
12 + . . = . . . + . . . = . . I 12
13 . . = . . . + . + . . . = . N 13
14 . = . . . * . . . * . . E R G 14
15 H Y D R O X Y B E N Z E N E # 15
A B C D E F G H I J K L M N O


An S tile is placed into the # in the bottom right corner where there is a 3× word bonus.



(HYDROXYBENZENE)S/(QUICKSILVERING)S for 231 points.






share|improve this answer











$endgroup$








  • 3




    $begingroup$
    That's pretty cool, but wouldn't work for tournament scrabble according to scrabble.merriam.com
    $endgroup$
    – James
    Mar 22 at 12:21






  • 1




    $begingroup$
    @James: As noted on the other answer, it will work if nobody challenges it. One problem historically with the OSPD3 was that it didn't include words that are longer than eight letters and are not formed by adding common prefix or suffix to a words of eight letters or less. As noted in the introduction, one would have to look in another dictionary to check the validity of a word like "petroleum", since "eum" is not a common suffix. Does the aformentioned dictionary claim to exhaustively list all valid words of all lengths up to 15, regardless of stem length?
    $endgroup$
    – supercat
    Mar 22 at 15:59










  • $begingroup$
    Hi @supercat: As far as I can tell, the dictionary I linked to exhaustively lists all "valid" words, where "valid" means "legal in tournament Scrabble". I also notice that there are some 15-letter words in that dictionary, including "cryptozoologist" and "cryptozoologies".
    $endgroup$
    – James
    Mar 22 at 17:10










  • $begingroup$
    @James: Unless things have changed, any played word that is not challenged is valid, and this is actually a significant aspect of strategy. Even if one would expect one's opponent to believe a word is probably invalid, one might expect the opponent to refrain from challenging in cases where the downside risk would be too great.
    $endgroup$
    – supercat
    Mar 22 at 17:34










  • $begingroup$
    @supercat: I totally agree with your last comment. I thought when you used the word "valid" in the last sentence of your first comment above, you meant "valid if challenged". After all, you discussed using a dictionary to "... check the validity of a word ...". Why would you use a dictionary if any combination of letters were valid.
    $endgroup$
    – James
    Mar 22 at 17:38














19












19








19





$begingroup$

In N-Tile Scrabble Records (Word Ways, May 1983, p.80), Kyle Corbin gives the following, for 231 points. All words can be found in Webster's Third.



 A B C D E F G H I J K L M N O
1 # . . + . . . # . . . + . . Q 1
2 . = . . . * . . . * . . . = U 2
3 . . = . . . + . + . . . = . I 3
4 + . . = . . . + . . . = . . C 4
5 . . . . = . . . . . = . . . K 5
6 . * . . . * . . . * . . . * S 6
7 . . + . . . + . + . . . + . I 7
8 # . . + . . . S N O W B A L L 8
9 . . + . . . + . + . . . + . V 9
10 . * . . . * . . . * . . . * E 10
11 . . . . = . . . . . = . . . R 11
12 + . . = . . . + . . . = . . I 12
13 . . = . . . + . + . . . = . N 13
14 . = . . . * . . . * . . E R G 14
15 H Y D R O X Y B E N Z E N E # 15
A B C D E F G H I J K L M N O


An S tile is placed into the # in the bottom right corner where there is a 3× word bonus.



(HYDROXYBENZENE)S/(QUICKSILVERING)S for 231 points.






share|improve this answer











$endgroup$



In N-Tile Scrabble Records (Word Ways, May 1983, p.80), Kyle Corbin gives the following, for 231 points. All words can be found in Webster's Third.



 A B C D E F G H I J K L M N O
1 # . . + . . . # . . . + . . Q 1
2 . = . . . * . . . * . . . = U 2
3 . . = . . . + . + . . . = . I 3
4 + . . = . . . + . . . = . . C 4
5 . . . . = . . . . . = . . . K 5
6 . * . . . * . . . * . . . * S 6
7 . . + . . . + . + . . . + . I 7
8 # . . + . . . S N O W B A L L 8
9 . . + . . . + . + . . . + . V 9
10 . * . . . * . . . * . . . * E 10
11 . . . . = . . . . . = . . . R 11
12 + . . = . . . + . . . = . . I 12
13 . . = . . . + . + . . . = . N 13
14 . = . . . * . . . * . . E R G 14
15 H Y D R O X Y B E N Z E N E # 15
A B C D E F G H I J K L M N O


An S tile is placed into the # in the bottom right corner where there is a 3× word bonus.



(HYDROXYBENZENE)S/(QUICKSILVERING)S for 231 points.







share|improve this answer














share|improve this answer



share|improve this answer








edited Mar 22 at 11:19









doppelgreener

298213




298213










answered Mar 22 at 7:37









Rosie FRosie F

5,9382944




5,9382944







  • 3




    $begingroup$
    That's pretty cool, but wouldn't work for tournament scrabble according to scrabble.merriam.com
    $endgroup$
    – James
    Mar 22 at 12:21






  • 1




    $begingroup$
    @James: As noted on the other answer, it will work if nobody challenges it. One problem historically with the OSPD3 was that it didn't include words that are longer than eight letters and are not formed by adding common prefix or suffix to a words of eight letters or less. As noted in the introduction, one would have to look in another dictionary to check the validity of a word like "petroleum", since "eum" is not a common suffix. Does the aformentioned dictionary claim to exhaustively list all valid words of all lengths up to 15, regardless of stem length?
    $endgroup$
    – supercat
    Mar 22 at 15:59










  • $begingroup$
    Hi @supercat: As far as I can tell, the dictionary I linked to exhaustively lists all "valid" words, where "valid" means "legal in tournament Scrabble". I also notice that there are some 15-letter words in that dictionary, including "cryptozoologist" and "cryptozoologies".
    $endgroup$
    – James
    Mar 22 at 17:10










  • $begingroup$
    @James: Unless things have changed, any played word that is not challenged is valid, and this is actually a significant aspect of strategy. Even if one would expect one's opponent to believe a word is probably invalid, one might expect the opponent to refrain from challenging in cases where the downside risk would be too great.
    $endgroup$
    – supercat
    Mar 22 at 17:34










  • $begingroup$
    @supercat: I totally agree with your last comment. I thought when you used the word "valid" in the last sentence of your first comment above, you meant "valid if challenged". After all, you discussed using a dictionary to "... check the validity of a word ...". Why would you use a dictionary if any combination of letters were valid.
    $endgroup$
    – James
    Mar 22 at 17:38













  • 3




    $begingroup$
    That's pretty cool, but wouldn't work for tournament scrabble according to scrabble.merriam.com
    $endgroup$
    – James
    Mar 22 at 12:21






  • 1




    $begingroup$
    @James: As noted on the other answer, it will work if nobody challenges it. One problem historically with the OSPD3 was that it didn't include words that are longer than eight letters and are not formed by adding common prefix or suffix to a words of eight letters or less. As noted in the introduction, one would have to look in another dictionary to check the validity of a word like "petroleum", since "eum" is not a common suffix. Does the aformentioned dictionary claim to exhaustively list all valid words of all lengths up to 15, regardless of stem length?
    $endgroup$
    – supercat
    Mar 22 at 15:59










  • $begingroup$
    Hi @supercat: As far as I can tell, the dictionary I linked to exhaustively lists all "valid" words, where "valid" means "legal in tournament Scrabble". I also notice that there are some 15-letter words in that dictionary, including "cryptozoologist" and "cryptozoologies".
    $endgroup$
    – James
    Mar 22 at 17:10










  • $begingroup$
    @James: Unless things have changed, any played word that is not challenged is valid, and this is actually a significant aspect of strategy. Even if one would expect one's opponent to believe a word is probably invalid, one might expect the opponent to refrain from challenging in cases where the downside risk would be too great.
    $endgroup$
    – supercat
    Mar 22 at 17:34










  • $begingroup$
    @supercat: I totally agree with your last comment. I thought when you used the word "valid" in the last sentence of your first comment above, you meant "valid if challenged". After all, you discussed using a dictionary to "... check the validity of a word ...". Why would you use a dictionary if any combination of letters were valid.
    $endgroup$
    – James
    Mar 22 at 17:38








3




3




$begingroup$
That's pretty cool, but wouldn't work for tournament scrabble according to scrabble.merriam.com
$endgroup$
– James
Mar 22 at 12:21




$begingroup$
That's pretty cool, but wouldn't work for tournament scrabble according to scrabble.merriam.com
$endgroup$
– James
Mar 22 at 12:21




1




1




$begingroup$
@James: As noted on the other answer, it will work if nobody challenges it. One problem historically with the OSPD3 was that it didn't include words that are longer than eight letters and are not formed by adding common prefix or suffix to a words of eight letters or less. As noted in the introduction, one would have to look in another dictionary to check the validity of a word like "petroleum", since "eum" is not a common suffix. Does the aformentioned dictionary claim to exhaustively list all valid words of all lengths up to 15, regardless of stem length?
$endgroup$
– supercat
Mar 22 at 15:59




$begingroup$
@James: As noted on the other answer, it will work if nobody challenges it. One problem historically with the OSPD3 was that it didn't include words that are longer than eight letters and are not formed by adding common prefix or suffix to a words of eight letters or less. As noted in the introduction, one would have to look in another dictionary to check the validity of a word like "petroleum", since "eum" is not a common suffix. Does the aformentioned dictionary claim to exhaustively list all valid words of all lengths up to 15, regardless of stem length?
$endgroup$
– supercat
Mar 22 at 15:59












$begingroup$
Hi @supercat: As far as I can tell, the dictionary I linked to exhaustively lists all "valid" words, where "valid" means "legal in tournament Scrabble". I also notice that there are some 15-letter words in that dictionary, including "cryptozoologist" and "cryptozoologies".
$endgroup$
– James
Mar 22 at 17:10




$begingroup$
Hi @supercat: As far as I can tell, the dictionary I linked to exhaustively lists all "valid" words, where "valid" means "legal in tournament Scrabble". I also notice that there are some 15-letter words in that dictionary, including "cryptozoologist" and "cryptozoologies".
$endgroup$
– James
Mar 22 at 17:10












$begingroup$
@James: Unless things have changed, any played word that is not challenged is valid, and this is actually a significant aspect of strategy. Even if one would expect one's opponent to believe a word is probably invalid, one might expect the opponent to refrain from challenging in cases where the downside risk would be too great.
$endgroup$
– supercat
Mar 22 at 17:34




$begingroup$
@James: Unless things have changed, any played word that is not challenged is valid, and this is actually a significant aspect of strategy. Even if one would expect one's opponent to believe a word is probably invalid, one might expect the opponent to refrain from challenging in cases where the downside risk would be too great.
$endgroup$
– supercat
Mar 22 at 17:34












$begingroup$
@supercat: I totally agree with your last comment. I thought when you used the word "valid" in the last sentence of your first comment above, you meant "valid if challenged". After all, you discussed using a dictionary to "... check the validity of a word ...". Why would you use a dictionary if any combination of letters were valid.
$endgroup$
– James
Mar 22 at 17:38





$begingroup$
@supercat: I totally agree with your last comment. I thought when you used the word "valid" in the last sentence of your first comment above, you meant "valid if challenged". After all, you discussed using a dictionary to "... check the validity of a word ...". Why would you use a dictionary if any combination of letters were valid.
$endgroup$
– James
Mar 22 at 17:38


















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