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Creating nested elements dynamically


Create GUID / UUID in JavaScript?How do I detect a click outside an element?How do I check if an element is hidden in jQuery?Event binding on dynamically created elements?Retrieve the position (X,Y) of an HTML elementHow do I find out which DOM element has the focus?Creating a div element in jQueryHow to move an element into another element?How do I remove a particular element from an array in JavaScript?jQuery scroll to element













9















I have this array of strings var arr = ["ul", "li", "strong", "em", "u"].



How can I make these into DOM Elements one inside another from left to right, first element as the root element. Without using ID because of some reason.



And maybe by using loop for it to be flexible to any number of elements.



var new_element = document.createElement(arr[0]);



I'm expecting something like this:



<ul>
<li><strong><em><u>Text Here</u></em></strong></li>
</ul>


Thank you.










share|improve this question



















  • 1





    You want to know about Node.appendChild.

    – moonwave99
    2 days ago















9















I have this array of strings var arr = ["ul", "li", "strong", "em", "u"].



How can I make these into DOM Elements one inside another from left to right, first element as the root element. Without using ID because of some reason.



And maybe by using loop for it to be flexible to any number of elements.



var new_element = document.createElement(arr[0]);



I'm expecting something like this:



<ul>
<li><strong><em><u>Text Here</u></em></strong></li>
</ul>


Thank you.










share|improve this question



















  • 1





    You want to know about Node.appendChild.

    – moonwave99
    2 days ago













9












9








9


1






I have this array of strings var arr = ["ul", "li", "strong", "em", "u"].



How can I make these into DOM Elements one inside another from left to right, first element as the root element. Without using ID because of some reason.



And maybe by using loop for it to be flexible to any number of elements.



var new_element = document.createElement(arr[0]);



I'm expecting something like this:



<ul>
<li><strong><em><u>Text Here</u></em></strong></li>
</ul>


Thank you.










share|improve this question
















I have this array of strings var arr = ["ul", "li", "strong", "em", "u"].



How can I make these into DOM Elements one inside another from left to right, first element as the root element. Without using ID because of some reason.



And maybe by using loop for it to be flexible to any number of elements.



var new_element = document.createElement(arr[0]);



I'm expecting something like this:



<ul>
<li><strong><em><u>Text Here</u></em></strong></li>
</ul>


Thank you.







javascript html dom






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 2 days ago









Community

11




11










asked 2 days ago









MuyieMuyie

728




728







  • 1





    You want to know about Node.appendChild.

    – moonwave99
    2 days ago












  • 1





    You want to know about Node.appendChild.

    – moonwave99
    2 days ago







1




1





You want to know about Node.appendChild.

– moonwave99
2 days ago





You want to know about Node.appendChild.

– moonwave99
2 days ago












3 Answers
3






active

oldest

votes


















7














You can do this with reduceRight() which avoids needing to query the result to get the deepest value because it starts with the deepest element and works out. The return value will be the topmost element:






var arr = ["ul", "li", "strong", "em", "u"]

let el = arr.reduceRight((el, n) =>
let d = document.createElement(n)
d.appendChild(el)
return d
, document.createTextNode("Text Here"))

document.getElementById('container').appendChild(el)

<div id = "container"></div>





It also fails gracefully with an empty array:






var arr = []

let el = arr.reduceRight((el, n) =>
let d = document.createElement(n)
d.appendChild(el)
return d
, document.createTextNode("Text Here"))

document.getElementById('container').appendChild(el)

<div id = "container"></div>








share|improve this answer


















  • 1





    Great! Works as expected. I'll be analyzing how this works and read about the reduce and reduceRight function. Thank you

    – Muyie
    2 days ago


















11














You can use Array.prototype.reduce and Node.prototype.appendChild.



https://jsbin.com/hizetekato/edit?html,js,output






var arr = ["ul", "li", "strong", "em", "u"];

function createChildren(mount, arr)
return arr.reduce((parent, elementName, i) =>
const element = document.createElement(elementName);
parent.appendChild(element);
return element;
, mount);


const deepest = createChildren(document.querySelector('#root'), arr);

deepest.innerText = 'WebDevNSK'

<div id="root"></div>








share|improve this answer

























  • Seems like this is what I am looking for. I'll try to analyze it. And read about .reduce() Thank you btw.

    – Muyie
    2 days ago











  • What about => parent.appendChild(document.createElement(elementName));? Node.appendChild returns the appended child. However, readability is probably more important that concision.

    – Solomon Ucko
    2 days ago


















0














createDocumentFragment() and run the array through a loop. On each iteration createElement() and appendChild()






const frag = document.createDocumentFragment();
const useless = ["ul", "li", "strong", "em", "u"];

let previous;
for (let u = 0; u < useless.length; u++)
const current = document.createElement(useless[u]);
if (u === 0)
frag.appendChild(current);
else
previous.appendChild(current);

previous = current;


document.body.appendChild(frag);

ul 
outline: 5px dashed green;
padding: 15px;


li
outline: 5px solid blue;
padding: 12px;


strong
outline: 5px dashed red;
padding: 9px


em
outline: 5px dashed grey;
padding: 6px


u
outline: 5px solid black;
padding: 3px;


u::before
content: 'THIS TEXT SHOULD BE UNDERLINED'








share|improve this answer






















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    3 Answers
    3






    active

    oldest

    votes








    3 Answers
    3






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    7














    You can do this with reduceRight() which avoids needing to query the result to get the deepest value because it starts with the deepest element and works out. The return value will be the topmost element:






    var arr = ["ul", "li", "strong", "em", "u"]

    let el = arr.reduceRight((el, n) =>
    let d = document.createElement(n)
    d.appendChild(el)
    return d
    , document.createTextNode("Text Here"))

    document.getElementById('container').appendChild(el)

    <div id = "container"></div>





    It also fails gracefully with an empty array:






    var arr = []

    let el = arr.reduceRight((el, n) =>
    let d = document.createElement(n)
    d.appendChild(el)
    return d
    , document.createTextNode("Text Here"))

    document.getElementById('container').appendChild(el)

    <div id = "container"></div>








    share|improve this answer


















    • 1





      Great! Works as expected. I'll be analyzing how this works and read about the reduce and reduceRight function. Thank you

      – Muyie
      2 days ago















    7














    You can do this with reduceRight() which avoids needing to query the result to get the deepest value because it starts with the deepest element and works out. The return value will be the topmost element:






    var arr = ["ul", "li", "strong", "em", "u"]

    let el = arr.reduceRight((el, n) =>
    let d = document.createElement(n)
    d.appendChild(el)
    return d
    , document.createTextNode("Text Here"))

    document.getElementById('container').appendChild(el)

    <div id = "container"></div>





    It also fails gracefully with an empty array:






    var arr = []

    let el = arr.reduceRight((el, n) =>
    let d = document.createElement(n)
    d.appendChild(el)
    return d
    , document.createTextNode("Text Here"))

    document.getElementById('container').appendChild(el)

    <div id = "container"></div>








    share|improve this answer


















    • 1





      Great! Works as expected. I'll be analyzing how this works and read about the reduce and reduceRight function. Thank you

      – Muyie
      2 days ago













    7












    7








    7







    You can do this with reduceRight() which avoids needing to query the result to get the deepest value because it starts with the deepest element and works out. The return value will be the topmost element:






    var arr = ["ul", "li", "strong", "em", "u"]

    let el = arr.reduceRight((el, n) =>
    let d = document.createElement(n)
    d.appendChild(el)
    return d
    , document.createTextNode("Text Here"))

    document.getElementById('container').appendChild(el)

    <div id = "container"></div>





    It also fails gracefully with an empty array:






    var arr = []

    let el = arr.reduceRight((el, n) =>
    let d = document.createElement(n)
    d.appendChild(el)
    return d
    , document.createTextNode("Text Here"))

    document.getElementById('container').appendChild(el)

    <div id = "container"></div>








    share|improve this answer













    You can do this with reduceRight() which avoids needing to query the result to get the deepest value because it starts with the deepest element and works out. The return value will be the topmost element:






    var arr = ["ul", "li", "strong", "em", "u"]

    let el = arr.reduceRight((el, n) =>
    let d = document.createElement(n)
    d.appendChild(el)
    return d
    , document.createTextNode("Text Here"))

    document.getElementById('container').appendChild(el)

    <div id = "container"></div>





    It also fails gracefully with an empty array:






    var arr = []

    let el = arr.reduceRight((el, n) =>
    let d = document.createElement(n)
    d.appendChild(el)
    return d
    , document.createTextNode("Text Here"))

    document.getElementById('container').appendChild(el)

    <div id = "container"></div>








    var arr = ["ul", "li", "strong", "em", "u"]

    let el = arr.reduceRight((el, n) =>
    let d = document.createElement(n)
    d.appendChild(el)
    return d
    , document.createTextNode("Text Here"))

    document.getElementById('container').appendChild(el)

    <div id = "container"></div>





    var arr = ["ul", "li", "strong", "em", "u"]

    let el = arr.reduceRight((el, n) =>
    let d = document.createElement(n)
    d.appendChild(el)
    return d
    , document.createTextNode("Text Here"))

    document.getElementById('container').appendChild(el)

    <div id = "container"></div>





    var arr = []

    let el = arr.reduceRight((el, n) =>
    let d = document.createElement(n)
    d.appendChild(el)
    return d
    , document.createTextNode("Text Here"))

    document.getElementById('container').appendChild(el)

    <div id = "container"></div>





    var arr = []

    let el = arr.reduceRight((el, n) =>
    let d = document.createElement(n)
    d.appendChild(el)
    return d
    , document.createTextNode("Text Here"))

    document.getElementById('container').appendChild(el)

    <div id = "container"></div>






    share|improve this answer












    share|improve this answer



    share|improve this answer










    answered 2 days ago









    Mark MeyerMark Meyer

    39.7k33262




    39.7k33262







    • 1





      Great! Works as expected. I'll be analyzing how this works and read about the reduce and reduceRight function. Thank you

      – Muyie
      2 days ago












    • 1





      Great! Works as expected. I'll be analyzing how this works and read about the reduce and reduceRight function. Thank you

      – Muyie
      2 days ago







    1




    1





    Great! Works as expected. I'll be analyzing how this works and read about the reduce and reduceRight function. Thank you

    – Muyie
    2 days ago





    Great! Works as expected. I'll be analyzing how this works and read about the reduce and reduceRight function. Thank you

    – Muyie
    2 days ago













    11














    You can use Array.prototype.reduce and Node.prototype.appendChild.



    https://jsbin.com/hizetekato/edit?html,js,output






    var arr = ["ul", "li", "strong", "em", "u"];

    function createChildren(mount, arr)
    return arr.reduce((parent, elementName, i) =>
    const element = document.createElement(elementName);
    parent.appendChild(element);
    return element;
    , mount);


    const deepest = createChildren(document.querySelector('#root'), arr);

    deepest.innerText = 'WebDevNSK'

    <div id="root"></div>








    share|improve this answer

























    • Seems like this is what I am looking for. I'll try to analyze it. And read about .reduce() Thank you btw.

      – Muyie
      2 days ago











    • What about => parent.appendChild(document.createElement(elementName));? Node.appendChild returns the appended child. However, readability is probably more important that concision.

      – Solomon Ucko
      2 days ago















    11














    You can use Array.prototype.reduce and Node.prototype.appendChild.



    https://jsbin.com/hizetekato/edit?html,js,output






    var arr = ["ul", "li", "strong", "em", "u"];

    function createChildren(mount, arr)
    return arr.reduce((parent, elementName, i) =>
    const element = document.createElement(elementName);
    parent.appendChild(element);
    return element;
    , mount);


    const deepest = createChildren(document.querySelector('#root'), arr);

    deepest.innerText = 'WebDevNSK'

    <div id="root"></div>








    share|improve this answer

























    • Seems like this is what I am looking for. I'll try to analyze it. And read about .reduce() Thank you btw.

      – Muyie
      2 days ago











    • What about => parent.appendChild(document.createElement(elementName));? Node.appendChild returns the appended child. However, readability is probably more important that concision.

      – Solomon Ucko
      2 days ago













    11












    11








    11







    You can use Array.prototype.reduce and Node.prototype.appendChild.



    https://jsbin.com/hizetekato/edit?html,js,output






    var arr = ["ul", "li", "strong", "em", "u"];

    function createChildren(mount, arr)
    return arr.reduce((parent, elementName, i) =>
    const element = document.createElement(elementName);
    parent.appendChild(element);
    return element;
    , mount);


    const deepest = createChildren(document.querySelector('#root'), arr);

    deepest.innerText = 'WebDevNSK'

    <div id="root"></div>








    share|improve this answer















    You can use Array.prototype.reduce and Node.prototype.appendChild.



    https://jsbin.com/hizetekato/edit?html,js,output






    var arr = ["ul", "li", "strong", "em", "u"];

    function createChildren(mount, arr)
    return arr.reduce((parent, elementName, i) =>
    const element = document.createElement(elementName);
    parent.appendChild(element);
    return element;
    , mount);


    const deepest = createChildren(document.querySelector('#root'), arr);

    deepest.innerText = 'WebDevNSK'

    <div id="root"></div>








    var arr = ["ul", "li", "strong", "em", "u"];

    function createChildren(mount, arr)
    return arr.reduce((parent, elementName, i) =>
    const element = document.createElement(elementName);
    parent.appendChild(element);
    return element;
    , mount);


    const deepest = createChildren(document.querySelector('#root'), arr);

    deepest.innerText = 'WebDevNSK'

    <div id="root"></div>





    var arr = ["ul", "li", "strong", "em", "u"];

    function createChildren(mount, arr)
    return arr.reduce((parent, elementName, i) =>
    const element = document.createElement(elementName);
    parent.appendChild(element);
    return element;
    , mount);


    const deepest = createChildren(document.querySelector('#root'), arr);

    deepest.innerText = 'WebDevNSK'

    <div id="root"></div>






    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited 2 days ago









    Jack Bashford

    13.3k31847




    13.3k31847










    answered 2 days ago









    dangreendangreen

    1498




    1498












    • Seems like this is what I am looking for. I'll try to analyze it. And read about .reduce() Thank you btw.

      – Muyie
      2 days ago











    • What about => parent.appendChild(document.createElement(elementName));? Node.appendChild returns the appended child. However, readability is probably more important that concision.

      – Solomon Ucko
      2 days ago

















    • Seems like this is what I am looking for. I'll try to analyze it. And read about .reduce() Thank you btw.

      – Muyie
      2 days ago











    • What about => parent.appendChild(document.createElement(elementName));? Node.appendChild returns the appended child. However, readability is probably more important that concision.

      – Solomon Ucko
      2 days ago
















    Seems like this is what I am looking for. I'll try to analyze it. And read about .reduce() Thank you btw.

    – Muyie
    2 days ago





    Seems like this is what I am looking for. I'll try to analyze it. And read about .reduce() Thank you btw.

    – Muyie
    2 days ago













    What about => parent.appendChild(document.createElement(elementName));? Node.appendChild returns the appended child. However, readability is probably more important that concision.

    – Solomon Ucko
    2 days ago





    What about => parent.appendChild(document.createElement(elementName));? Node.appendChild returns the appended child. However, readability is probably more important that concision.

    – Solomon Ucko
    2 days ago











    0














    createDocumentFragment() and run the array through a loop. On each iteration createElement() and appendChild()






    const frag = document.createDocumentFragment();
    const useless = ["ul", "li", "strong", "em", "u"];

    let previous;
    for (let u = 0; u < useless.length; u++)
    const current = document.createElement(useless[u]);
    if (u === 0)
    frag.appendChild(current);
    else
    previous.appendChild(current);

    previous = current;


    document.body.appendChild(frag);

    ul 
    outline: 5px dashed green;
    padding: 15px;


    li
    outline: 5px solid blue;
    padding: 12px;


    strong
    outline: 5px dashed red;
    padding: 9px


    em
    outline: 5px dashed grey;
    padding: 6px


    u
    outline: 5px solid black;
    padding: 3px;


    u::before
    content: 'THIS TEXT SHOULD BE UNDERLINED'








    share|improve this answer



























      0














      createDocumentFragment() and run the array through a loop. On each iteration createElement() and appendChild()






      const frag = document.createDocumentFragment();
      const useless = ["ul", "li", "strong", "em", "u"];

      let previous;
      for (let u = 0; u < useless.length; u++)
      const current = document.createElement(useless[u]);
      if (u === 0)
      frag.appendChild(current);
      else
      previous.appendChild(current);

      previous = current;


      document.body.appendChild(frag);

      ul 
      outline: 5px dashed green;
      padding: 15px;


      li
      outline: 5px solid blue;
      padding: 12px;


      strong
      outline: 5px dashed red;
      padding: 9px


      em
      outline: 5px dashed grey;
      padding: 6px


      u
      outline: 5px solid black;
      padding: 3px;


      u::before
      content: 'THIS TEXT SHOULD BE UNDERLINED'








      share|improve this answer

























        0












        0








        0







        createDocumentFragment() and run the array through a loop. On each iteration createElement() and appendChild()






        const frag = document.createDocumentFragment();
        const useless = ["ul", "li", "strong", "em", "u"];

        let previous;
        for (let u = 0; u < useless.length; u++)
        const current = document.createElement(useless[u]);
        if (u === 0)
        frag.appendChild(current);
        else
        previous.appendChild(current);

        previous = current;


        document.body.appendChild(frag);

        ul 
        outline: 5px dashed green;
        padding: 15px;


        li
        outline: 5px solid blue;
        padding: 12px;


        strong
        outline: 5px dashed red;
        padding: 9px


        em
        outline: 5px dashed grey;
        padding: 6px


        u
        outline: 5px solid black;
        padding: 3px;


        u::before
        content: 'THIS TEXT SHOULD BE UNDERLINED'








        share|improve this answer













        createDocumentFragment() and run the array through a loop. On each iteration createElement() and appendChild()






        const frag = document.createDocumentFragment();
        const useless = ["ul", "li", "strong", "em", "u"];

        let previous;
        for (let u = 0; u < useless.length; u++)
        const current = document.createElement(useless[u]);
        if (u === 0)
        frag.appendChild(current);
        else
        previous.appendChild(current);

        previous = current;


        document.body.appendChild(frag);

        ul 
        outline: 5px dashed green;
        padding: 15px;


        li
        outline: 5px solid blue;
        padding: 12px;


        strong
        outline: 5px dashed red;
        padding: 9px


        em
        outline: 5px dashed grey;
        padding: 6px


        u
        outline: 5px solid black;
        padding: 3px;


        u::before
        content: 'THIS TEXT SHOULD BE UNDERLINED'








        const frag = document.createDocumentFragment();
        const useless = ["ul", "li", "strong", "em", "u"];

        let previous;
        for (let u = 0; u < useless.length; u++)
        const current = document.createElement(useless[u]);
        if (u === 0)
        frag.appendChild(current);
        else
        previous.appendChild(current);

        previous = current;


        document.body.appendChild(frag);

        ul 
        outline: 5px dashed green;
        padding: 15px;


        li
        outline: 5px solid blue;
        padding: 12px;


        strong
        outline: 5px dashed red;
        padding: 9px


        em
        outline: 5px dashed grey;
        padding: 6px


        u
        outline: 5px solid black;
        padding: 3px;


        u::before
        content: 'THIS TEXT SHOULD BE UNDERLINED'





        const frag = document.createDocumentFragment();
        const useless = ["ul", "li", "strong", "em", "u"];

        let previous;
        for (let u = 0; u < useless.length; u++)
        const current = document.createElement(useless[u]);
        if (u === 0)
        frag.appendChild(current);
        else
        previous.appendChild(current);

        previous = current;


        document.body.appendChild(frag);

        ul 
        outline: 5px dashed green;
        padding: 15px;


        li
        outline: 5px solid blue;
        padding: 12px;


        strong
        outline: 5px dashed red;
        padding: 9px


        em
        outline: 5px dashed grey;
        padding: 6px


        u
        outline: 5px solid black;
        padding: 3px;


        u::before
        content: 'THIS TEXT SHOULD BE UNDERLINED'






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered 2 days ago









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            2017 IndyCar Series Contents Series news Teams and drivers Schedule Season summary Footnotes References External links Navigation menu"INDYCAR: Initial 2018 bodywork concepts unveiled"the original"IndyCar confirms switch to Performance Friction brakes in 2017""AJ Foyt Racing will switch to Chevy"the original"Carlos Munoz, Conor Daly will drive for AJ Foyt Racing""Zach Veach's Indy 500 Debut Confirmed with Foyt""No mass exodus from Honda after Ganassi switch""Ex-F1 driver Sato joins Andretti Autosport for 2017 IndyCar season""IndyCar's Ryan Hunter-Reay, sponsor DHL paired through 2020""hhgregg and Andretti Autosport announce partnership for key races in 2016""INDYCAR: Rossi re-signs with Andretti"the original"McLaren Formula 1 - Fernando Alonso to race at Indy 500 with McLaren, Honda and Andretti Autosport""Shank will finally take part in Indy 500 with Harvey, Andretti | MotorSportsTalk""Andretti adds Jack Harvey to Indy 500 field""Ganassi switches to Honda power for 2017""INDYCAR: Chilton returns to Ganassi"the original"IndyCar silly season: Who's going where in 2017?""INDYCAR: Kanaan, NTT Data return to Ganassi"the original"Kimball to remain at Ganassi for 2017""Coyne confirms Bourdais for 2017 IndyCar season""Davison to sub for Bourdais in Indy 500"the original"Gutierrez confirmed for Detroit IndyCar debut""Gutierrez returns with Coyne for rest of 2017 season""Vautier to drive for Coyne at Texas"the original"INDYCAR: Coyne confirms Jones for 2017"the original"Pippa Mann returns to Coyne for Indy 500""Karam, Dreyer & Reinbold teaming up again for Indianapolis 500""Pigot to return to Ed Carpenter Racing""Hildebrand confirmed as full-time Ed Carpenter driver""Veach to replace injured Hildebrand at Barber"the originalNew Team Harding Racing Enters Chaves for 101st Indianapolis 500"Juncos Racing Announces Entry in 101st Running of the Indianapolis 500 :: Juncos Racing""Juncos confirms Pigot for Indy 500""Saavedra confirmed in Juncos' second 500 entry"the original"Lazier confirms Indy 500 run after son's USF2000 debut"the original"Claman DeMelo to race for RLLR at Sonoma"the original"Rahal signs Servia and ace engineer for 2017""IndyCar: Aleshin returns with Schmidt"the original"Aleshin replaced by Saavedra for Toronto""Jack Harvey will pilot SPM No. 7 car at Watkins Glen, Sonoma""Jay Howard confirmed in Tony Stewart's supported SPM Indy entry""INDYCAR: Newgarden to wave the flag at Penske"the original"Pagenaud opts for No. 1 in 2017"the original"Penske confirms Newgarden for 2017""Montoya to stay with Team Penske in 2017""Target leaving IndyCar after 27 seasons with Chip Ganassi""Cavin: IndyCar could see complete driver/team shakeup in 2017""End of the road for KV Racing?""KV Racing confirms closure, equipment sold to Juncos""Juncos confirms IndyCar Series entry"the original"Juncos readies IndyCar program, aims for '17 500"the original"Harding Racing to add Texas, Pocono to schedule"the original"Sato signs with Andretti Autosport for 2017""INDYCAR: Aleshin in Doubt at SPM"the original"Long Beach notebook: JR Hildebrand breaks hand""Hildebrand cleared to return at Phoenix"the original"Bourdais to undergo surgery on multiple fractures""Aleshin loses Schmidt Peterson IndyCar ride""Saavedra in at SPM for Pocono, Gateway"the original"Bourdais to make return at Gateway"the original"The IndyCar Grand Prix no longer is sponsored by Angie's List""2017 IndyCar Series rulebook""2017 Verizon IndyCar Series Official Rulebook"Official websiteeeeee