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Running bash inside cronjob

How to determine why a machine is running slowly?Why does my cronjob not execute my shell-script?Cron job running at 12.00 AM despite changing its timeHow to interpret busybox “top” output?Latexmk, from Makefile, from bash script, from Cron - Latexmk not being executedLog free and topoutput logs in crontab does not workunreasonable memory usageSFTP script not working with cron jobBash script able to run manually, but with cron not working. + Ubuntu 16.04

1

I have this cronjob to run every minute

*/1 * * * * root sh /test.sh

My /test.sh logs the result of "top" and "free" command. It works fine when I run it manually on terminal with "sh /teste.sh" and saves the output to a nice file, however when the cron job runs it only saves the result of the command "free" below. Check this please:

printf "n" >> "log_lojar_top_free.txt"
printf %s "$(date)" >> "log_lojar_top_free.txt"
printf 't' >> "log_lojar_top_free.txt"
top -b -n 3 -d 1 | grep "Cpu" | tail -n 1 | awk '/^%Cpu(s)/ printf $2' >> "log_lojar_top_free.txt"
printf 't' >> "log_lojar_top_free.txt"
free | awk '/^Mem:/ printf $7' >> "log_lojar_top_free.txt"

What is the error that is causing that only the last line (free) to have it's output loged?

linux ubuntu centos

share|improve this question

edited 1 min ago

Guillermo Mosse

1031

asked Oct 30 '15 at 22:46

SamulSamul

18117

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  if you want to run a bash script then use bash, not sh. they're not the same thing. even if sh is a symlink to bash, bash behaves differently if called as sh rather than bash.
  
  – cas
  Oct 31 '15 at 0:51
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  you can do as cas suggests either by prefixing in crontab with /bin/bash instead of sh, or by starting your script with a shebang line: #!/bin/bash - see if it behaves better once you definitely have it running under bash and not some other shell. Another possibility is that you aren't looking in the right place for the output file. The cron job is running as root and since you didn't specify an output directory, only a file, it will probably save it at / - not a good place to use generally. Oh and BTW you don't need the /1.
  
  – gogoud
  Oct 31 '15 at 8:13
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  A quick check shows that my implementation of crond writes to the user's home directory. In my case, for root that's /root.
  
  – roaima
  Nov 3 '15 at 22:51
  

  
  
  
  

add a comment | 

1

I have this cronjob to run every minute

*/1 * * * * root sh /test.sh

My /test.sh logs the result of "top" and "free" command. It works fine when I run it manually on terminal with "sh /teste.sh" and saves the output to a nice file, however when the cron job runs it only saves the result of the command "free" below. Check this please:

printf "n" >> "log_lojar_top_free.txt"
printf %s "$(date)" >> "log_lojar_top_free.txt"
printf 't' >> "log_lojar_top_free.txt"
top -b -n 3 -d 1 | grep "Cpu" | tail -n 1 | awk '/^%Cpu(s)/ printf $2' >> "log_lojar_top_free.txt"
printf 't' >> "log_lojar_top_free.txt"
free | awk '/^Mem:/ printf $7' >> "log_lojar_top_free.txt"

What is the error that is causing that only the last line (free) to have it's output loged?

linux ubuntu centos

share|improve this question

edited 1 min ago

Guillermo Mosse

1031

asked Oct 30 '15 at 22:46

SamulSamul

18117

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  if you want to run a bash script then use bash, not sh. they're not the same thing. even if sh is a symlink to bash, bash behaves differently if called as sh rather than bash.
  
  – cas
  Oct 31 '15 at 0:51
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  you can do as cas suggests either by prefixing in crontab with /bin/bash instead of sh, or by starting your script with a shebang line: #!/bin/bash - see if it behaves better once you definitely have it running under bash and not some other shell. Another possibility is that you aren't looking in the right place for the output file. The cron job is running as root and since you didn't specify an output directory, only a file, it will probably save it at / - not a good place to use generally. Oh and BTW you don't need the /1.
  
  – gogoud
  Oct 31 '15 at 8:13
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  A quick check shows that my implementation of crond writes to the user's home directory. In my case, for root that's /root.
  
  – roaima
  Nov 3 '15 at 22:51
  

  
  
  
  

add a comment | 

I have this cronjob to run every minute

*/1 * * * * root sh /test.sh

My /test.sh logs the result of "top" and "free" command. It works fine when I run it manually on terminal with "sh /teste.sh" and saves the output to a nice file, however when the cron job runs it only saves the result of the command "free" below. Check this please:

printf "n" >> "log_lojar_top_free.txt"
printf %s "$(date)" >> "log_lojar_top_free.txt"
printf 't' >> "log_lojar_top_free.txt"
top -b -n 3 -d 1 | grep "Cpu" | tail -n 1 | awk '/^%Cpu(s)/ printf $2' >> "log_lojar_top_free.txt"
printf 't' >> "log_lojar_top_free.txt"
free | awk '/^Mem:/ printf $7' >> "log_lojar_top_free.txt"

What is the error that is causing that only the last line (free) to have it's output loged?

linux ubuntu centos

share|improve this question

edited 1 min ago

Guillermo Mosse

1031

asked Oct 30 '15 at 22:46

SamulSamul

18117

*/1 * * * * root sh /test.sh

printf "n" >> "log_lojar_top_free.txt"
printf %s "$(date)" >> "log_lojar_top_free.txt"
printf 't' >> "log_lojar_top_free.txt"
top -b -n 3 -d 1 | grep "Cpu" | tail -n 1 | awk '/^%Cpu(s)/ printf $2' >> "log_lojar_top_free.txt"
printf 't' >> "log_lojar_top_free.txt"
free | awk '/^Mem:/ printf $7' >> "log_lojar_top_free.txt"

share|improve this question

edited 1 min ago

Guillermo Mosse

1031

asked Oct 30 '15 at 22:46

SamulSamul

18117

share|improve this question

edited 1 min ago

Guillermo Mosse

1031

asked Oct 30 '15 at 22:46

SamulSamul

18117

edited 1 min ago

Guillermo Mosse

1031

edited 1 min ago

Guillermo Mosse

1031

asked Oct 30 '15 at 22:46

SamulSamul

18117

asked Oct 30 '15 at 22:46

SamulSamul

18117

2 Answers
2

active

oldest

votes

1

As suggested by others, try to direct use the bash shebang in your script or prefix by using bash instead of sh. For I don't know what system you're actually running, I recently ran into trouble calling a script usign /bin/sh -c myscript.sh under ubuntu which is a debian derivate which uses dash instead of bash.

Maybe this is the key to your problem.

EDIT: I've got it working with this crontab entry, done as root with crontab -e:

*/1 * * * * /bin/bash -c "/test.sh"

share|improve this answer

edited Nov 3 '15 at 23:41

answered Nov 3 '15 at 23:19

ferdyferdy

1496

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Good catch re dash. However, the OP's script appears to run equivalently under bash, sh (for some value of sh) and dash.
  
  – roaima
  Nov 3 '15 at 23:22
  

  
  
  
  

add a comment | 

0

This version works for me. However, as your own script also works here I'm not entirely sure this will fix your problem.

System-wide crontab entry (omit the root field if this is root's own crontab, as accessed with crontab -e):

* * * * * root /root/test.sh

As far as I can detemine, your script takes the third iteration from top and collects the CPU usermode percentage. It also collects the cached memory value from free. Here I've dispensed with free and extracted the same value from the third iteration of top. Copy this script to /root/test.sh (and make it executable):

#!/bin/bash
top -b -n 3 -d 1 |
 awk -v date="$(date)" '
 /^%Cpu/ cpu=$2
 /cached Mem/ cached=$9
 END printf "n%st%st%s", date, cpu, cached
 ' >> /root/log_lojar_top_free.txt

Make the script executable:

chmod +x /root/test.sh

share|improve this answer

answered Nov 3 '15 at 23:11

roaimaroaima

45.4k757123

add a comment | 

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1

As suggested by others, try to direct use the bash shebang in your script or prefix by using bash instead of sh. For I don't know what system you're actually running, I recently ran into trouble calling a script usign /bin/sh -c myscript.sh under ubuntu which is a debian derivate which uses dash instead of bash.

Maybe this is the key to your problem.

EDIT: I've got it working with this crontab entry, done as root with crontab -e:

*/1 * * * * /bin/bash -c "/test.sh"

share|improve this answer

edited Nov 3 '15 at 23:41

answered Nov 3 '15 at 23:19

ferdyferdy

1496

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Good catch re dash. However, the OP's script appears to run equivalently under bash, sh (for some value of sh) and dash.
  
  – roaima
  Nov 3 '15 at 23:22
  

  
  
  
  

add a comment | 

1

As suggested by others, try to direct use the bash shebang in your script or prefix by using bash instead of sh. For I don't know what system you're actually running, I recently ran into trouble calling a script usign /bin/sh -c myscript.sh under ubuntu which is a debian derivate which uses dash instead of bash.

Maybe this is the key to your problem.

EDIT: I've got it working with this crontab entry, done as root with crontab -e:

*/1 * * * * /bin/bash -c "/test.sh"

share|improve this answer

edited Nov 3 '15 at 23:41

answered Nov 3 '15 at 23:19

ferdyferdy

1496

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Good catch re dash. However, the OP's script appears to run equivalently under bash, sh (for some value of sh) and dash.
  
  – roaima
  Nov 3 '15 at 23:22
  

  
  
  
  

add a comment | 

As suggested by others, try to direct use the bash shebang in your script or prefix by using bash instead of sh. For I don't know what system you're actually running, I recently ran into trouble calling a script usign /bin/sh -c myscript.sh under ubuntu which is a debian derivate which uses dash instead of bash.

Maybe this is the key to your problem.

EDIT: I've got it working with this crontab entry, done as root with crontab -e:

*/1 * * * * /bin/bash -c "/test.sh"

share|improve this answer

edited Nov 3 '15 at 23:41

answered Nov 3 '15 at 23:19

ferdyferdy

1496

*/1 * * * * /bin/bash -c "/test.sh"

share|improve this answer

edited Nov 3 '15 at 23:41

answered Nov 3 '15 at 23:19

ferdyferdy

1496

answered Nov 3 '15 at 23:19

ferdyferdy

1496

answered Nov 3 '15 at 23:19

ferdyferdy

1496

0

This version works for me. However, as your own script also works here I'm not entirely sure this will fix your problem.

System-wide crontab entry (omit the root field if this is root's own crontab, as accessed with crontab -e):

* * * * * root /root/test.sh

As far as I can detemine, your script takes the third iteration from top and collects the CPU usermode percentage. It also collects the cached memory value from free. Here I've dispensed with free and extracted the same value from the third iteration of top. Copy this script to /root/test.sh (and make it executable):

#!/bin/bash
top -b -n 3 -d 1 |
 awk -v date="$(date)" '
 /^%Cpu/ cpu=$2
 /cached Mem/ cached=$9
 END printf "n%st%st%s", date, cpu, cached
 ' >> /root/log_lojar_top_free.txt

Make the script executable:

chmod +x /root/test.sh

share|improve this answer

answered Nov 3 '15 at 23:11

roaimaroaima

45.4k757123

add a comment | 

0

This version works for me. However, as your own script also works here I'm not entirely sure this will fix your problem.

System-wide crontab entry (omit the root field if this is root's own crontab, as accessed with crontab -e):

* * * * * root /root/test.sh

As far as I can detemine, your script takes the third iteration from top and collects the CPU usermode percentage. It also collects the cached memory value from free. Here I've dispensed with free and extracted the same value from the third iteration of top. Copy this script to /root/test.sh (and make it executable):

#!/bin/bash
top -b -n 3 -d 1 |
 awk -v date="$(date)" '
 /^%Cpu/ cpu=$2
 /cached Mem/ cached=$9
 END printf "n%st%st%s", date, cpu, cached
 ' >> /root/log_lojar_top_free.txt

Make the script executable:

chmod +x /root/test.sh

share|improve this answer

answered Nov 3 '15 at 23:11

roaimaroaima

45.4k757123

add a comment | 

This version works for me. However, as your own script also works here I'm not entirely sure this will fix your problem.

System-wide crontab entry (omit the root field if this is root's own crontab, as accessed with crontab -e):

* * * * * root /root/test.sh

As far as I can detemine, your script takes the third iteration from top and collects the CPU usermode percentage. It also collects the cached memory value from free. Here I've dispensed with free and extracted the same value from the third iteration of top. Copy this script to /root/test.sh (and make it executable):

#!/bin/bash
top -b -n 3 -d 1 |
 awk -v date="$(date)" '
 /^%Cpu/ cpu=$2
 /cached Mem/ cached=$9
 END printf "n%st%st%s", date, cpu, cached
 ' >> /root/log_lojar_top_free.txt

Make the script executable:

chmod +x /root/test.sh

share|improve this answer

answered Nov 3 '15 at 23:11

roaimaroaima

45.4k757123

* * * * * root /root/test.sh

#!/bin/bash
top -b -n 3 -d 1 |
 awk -v date="$(date)" '
 /^%Cpu/ cpu=$2
 /cached Mem/ cached=$9
 END printf "n%st%st%s", date, cpu, cached
 ' >> /root/log_lojar_top_free.txt

chmod +x /root/test.sh

share|improve this answer

answered Nov 3 '15 at 23:11

roaimaroaima

45.4k757123

answered Nov 3 '15 at 23:11

roaimaroaima

45.4k757123

answered Nov 3 '15 at 23:11

roaimaroaima

45.4k757123