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Moving plot label
Scale Insetted Characters to PlotImagePadding or other means of getting whitespace when the PlotLabel is a Column or GridCustomizing FrameTicks in DistributionChartCannot Plot Output of SolveHow do I plot a U- form cylinderPut together two ListLinePlot with right alignmentHow to insert a plot into a figure with axes coincidenceProblem when customizing frame ticksEpilog relative to frameHow to plot a function using piecewise of two variables
$begingroup$
I am trying to place the plot title somewhere neat, to the left of x=0.
Plot[1/(1 + Exp[-x]), x, -10, 10,
PlotLabel ->
Framed@Pane[
"F (x)=!(*FractionBox[(1), (1 + *SuperscriptBox[(e),
(-x)])])", Alignment -> Right]]
I tried this but it's still sticking at the top of figure, any help appreciated!
plotting
$endgroup$
add a comment |
$begingroup$
I am trying to place the plot title somewhere neat, to the left of x=0.
Plot[1/(1 + Exp[-x]), x, -10, 10,
PlotLabel ->
Framed@Pane[
"F (x)=!(*FractionBox[(1), (1 + *SuperscriptBox[(e),
(-x)])])", Alignment -> Right]]
I tried this but it's still sticking at the top of figure, any help appreciated!
plotting
$endgroup$
add a comment |
$begingroup$
I am trying to place the plot title somewhere neat, to the left of x=0.
Plot[1/(1 + Exp[-x]), x, -10, 10,
PlotLabel ->
Framed@Pane[
"F (x)=!(*FractionBox[(1), (1 + *SuperscriptBox[(e),
(-x)])])", Alignment -> Right]]
I tried this but it's still sticking at the top of figure, any help appreciated!
plotting
$endgroup$
I am trying to place the plot title somewhere neat, to the left of x=0.
Plot[1/(1 + Exp[-x]), x, -10, 10,
PlotLabel ->
Framed@Pane[
"F (x)=!(*FractionBox[(1), (1 + *SuperscriptBox[(e),
(-x)])])", Alignment -> Right]]
I tried this but it's still sticking at the top of figure, any help appreciated!
plotting
plotting
asked 4 hours ago
rodger_kicksrodger_kicks
365
365
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
$begingroup$
You can use Inset[]
to add it to the graphics, instead it being a label:
Plot[1/(1 + Exp[-x]), x, -10, 10,
Epilog ->
Inset[Framed@
Pane["F (x)=!(*FractionBox[(1), (1 +
*SuperscriptBox[(e), (-x)])])", Alignment -> Right],
-1.5, 1, 1, 1]]
FWIW, I rather prefer the look of TraditionalForm
in this:
Plot[1/(1 + Exp[-x]), x, -10, 10,
Epilog -> Inset[Framed@
Pane[HoldForm[F[x] == 1/(1 + E^-x)], Alignment -> Right],
-1.5, 1, 1, 1]]
$endgroup$
add a comment |
$begingroup$
You can wrap your label with another Framed
with the options FrameStyle -> None
and FrameMargins -> 0, rightmargin, 0,0
with your choice of rightmargin
:
Plot[1/(1 + Exp[-x]), x, -10, 10,
PlotLabel -> Framed[Framed[Pane[HoldForm[F[x] = 1/(1 + E^-x)],
Alignment -> Right]],
FrameStyle -> None, FrameMargins -> 0, Scaled[.1], 0, 0]]
Use FrameMargins -> 0, Scaled[.14], 0, Scaled[.05]
to get
Update: An alternative way is to put the label in a dynamic, movable Epilog
:
DynamicModule[pt = Scaled[.5, 1],
Plot[1/(1 + Exp[-x]), x, -10, 10,
ImagePadding -> Automatic, Automatic, Automatic, Scaled[.05],
PlotRangeClipping -> False,
Epilog -> Dynamic[Locator[Dynamic[pt],
Panel[HoldForm[F[x] = 1/(1 + E^-x)]],
Background -> White, LocatorRegion -> Full]]]]
$endgroup$
$begingroup$
Isn't theTraditionalForm
unnecessary? (It's applied by default here, I think.)
$endgroup$
– Michael E2
3 hours ago
$begingroup$
Thank you @MichaelE2; good point.
$endgroup$
– kglr
3 hours ago
add a comment |
Your Answer
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
You can use Inset[]
to add it to the graphics, instead it being a label:
Plot[1/(1 + Exp[-x]), x, -10, 10,
Epilog ->
Inset[Framed@
Pane["F (x)=!(*FractionBox[(1), (1 +
*SuperscriptBox[(e), (-x)])])", Alignment -> Right],
-1.5, 1, 1, 1]]
FWIW, I rather prefer the look of TraditionalForm
in this:
Plot[1/(1 + Exp[-x]), x, -10, 10,
Epilog -> Inset[Framed@
Pane[HoldForm[F[x] == 1/(1 + E^-x)], Alignment -> Right],
-1.5, 1, 1, 1]]
$endgroup$
add a comment |
$begingroup$
You can use Inset[]
to add it to the graphics, instead it being a label:
Plot[1/(1 + Exp[-x]), x, -10, 10,
Epilog ->
Inset[Framed@
Pane["F (x)=!(*FractionBox[(1), (1 +
*SuperscriptBox[(e), (-x)])])", Alignment -> Right],
-1.5, 1, 1, 1]]
FWIW, I rather prefer the look of TraditionalForm
in this:
Plot[1/(1 + Exp[-x]), x, -10, 10,
Epilog -> Inset[Framed@
Pane[HoldForm[F[x] == 1/(1 + E^-x)], Alignment -> Right],
-1.5, 1, 1, 1]]
$endgroup$
add a comment |
$begingroup$
You can use Inset[]
to add it to the graphics, instead it being a label:
Plot[1/(1 + Exp[-x]), x, -10, 10,
Epilog ->
Inset[Framed@
Pane["F (x)=!(*FractionBox[(1), (1 +
*SuperscriptBox[(e), (-x)])])", Alignment -> Right],
-1.5, 1, 1, 1]]
FWIW, I rather prefer the look of TraditionalForm
in this:
Plot[1/(1 + Exp[-x]), x, -10, 10,
Epilog -> Inset[Framed@
Pane[HoldForm[F[x] == 1/(1 + E^-x)], Alignment -> Right],
-1.5, 1, 1, 1]]
$endgroup$
You can use Inset[]
to add it to the graphics, instead it being a label:
Plot[1/(1 + Exp[-x]), x, -10, 10,
Epilog ->
Inset[Framed@
Pane["F (x)=!(*FractionBox[(1), (1 +
*SuperscriptBox[(e), (-x)])])", Alignment -> Right],
-1.5, 1, 1, 1]]
FWIW, I rather prefer the look of TraditionalForm
in this:
Plot[1/(1 + Exp[-x]), x, -10, 10,
Epilog -> Inset[Framed@
Pane[HoldForm[F[x] == 1/(1 + E^-x)], Alignment -> Right],
-1.5, 1, 1, 1]]
answered 3 hours ago
Michael E2Michael E2
149k12200479
149k12200479
add a comment |
add a comment |
$begingroup$
You can wrap your label with another Framed
with the options FrameStyle -> None
and FrameMargins -> 0, rightmargin, 0,0
with your choice of rightmargin
:
Plot[1/(1 + Exp[-x]), x, -10, 10,
PlotLabel -> Framed[Framed[Pane[HoldForm[F[x] = 1/(1 + E^-x)],
Alignment -> Right]],
FrameStyle -> None, FrameMargins -> 0, Scaled[.1], 0, 0]]
Use FrameMargins -> 0, Scaled[.14], 0, Scaled[.05]
to get
Update: An alternative way is to put the label in a dynamic, movable Epilog
:
DynamicModule[pt = Scaled[.5, 1],
Plot[1/(1 + Exp[-x]), x, -10, 10,
ImagePadding -> Automatic, Automatic, Automatic, Scaled[.05],
PlotRangeClipping -> False,
Epilog -> Dynamic[Locator[Dynamic[pt],
Panel[HoldForm[F[x] = 1/(1 + E^-x)]],
Background -> White, LocatorRegion -> Full]]]]
$endgroup$
$begingroup$
Isn't theTraditionalForm
unnecessary? (It's applied by default here, I think.)
$endgroup$
– Michael E2
3 hours ago
$begingroup$
Thank you @MichaelE2; good point.
$endgroup$
– kglr
3 hours ago
add a comment |
$begingroup$
You can wrap your label with another Framed
with the options FrameStyle -> None
and FrameMargins -> 0, rightmargin, 0,0
with your choice of rightmargin
:
Plot[1/(1 + Exp[-x]), x, -10, 10,
PlotLabel -> Framed[Framed[Pane[HoldForm[F[x] = 1/(1 + E^-x)],
Alignment -> Right]],
FrameStyle -> None, FrameMargins -> 0, Scaled[.1], 0, 0]]
Use FrameMargins -> 0, Scaled[.14], 0, Scaled[.05]
to get
Update: An alternative way is to put the label in a dynamic, movable Epilog
:
DynamicModule[pt = Scaled[.5, 1],
Plot[1/(1 + Exp[-x]), x, -10, 10,
ImagePadding -> Automatic, Automatic, Automatic, Scaled[.05],
PlotRangeClipping -> False,
Epilog -> Dynamic[Locator[Dynamic[pt],
Panel[HoldForm[F[x] = 1/(1 + E^-x)]],
Background -> White, LocatorRegion -> Full]]]]
$endgroup$
$begingroup$
Isn't theTraditionalForm
unnecessary? (It's applied by default here, I think.)
$endgroup$
– Michael E2
3 hours ago
$begingroup$
Thank you @MichaelE2; good point.
$endgroup$
– kglr
3 hours ago
add a comment |
$begingroup$
You can wrap your label with another Framed
with the options FrameStyle -> None
and FrameMargins -> 0, rightmargin, 0,0
with your choice of rightmargin
:
Plot[1/(1 + Exp[-x]), x, -10, 10,
PlotLabel -> Framed[Framed[Pane[HoldForm[F[x] = 1/(1 + E^-x)],
Alignment -> Right]],
FrameStyle -> None, FrameMargins -> 0, Scaled[.1], 0, 0]]
Use FrameMargins -> 0, Scaled[.14], 0, Scaled[.05]
to get
Update: An alternative way is to put the label in a dynamic, movable Epilog
:
DynamicModule[pt = Scaled[.5, 1],
Plot[1/(1 + Exp[-x]), x, -10, 10,
ImagePadding -> Automatic, Automatic, Automatic, Scaled[.05],
PlotRangeClipping -> False,
Epilog -> Dynamic[Locator[Dynamic[pt],
Panel[HoldForm[F[x] = 1/(1 + E^-x)]],
Background -> White, LocatorRegion -> Full]]]]
$endgroup$
You can wrap your label with another Framed
with the options FrameStyle -> None
and FrameMargins -> 0, rightmargin, 0,0
with your choice of rightmargin
:
Plot[1/(1 + Exp[-x]), x, -10, 10,
PlotLabel -> Framed[Framed[Pane[HoldForm[F[x] = 1/(1 + E^-x)],
Alignment -> Right]],
FrameStyle -> None, FrameMargins -> 0, Scaled[.1], 0, 0]]
Use FrameMargins -> 0, Scaled[.14], 0, Scaled[.05]
to get
Update: An alternative way is to put the label in a dynamic, movable Epilog
:
DynamicModule[pt = Scaled[.5, 1],
Plot[1/(1 + Exp[-x]), x, -10, 10,
ImagePadding -> Automatic, Automatic, Automatic, Scaled[.05],
PlotRangeClipping -> False,
Epilog -> Dynamic[Locator[Dynamic[pt],
Panel[HoldForm[F[x] = 1/(1 + E^-x)]],
Background -> White, LocatorRegion -> Full]]]]
edited 3 hours ago
answered 4 hours ago
kglrkglr
188k10204422
188k10204422
$begingroup$
Isn't theTraditionalForm
unnecessary? (It's applied by default here, I think.)
$endgroup$
– Michael E2
3 hours ago
$begingroup$
Thank you @MichaelE2; good point.
$endgroup$
– kglr
3 hours ago
add a comment |
$begingroup$
Isn't theTraditionalForm
unnecessary? (It's applied by default here, I think.)
$endgroup$
– Michael E2
3 hours ago
$begingroup$
Thank you @MichaelE2; good point.
$endgroup$
– kglr
3 hours ago
$begingroup$
Isn't the
TraditionalForm
unnecessary? (It's applied by default here, I think.)$endgroup$
– Michael E2
3 hours ago
$begingroup$
Isn't the
TraditionalForm
unnecessary? (It's applied by default here, I think.)$endgroup$
– Michael E2
3 hours ago
$begingroup$
Thank you @MichaelE2; good point.
$endgroup$
– kglr
3 hours ago
$begingroup$
Thank you @MichaelE2; good point.
$endgroup$
– kglr
3 hours ago
add a comment |
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