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How can I have x-axis ticks that show ticks scaled in powers of ten?
How can I set the ratio of the axis to 1:1 when plotrange->1 or how can I scale a rectangle according to the axisHow can automatic ticks be made “outie”?ListPolarPlot not showing full plot range even with PlotRange -> AllChanging the axis ticks of a LogLogPlotHow to correct the name of axis?How to show an angle axis in a RevolutionPlot3D plotNot getting smooth motion when animating a 3D plot (with jumps in rotation)How I can rotate the x-axis FrameTicks?Whats the code for this surfaceplot?How to force Plot[..] to show the x-axis?
$begingroup$
I am having trouble achieving this effect with on the x-axis. Does anybody have an idea how I can achieve this effect?
plotting
New contributor
$endgroup$
add a comment |
$begingroup$
I am having trouble achieving this effect with on the x-axis. Does anybody have an idea how I can achieve this effect?
plotting
New contributor
$endgroup$
2
$begingroup$
As a slight correction to kglr's comment: the "number theory" version of the logarithmic integral is expressed asLogIntegral[x] - LogIntegral[2]
.
$endgroup$
– J. M. is computer-less♦
5 hours ago
add a comment |
$begingroup$
I am having trouble achieving this effect with on the x-axis. Does anybody have an idea how I can achieve this effect?
plotting
New contributor
$endgroup$
I am having trouble achieving this effect with on the x-axis. Does anybody have an idea how I can achieve this effect?
plotting
plotting
New contributor
New contributor
edited 3 hours ago
m_goldberg
87.4k872198
87.4k872198
New contributor
asked 5 hours ago
Kanye WestKanye West
92
92
New contributor
New contributor
2
$begingroup$
As a slight correction to kglr's comment: the "number theory" version of the logarithmic integral is expressed asLogIntegral[x] - LogIntegral[2]
.
$endgroup$
– J. M. is computer-less♦
5 hours ago
add a comment |
2
$begingroup$
As a slight correction to kglr's comment: the "number theory" version of the logarithmic integral is expressed asLogIntegral[x] - LogIntegral[2]
.
$endgroup$
– J. M. is computer-less♦
5 hours ago
2
2
$begingroup$
As a slight correction to kglr's comment: the "number theory" version of the logarithmic integral is expressed as
LogIntegral[x] - LogIntegral[2]
.$endgroup$
– J. M. is computer-less♦
5 hours ago
$begingroup$
As a slight correction to kglr's comment: the "number theory" version of the logarithmic integral is expressed as
LogIntegral[x] - LogIntegral[2]
.$endgroup$
– J. M. is computer-less♦
5 hours ago
add a comment |
1 Answer
1
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$begingroup$
LogLinearPlot[PrimePi[x]/(LogIntegral[x]-LogIntegral[2]),
PrimePi[x]/(x/Log[x]), x, 2, 10000000, GridLines -> None, 1]
Thanks: @J.M.iscomputer-less for the LogIntegral[2]
correction.
$endgroup$
add a comment |
Your Answer
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$begingroup$
LogLinearPlot[PrimePi[x]/(LogIntegral[x]-LogIntegral[2]),
PrimePi[x]/(x/Log[x]), x, 2, 10000000, GridLines -> None, 1]
Thanks: @J.M.iscomputer-less for the LogIntegral[2]
correction.
$endgroup$
add a comment |
$begingroup$
LogLinearPlot[PrimePi[x]/(LogIntegral[x]-LogIntegral[2]),
PrimePi[x]/(x/Log[x]), x, 2, 10000000, GridLines -> None, 1]
Thanks: @J.M.iscomputer-less for the LogIntegral[2]
correction.
$endgroup$
add a comment |
$begingroup$
LogLinearPlot[PrimePi[x]/(LogIntegral[x]-LogIntegral[2]),
PrimePi[x]/(x/Log[x]), x, 2, 10000000, GridLines -> None, 1]
Thanks: @J.M.iscomputer-less for the LogIntegral[2]
correction.
$endgroup$
LogLinearPlot[PrimePi[x]/(LogIntegral[x]-LogIntegral[2]),
PrimePi[x]/(x/Log[x]), x, 2, 10000000, GridLines -> None, 1]
Thanks: @J.M.iscomputer-less for the LogIntegral[2]
correction.
edited 5 hours ago
answered 5 hours ago
kglrkglr
187k10203421
187k10203421
add a comment |
add a comment |
Kanye West is a new contributor. Be nice, and check out our Code of Conduct.
Kanye West is a new contributor. Be nice, and check out our Code of Conduct.
Kanye West is a new contributor. Be nice, and check out our Code of Conduct.
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$begingroup$
As a slight correction to kglr's comment: the "number theory" version of the logarithmic integral is expressed as
LogIntegral[x] - LogIntegral[2]
.$endgroup$
– J. M. is computer-less♦
5 hours ago