Bash Script Case statement (if not logic)

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Bash Script Case statement (if not logic)














0















I wrote a small bash script, where it will try to find a word ERROR, if found resulting value will be non-zero variable numeric (for example, 25 I mentioned in the script but it is variable numeric value) and if not found, it will be 0.



My problem is, I want to use Case statement such as if output is not zero, only then execute this particular command



truncate -s 0 /root/test/wayfile.log && screen -X -S wowow quit &


script here



#! /bin/bash

case "$(grep ERROR /root/test/wayfile.log | wc -w)" in

25) echo "empty log file and kill screen: $(date)" >> /var/log/finderror.txt
truncate -s 0 /root/test/wayfile.log && screen -X -S wowow quit &
;;
0) # all ok
;;
esac








share


























    0















    I wrote a small bash script, where it will try to find a word ERROR, if found resulting value will be non-zero variable numeric (for example, 25 I mentioned in the script but it is variable numeric value) and if not found, it will be 0.



    My problem is, I want to use Case statement such as if output is not zero, only then execute this particular command



    truncate -s 0 /root/test/wayfile.log && screen -X -S wowow quit &


    script here



    #! /bin/bash

    case "$(grep ERROR /root/test/wayfile.log | wc -w)" in

    25) echo "empty log file and kill screen: $(date)" >> /var/log/finderror.txt
    truncate -s 0 /root/test/wayfile.log && screen -X -S wowow quit &
    ;;
    0) # all ok
    ;;
    esac








    share
























      0












      0








      0








      I wrote a small bash script, where it will try to find a word ERROR, if found resulting value will be non-zero variable numeric (for example, 25 I mentioned in the script but it is variable numeric value) and if not found, it will be 0.



      My problem is, I want to use Case statement such as if output is not zero, only then execute this particular command



      truncate -s 0 /root/test/wayfile.log && screen -X -S wowow quit &


      script here



      #! /bin/bash

      case "$(grep ERROR /root/test/wayfile.log | wc -w)" in

      25) echo "empty log file and kill screen: $(date)" >> /var/log/finderror.txt
      truncate -s 0 /root/test/wayfile.log && screen -X -S wowow quit &
      ;;
      0) # all ok
      ;;
      esac








      share














      I wrote a small bash script, where it will try to find a word ERROR, if found resulting value will be non-zero variable numeric (for example, 25 I mentioned in the script but it is variable numeric value) and if not found, it will be 0.



      My problem is, I want to use Case statement such as if output is not zero, only then execute this particular command



      truncate -s 0 /root/test/wayfile.log && screen -X -S wowow quit &


      script here



      #! /bin/bash

      case "$(grep ERROR /root/test/wayfile.log | wc -w)" in

      25) echo "empty log file and kill screen: $(date)" >> /var/log/finderror.txt
      truncate -s 0 /root/test/wayfile.log && screen -X -S wowow quit &
      ;;
      0) # all ok
      ;;
      esac






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