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2

1

From a discussion on useless use of cat.

I decided to see if It was possible to avoid some of the troubles by changing the owner of the pipe. So I did:

# cat | cat &
[1] 16500
# cd /proc/16500/fd
# ls -l
lr-x------ root root 0 -> pipe:[931613]
lrwx------ root root 1 -> /dev/tty1
lrwx------ root root 2 -> /dev/tty1
# chown --dereference daemon 0
# ls -l
lr-x------ root root 0 -> pipe:[931613]
lrwx------ root root 1 -> /dev/tty1
lrwx------ root root 2 -> /dev/tty1

I also tried chown and chown -L. No go. I'm convinced this is simply impossible, but why? They clearly have inodes. That 931613 is the inode number.

In the case I am actually interested in, the process on the right would be running at lower privileges and I'd kind of like it to own its own handles so that it can re-open them.

pipe chown

share|improve this question

asked yesterday

JoshuaJoshua

1,332816

put on hold as off-topic by Stephen Harris, muru, roaima, Kusalananda♦ 23 hours ago

This question appears to be off-topic. The users who voted to close gave this specific reason:

• "Questions describing a problem that can't be reproduced and seemingly went away on its own (or went away when a typo was fixed) are off-topic as they are unlikely to help future readers." – Stephen Harris, muru, roaima, Kusalananda

If this question can be reworded to fit the rules in the help center, please edit the question.

add a comment | 

2

1

From a discussion on useless use of cat.

I decided to see if It was possible to avoid some of the troubles by changing the owner of the pipe. So I did:

# cat | cat &
[1] 16500
# cd /proc/16500/fd
# ls -l
lr-x------ root root 0 -> pipe:[931613]
lrwx------ root root 1 -> /dev/tty1
lrwx------ root root 2 -> /dev/tty1
# chown --dereference daemon 0
# ls -l
lr-x------ root root 0 -> pipe:[931613]
lrwx------ root root 1 -> /dev/tty1
lrwx------ root root 2 -> /dev/tty1

I also tried chown and chown -L. No go. I'm convinced this is simply impossible, but why? They clearly have inodes. That 931613 is the inode number.

In the case I am actually interested in, the process on the right would be running at lower privileges and I'd kind of like it to own its own handles so that it can re-open them.

pipe chown

share|improve this question

asked yesterday

JoshuaJoshua

1,332816

put on hold as off-topic by Stephen Harris, muru, roaima, Kusalananda♦ 23 hours ago

This question appears to be off-topic. The users who voted to close gave this specific reason:

• "Questions describing a problem that can't be reproduced and seemingly went away on its own (or went away when a typo was fixed) are off-topic as they are unlikely to help future readers." – Stephen Harris, muru, roaima, Kusalananda

If this question can be reworded to fit the rules in the help center, please edit the question.

add a comment | 

From a discussion on useless use of cat.

I decided to see if It was possible to avoid some of the troubles by changing the owner of the pipe. So I did:

# cat | cat &
[1] 16500
# cd /proc/16500/fd
# ls -l
lr-x------ root root 0 -> pipe:[931613]
lrwx------ root root 1 -> /dev/tty1
lrwx------ root root 2 -> /dev/tty1
# chown --dereference daemon 0
# ls -l
lr-x------ root root 0 -> pipe:[931613]
lrwx------ root root 1 -> /dev/tty1
lrwx------ root root 2 -> /dev/tty1

I also tried chown and chown -L. No go. I'm convinced this is simply impossible, but why? They clearly have inodes. That 931613 is the inode number.

In the case I am actually interested in, the process on the right would be running at lower privileges and I'd kind of like it to own its own handles so that it can re-open them.

pipe chown

share|improve this question

asked yesterday

JoshuaJoshua

1,332816

# cat | cat &
[1] 16500
# cd /proc/16500/fd
# ls -l
lr-x------ root root 0 -> pipe:[931613]
lrwx------ root root 1 -> /dev/tty1
lrwx------ root root 2 -> /dev/tty1
# chown --dereference daemon 0
# ls -l
lr-x------ root root 0 -> pipe:[931613]
lrwx------ root root 1 -> /dev/tty1
lrwx------ root root 2 -> /dev/tty1

share|improve this question

asked yesterday

JoshuaJoshua

1,332816

share|improve this question

asked yesterday

JoshuaJoshua

1,332816

asked yesterday

JoshuaJoshua

1,332816

asked yesterday

JoshuaJoshua

1,332816

1 Answer
1

active

oldest

votes

0

Turns out I goofed up my ls command.

# ls -lL
lr-x------ daemon root 0 -> pipe:[931613]
lrwx------ root root 1 -> /dev/tty1
lrwx------ root root 2 -> /dev/tty1

share|improve this answer

answered yesterday

JoshuaJoshua

1,332816

add a comment | 

0

Turns out I goofed up my ls command.

# ls -lL
lr-x------ daemon root 0 -> pipe:[931613]
lrwx------ root root 1 -> /dev/tty1
lrwx------ root root 2 -> /dev/tty1

share|improve this answer

answered yesterday

JoshuaJoshua

1,332816

add a comment | 

0

Turns out I goofed up my ls command.

# ls -lL
lr-x------ daemon root 0 -> pipe:[931613]
lrwx------ root root 1 -> /dev/tty1
lrwx------ root root 2 -> /dev/tty1

share|improve this answer

answered yesterday

JoshuaJoshua

1,332816

add a comment | 

Turns out I goofed up my ls command.

# ls -lL
lr-x------ daemon root 0 -> pipe:[931613]
lrwx------ root root 1 -> /dev/tty1
lrwx------ root root 2 -> /dev/tty1

share|improve this answer

answered yesterday

JoshuaJoshua

1,332816

# ls -lL
lr-x------ daemon root 0 -> pipe:[931613]
lrwx------ root root 1 -> /dev/tty1
lrwx------ root root 2 -> /dev/tty1

share|improve this answer

answered yesterday

JoshuaJoshua

1,332816

answered yesterday

JoshuaJoshua

1,332816

answered yesterday

JoshuaJoshua

1,332816