How is it possible to add a double into an ArrayList of Integer? (Java)Java generics type erasure: when and what happens?type erasure in implementation of ArrayList in JavaHow do I efficiently iterate over each entry in a Java Map?How do I call one constructor from another in Java?How do I read / convert an InputStream into a String in Java?When to use LinkedList over ArrayList in Java?How do I generate random integers within a specific range in Java?How do I determine whether an array contains a particular value in Java?How do I declare and initialize an array in Java?How to split a string in JavaConverting 'ArrayList<String> to 'String[]' in JavaHow do I convert a String to an int in Java?
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How is it possible to add a double into an ArrayList of Integer? (Java)
Java generics type erasure: when and what happens?type erasure in implementation of ArrayList in JavaHow do I efficiently iterate over each entry in a Java Map?How do I call one constructor from another in Java?How do I read / convert an InputStream into a String in Java?When to use LinkedList over ArrayList in Java?How do I generate random integers within a specific range in Java?How do I determine whether an array contains a particular value in Java?How do I declare and initialize an array in Java?How to split a string in JavaConverting 'ArrayList<String> to 'String[]' in JavaHow do I convert a String to an int in Java?
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I try to understand how is it possible to have a Double
value into an ArrayList
of Integer
. The numList
is an ArrayList
of Integer
, and the value from it is a Double
.
This is the code:
package bounded.wildcards;
import java.util.ArrayList;
import java.util.List;
public class GenericsDemo
public static void main(String[] args)
// Invariance Workaround
List<Integer> numList = new ArrayList<>();
GenericsDemo.invarianceWorkaround(numList);
System.out.println(numList);
static <T extends Number> void invarianceWorkaround(List<T> list)
T element = (T) new Double(23.3);
list.add(element);
This will compile and run without an error.
java generics arraylist
add a comment |
I try to understand how is it possible to have a Double
value into an ArrayList
of Integer
. The numList
is an ArrayList
of Integer
, and the value from it is a Double
.
This is the code:
package bounded.wildcards;
import java.util.ArrayList;
import java.util.List;
public class GenericsDemo
public static void main(String[] args)
// Invariance Workaround
List<Integer> numList = new ArrayList<>();
GenericsDemo.invarianceWorkaround(numList);
System.out.println(numList);
static <T extends Number> void invarianceWorkaround(List<T> list)
T element = (T) new Double(23.3);
list.add(element);
This will compile and run without an error.
java generics arraylist
3
Possible duplicate of type erasure in implementation of ArrayList in Java
– vaxquis
Mar 28 at 13:19
1
also, stackoverflow.com/questions/339699/… and many others... I think that someone can find an exact duplicate, but they are are extremely closely related.
– vaxquis
Mar 28 at 13:20
Thank you for the links, I know about type erasure and add cast, but I cannot understand how is it possible to have an ArrayList of Integer with this Double value in it. And there is no exception when I run it.
– gaby
Mar 28 at 18:58
1
@gabv you're contradicting yourself. If you knew about type erasure, you'd understand why you can add anything toArrayList<Double>
at runtime... because the answer is because of type erasure. As such, it follows you must either not know about type erasure mechanism in Java or not understand it, which both mean you should learn more about it.
– vaxquis
Mar 28 at 21:20
add a comment |
I try to understand how is it possible to have a Double
value into an ArrayList
of Integer
. The numList
is an ArrayList
of Integer
, and the value from it is a Double
.
This is the code:
package bounded.wildcards;
import java.util.ArrayList;
import java.util.List;
public class GenericsDemo
public static void main(String[] args)
// Invariance Workaround
List<Integer> numList = new ArrayList<>();
GenericsDemo.invarianceWorkaround(numList);
System.out.println(numList);
static <T extends Number> void invarianceWorkaround(List<T> list)
T element = (T) new Double(23.3);
list.add(element);
This will compile and run without an error.
java generics arraylist
I try to understand how is it possible to have a Double
value into an ArrayList
of Integer
. The numList
is an ArrayList
of Integer
, and the value from it is a Double
.
This is the code:
package bounded.wildcards;
import java.util.ArrayList;
import java.util.List;
public class GenericsDemo
public static void main(String[] args)
// Invariance Workaround
List<Integer> numList = new ArrayList<>();
GenericsDemo.invarianceWorkaround(numList);
System.out.println(numList);
static <T extends Number> void invarianceWorkaround(List<T> list)
T element = (T) new Double(23.3);
list.add(element);
This will compile and run without an error.
java generics arraylist
java generics arraylist
edited Mar 28 at 13:18
gaby
asked Mar 28 at 11:45
gabygaby
571112
571112
3
Possible duplicate of type erasure in implementation of ArrayList in Java
– vaxquis
Mar 28 at 13:19
1
also, stackoverflow.com/questions/339699/… and many others... I think that someone can find an exact duplicate, but they are are extremely closely related.
– vaxquis
Mar 28 at 13:20
Thank you for the links, I know about type erasure and add cast, but I cannot understand how is it possible to have an ArrayList of Integer with this Double value in it. And there is no exception when I run it.
– gaby
Mar 28 at 18:58
1
@gabv you're contradicting yourself. If you knew about type erasure, you'd understand why you can add anything toArrayList<Double>
at runtime... because the answer is because of type erasure. As such, it follows you must either not know about type erasure mechanism in Java or not understand it, which both mean you should learn more about it.
– vaxquis
Mar 28 at 21:20
add a comment |
3
Possible duplicate of type erasure in implementation of ArrayList in Java
– vaxquis
Mar 28 at 13:19
1
also, stackoverflow.com/questions/339699/… and many others... I think that someone can find an exact duplicate, but they are are extremely closely related.
– vaxquis
Mar 28 at 13:20
Thank you for the links, I know about type erasure and add cast, but I cannot understand how is it possible to have an ArrayList of Integer with this Double value in it. And there is no exception when I run it.
– gaby
Mar 28 at 18:58
1
@gabv you're contradicting yourself. If you knew about type erasure, you'd understand why you can add anything toArrayList<Double>
at runtime... because the answer is because of type erasure. As such, it follows you must either not know about type erasure mechanism in Java or not understand it, which both mean you should learn more about it.
– vaxquis
Mar 28 at 21:20
3
3
Possible duplicate of type erasure in implementation of ArrayList in Java
– vaxquis
Mar 28 at 13:19
Possible duplicate of type erasure in implementation of ArrayList in Java
– vaxquis
Mar 28 at 13:19
1
1
also, stackoverflow.com/questions/339699/… and many others... I think that someone can find an exact duplicate, but they are are extremely closely related.
– vaxquis
Mar 28 at 13:20
also, stackoverflow.com/questions/339699/… and many others... I think that someone can find an exact duplicate, but they are are extremely closely related.
– vaxquis
Mar 28 at 13:20
Thank you for the links, I know about type erasure and add cast, but I cannot understand how is it possible to have an ArrayList of Integer with this Double value in it. And there is no exception when I run it.
– gaby
Mar 28 at 18:58
Thank you for the links, I know about type erasure and add cast, but I cannot understand how is it possible to have an ArrayList of Integer with this Double value in it. And there is no exception when I run it.
– gaby
Mar 28 at 18:58
1
1
@gabv you're contradicting yourself. If you knew about type erasure, you'd understand why you can add anything to
ArrayList<Double>
at runtime... because the answer is because of type erasure. As such, it follows you must either not know about type erasure mechanism in Java or not understand it, which both mean you should learn more about it.– vaxquis
Mar 28 at 21:20
@gabv you're contradicting yourself. If you knew about type erasure, you'd understand why you can add anything to
ArrayList<Double>
at runtime... because the answer is because of type erasure. As such, it follows you must either not know about type erasure mechanism in Java or not understand it, which both mean you should learn more about it.– vaxquis
Mar 28 at 21:20
add a comment |
1 Answer
1
active
oldest
votes
This is because of type erasure used with Java generics - the type checks are only performed at compile time for generic types, and the type info for generics is then erased, effectively turning List<Integer>
into List<Object>
.
My IDE warns you of an "Unchecked cast from Double to T". But the compiler couldn't be sure that your code is wrong, so it does not emit an error, just a warning.
Then at runtime, the type check is no longer present due to type erasure, so the code will run without error unless you perform some operation that fails due to incompatible runtime type. System.out.println()
is not such operation.
If you change the print code to
Integer num = numList.get(0);
System.out.println(num);
this will now involve runtime type check and will therefore fail:
java.lang.ClassCastException: java.lang.Double cannot be cast to java.lang.Integer
3
Note that aClassCastException
is emitted when one tries to do this:Integer i = numList.get(0)
.
– MC Emperor
Mar 28 at 11:57
@MCEmperor Thanks, added. I couldn't find a simple example to force type incompatibility - integer seems to basically have no meaningful methods that wouldn't either be static or already inNumber
.
– Jiri Tousek
Mar 28 at 12:06
2
@JiriTousek You may be interested in Java is Unsound. Basically all java compilers will add cast checks in places to avoid issues because they know that the type system is broken.
– Giacomo Alzetta
Mar 28 at 12:53
effectively turning intoList<Number>
notList<Object>
because of upper bound isNumber
. if its List<Object> then you can store String but you can't
– Akash Shah
Mar 28 at 13:00
@AkashShah I disagree:List<String> stringList = (List) numList; stringList.add("abc");
. Lots of compiler warnings, but compiles and runs nevertheless.
– Jiri Tousek
Mar 28 at 22:44
|
show 3 more comments
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oldest
votes
This is because of type erasure used with Java generics - the type checks are only performed at compile time for generic types, and the type info for generics is then erased, effectively turning List<Integer>
into List<Object>
.
My IDE warns you of an "Unchecked cast from Double to T". But the compiler couldn't be sure that your code is wrong, so it does not emit an error, just a warning.
Then at runtime, the type check is no longer present due to type erasure, so the code will run without error unless you perform some operation that fails due to incompatible runtime type. System.out.println()
is not such operation.
If you change the print code to
Integer num = numList.get(0);
System.out.println(num);
this will now involve runtime type check and will therefore fail:
java.lang.ClassCastException: java.lang.Double cannot be cast to java.lang.Integer
3
Note that aClassCastException
is emitted when one tries to do this:Integer i = numList.get(0)
.
– MC Emperor
Mar 28 at 11:57
@MCEmperor Thanks, added. I couldn't find a simple example to force type incompatibility - integer seems to basically have no meaningful methods that wouldn't either be static or already inNumber
.
– Jiri Tousek
Mar 28 at 12:06
2
@JiriTousek You may be interested in Java is Unsound. Basically all java compilers will add cast checks in places to avoid issues because they know that the type system is broken.
– Giacomo Alzetta
Mar 28 at 12:53
effectively turning intoList<Number>
notList<Object>
because of upper bound isNumber
. if its List<Object> then you can store String but you can't
– Akash Shah
Mar 28 at 13:00
@AkashShah I disagree:List<String> stringList = (List) numList; stringList.add("abc");
. Lots of compiler warnings, but compiles and runs nevertheless.
– Jiri Tousek
Mar 28 at 22:44
|
show 3 more comments
This is because of type erasure used with Java generics - the type checks are only performed at compile time for generic types, and the type info for generics is then erased, effectively turning List<Integer>
into List<Object>
.
My IDE warns you of an "Unchecked cast from Double to T". But the compiler couldn't be sure that your code is wrong, so it does not emit an error, just a warning.
Then at runtime, the type check is no longer present due to type erasure, so the code will run without error unless you perform some operation that fails due to incompatible runtime type. System.out.println()
is not such operation.
If you change the print code to
Integer num = numList.get(0);
System.out.println(num);
this will now involve runtime type check and will therefore fail:
java.lang.ClassCastException: java.lang.Double cannot be cast to java.lang.Integer
3
Note that aClassCastException
is emitted when one tries to do this:Integer i = numList.get(0)
.
– MC Emperor
Mar 28 at 11:57
@MCEmperor Thanks, added. I couldn't find a simple example to force type incompatibility - integer seems to basically have no meaningful methods that wouldn't either be static or already inNumber
.
– Jiri Tousek
Mar 28 at 12:06
2
@JiriTousek You may be interested in Java is Unsound. Basically all java compilers will add cast checks in places to avoid issues because they know that the type system is broken.
– Giacomo Alzetta
Mar 28 at 12:53
effectively turning intoList<Number>
notList<Object>
because of upper bound isNumber
. if its List<Object> then you can store String but you can't
– Akash Shah
Mar 28 at 13:00
@AkashShah I disagree:List<String> stringList = (List) numList; stringList.add("abc");
. Lots of compiler warnings, but compiles and runs nevertheless.
– Jiri Tousek
Mar 28 at 22:44
|
show 3 more comments
This is because of type erasure used with Java generics - the type checks are only performed at compile time for generic types, and the type info for generics is then erased, effectively turning List<Integer>
into List<Object>
.
My IDE warns you of an "Unchecked cast from Double to T". But the compiler couldn't be sure that your code is wrong, so it does not emit an error, just a warning.
Then at runtime, the type check is no longer present due to type erasure, so the code will run without error unless you perform some operation that fails due to incompatible runtime type. System.out.println()
is not such operation.
If you change the print code to
Integer num = numList.get(0);
System.out.println(num);
this will now involve runtime type check and will therefore fail:
java.lang.ClassCastException: java.lang.Double cannot be cast to java.lang.Integer
This is because of type erasure used with Java generics - the type checks are only performed at compile time for generic types, and the type info for generics is then erased, effectively turning List<Integer>
into List<Object>
.
My IDE warns you of an "Unchecked cast from Double to T". But the compiler couldn't be sure that your code is wrong, so it does not emit an error, just a warning.
Then at runtime, the type check is no longer present due to type erasure, so the code will run without error unless you perform some operation that fails due to incompatible runtime type. System.out.println()
is not such operation.
If you change the print code to
Integer num = numList.get(0);
System.out.println(num);
this will now involve runtime type check and will therefore fail:
java.lang.ClassCastException: java.lang.Double cannot be cast to java.lang.Integer
edited Mar 28 at 12:05
answered Mar 28 at 11:55
Jiri TousekJiri Tousek
10.6k52240
10.6k52240
3
Note that aClassCastException
is emitted when one tries to do this:Integer i = numList.get(0)
.
– MC Emperor
Mar 28 at 11:57
@MCEmperor Thanks, added. I couldn't find a simple example to force type incompatibility - integer seems to basically have no meaningful methods that wouldn't either be static or already inNumber
.
– Jiri Tousek
Mar 28 at 12:06
2
@JiriTousek You may be interested in Java is Unsound. Basically all java compilers will add cast checks in places to avoid issues because they know that the type system is broken.
– Giacomo Alzetta
Mar 28 at 12:53
effectively turning intoList<Number>
notList<Object>
because of upper bound isNumber
. if its List<Object> then you can store String but you can't
– Akash Shah
Mar 28 at 13:00
@AkashShah I disagree:List<String> stringList = (List) numList; stringList.add("abc");
. Lots of compiler warnings, but compiles and runs nevertheless.
– Jiri Tousek
Mar 28 at 22:44
|
show 3 more comments
3
Note that aClassCastException
is emitted when one tries to do this:Integer i = numList.get(0)
.
– MC Emperor
Mar 28 at 11:57
@MCEmperor Thanks, added. I couldn't find a simple example to force type incompatibility - integer seems to basically have no meaningful methods that wouldn't either be static or already inNumber
.
– Jiri Tousek
Mar 28 at 12:06
2
@JiriTousek You may be interested in Java is Unsound. Basically all java compilers will add cast checks in places to avoid issues because they know that the type system is broken.
– Giacomo Alzetta
Mar 28 at 12:53
effectively turning intoList<Number>
notList<Object>
because of upper bound isNumber
. if its List<Object> then you can store String but you can't
– Akash Shah
Mar 28 at 13:00
@AkashShah I disagree:List<String> stringList = (List) numList; stringList.add("abc");
. Lots of compiler warnings, but compiles and runs nevertheless.
– Jiri Tousek
Mar 28 at 22:44
3
3
Note that a
ClassCastException
is emitted when one tries to do this: Integer i = numList.get(0)
.– MC Emperor
Mar 28 at 11:57
Note that a
ClassCastException
is emitted when one tries to do this: Integer i = numList.get(0)
.– MC Emperor
Mar 28 at 11:57
@MCEmperor Thanks, added. I couldn't find a simple example to force type incompatibility - integer seems to basically have no meaningful methods that wouldn't either be static or already in
Number
.– Jiri Tousek
Mar 28 at 12:06
@MCEmperor Thanks, added. I couldn't find a simple example to force type incompatibility - integer seems to basically have no meaningful methods that wouldn't either be static or already in
Number
.– Jiri Tousek
Mar 28 at 12:06
2
2
@JiriTousek You may be interested in Java is Unsound. Basically all java compilers will add cast checks in places to avoid issues because they know that the type system is broken.
– Giacomo Alzetta
Mar 28 at 12:53
@JiriTousek You may be interested in Java is Unsound. Basically all java compilers will add cast checks in places to avoid issues because they know that the type system is broken.
– Giacomo Alzetta
Mar 28 at 12:53
effectively turning into
List<Number>
not List<Object>
because of upper bound is Number
. if its List<Object> then you can store String but you can't– Akash Shah
Mar 28 at 13:00
effectively turning into
List<Number>
not List<Object>
because of upper bound is Number
. if its List<Object> then you can store String but you can't– Akash Shah
Mar 28 at 13:00
@AkashShah I disagree:
List<String> stringList = (List) numList; stringList.add("abc");
. Lots of compiler warnings, but compiles and runs nevertheless.– Jiri Tousek
Mar 28 at 22:44
@AkashShah I disagree:
List<String> stringList = (List) numList; stringList.add("abc");
. Lots of compiler warnings, but compiles and runs nevertheless.– Jiri Tousek
Mar 28 at 22:44
|
show 3 more comments
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-arraylist, generics, java
3
Possible duplicate of type erasure in implementation of ArrayList in Java
– vaxquis
Mar 28 at 13:19
1
also, stackoverflow.com/questions/339699/… and many others... I think that someone can find an exact duplicate, but they are are extremely closely related.
– vaxquis
Mar 28 at 13:20
Thank you for the links, I know about type erasure and add cast, but I cannot understand how is it possible to have an ArrayList of Integer with this Double value in it. And there is no exception when I run it.
– gaby
Mar 28 at 18:58
1
@gabv you're contradicting yourself. If you knew about type erasure, you'd understand why you can add anything to
ArrayList<Double>
at runtime... because the answer is because of type erasure. As such, it follows you must either not know about type erasure mechanism in Java or not understand it, which both mean you should learn more about it.– vaxquis
Mar 28 at 21:20