Awk one-liner to print column of SQL table? Announcing the arrival of Valued Associate #679: Cesar Manara Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern) 2019 Community Moderator Election Results Why I closed the “Why is Kali so hard” questionSearch for a Value only in one column w.o using awk, sed, or perlsplitting a column using awksubstituting a column value using awkCompare two sql output files which have column names and print the difference into another fileHow to print first column of next line in current line?How to print a specific column condition using awk?Print column with AWKusing awk to print lines from one match through a second instance of a separate matchAWK - print last column along with empty valuecompare column of two files and print data accordingly
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Awk one-liner to print column of SQL table?
Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)
2019 Community Moderator Election Results
Why I closed the “Why is Kali so hard” questionSearch for a Value only in one column w.o using awk, sed, or perlsplitting a column using awksubstituting a column value using awkCompare two sql output files which have column names and print the difference into another fileHow to print first column of next line in current line?How to print a specific column condition using awk?Print column with AWKusing awk to print lines from one match through a second instance of a separate matchAWK - print last column along with empty valuecompare column of two files and print data accordingly
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Suppose I have table like:
This is first line
name minimum maximum config_value
----------------------------------- ----------- ----------- ------------
some text goes here for sample 0 1 0
Output Ends
The out should be like column 2nd:
minimum
-----------
0
What will be the awk command to generate the output like this?
linux awk sql
asked Apr 7 '15 at 7:12
snoopsnoop
224110
add a comment |
Suppose I have table like:
This is first line
name minimum maximum config_value
----------------------------------- ----------- ----------- ------------
some text goes here for sample 0 1 0
Output Ends
The out should be like column 2nd:
minimum
-----------
0
What will be the awk command to generate the output like this?
linux awk sql
asked Apr 7 '15 at 7:12
snoopsnoop
224110
"This is first line" and "Output Ends" are in the table?
– yeti
Apr 7 '15 at 7:59
"This is first line" and "Output Ends" should not be visible in output.
– snoop
Apr 7 '15 at 8:07
add a comment |
Suppose I have table like:
This is first line
name minimum maximum config_value
----------------------------------- ----------- ----------- ------------
some text goes here for sample 0 1 0
Output Ends
The out should be like column 2nd:
minimum
-----------
0
What will be the awk command to generate the output like this?
linux awk sql
asked Apr 7 '15 at 7:12
snoopsnoop
224110
Suppose I have table like:
This is first line
name minimum maximum config_value
----------------------------------- ----------- ----------- ------------
some text goes here for sample 0 1 0
Output Ends
The out should be like column 2nd:
minimum
-----------
0
What will be the awk command to generate the output like this?
linux awk sql
linux awk sql
asked Apr 7 '15 at 7:12
snoopsnoop
224110
asked Apr 7 '15 at 7:12
snoopsnoop
224110
asked Apr 7 '15 at 7:12
snoopsnoop
224110
asked Apr 7 '15 at 7:12
snoopsnoop
224110
asked Apr 7 '15 at 7:12
snoopsnoop
224110
224110
"This is first line" and "Output Ends" are in the table?
– yeti
Apr 7 '15 at 7:59
"This is first line" and "Output Ends" should not be visible in output.
– snoop
Apr 7 '15 at 8:07
add a comment |
"This is first line" and "Output Ends" are in the table?
– yeti
Apr 7 '15 at 7:59
"This is first line" and "Output Ends" should not be visible in output.
– snoop
Apr 7 '15 at 8:07
"This is first line" and "Output Ends" are in the table?
– yeti
Apr 7 '15 at 7:59
"This is first line" and "Output Ends" are in the table?
– yeti
Apr 7 '15 at 7:59
"This is first line" and "Output Ends" should not be visible in output.
– snoop
Apr 7 '15 at 8:07
"This is first line" and "Output Ends" should not be visible in output.
– snoop
Apr 7 '15 at 8:07
add a comment |
2 Answers
2
active
oldest
votes
If awk is not an substantial requirement, you could cut the file in pieces on fixed bytes (and grep away empty lines):
cut -b 37-47 data | grep -v '^$'
answered Apr 7 '15 at 8:21
FloHimselfFloHimself
6,71421419
andgrepaway those first and last marker lines
– Skaperen
Apr 7 '15 at 8:27
Be careful that length of first column may vary depending on the "name" value.
– apaul
Apr 7 '15 at 8:30
And start byte and length might vary. Well, this is more an example for usingcutto achieve what OP is asking for, based on the information the question offers, than an final solution.
– FloHimself
Apr 7 '15 at 8:34
add a comment |
I'm no awk guru, but if your output is always the same (I mean, second line is headers, and third line contains results), you can use something like this:
cat /tmp/test.txt | awk 'NR==2 headers=$0; start=0; len=0 NR==3 start=index($0," "); len=length($2)+1; print substr(headers,start,len) ; print substr($0,start,len) NR==4 print substr($0,start,len)'
Since it's length delimited fields, you can get the starting index and length of your field by reading the "underline" line (NR==3).
If your SQL returns more than one line, so you'd have to use something like if( NR > 1 && NR <= x ).
edited 11 hours ago
Rui F Ribeiro
42.1k1484142
answered Apr 7 '15 at 8:05
apaulapaul
2,5101913
Can we have an example which does not contain , in awk command? as I have to write this command in csv file.
– snoop
Apr 7 '15 at 8:14
@snoop : sorry, I'm not able to make it without comma. Can't you define another field separator for your CSV file? Otherway, are you really required to useawkonly as @FloHimself specified?
– apaul
Apr 7 '15 at 9:24
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
If awk is not an substantial requirement, you could cut the file in pieces on fixed bytes (and grep away empty lines):
cut -b 37-47 data | grep -v '^$'
answered Apr 7 '15 at 8:21
FloHimselfFloHimself
6,71421419
andgrepaway those first and last marker lines
– Skaperen
Apr 7 '15 at 8:27
Be careful that length of first column may vary depending on the "name" value.
– apaul
Apr 7 '15 at 8:30
And start byte and length might vary. Well, this is more an example for usingcutto achieve what OP is asking for, based on the information the question offers, than an final solution.
– FloHimself
Apr 7 '15 at 8:34
add a comment |
If awk is not an substantial requirement, you could cut the file in pieces on fixed bytes (and grep away empty lines):
cut -b 37-47 data | grep -v '^$'
answered Apr 7 '15 at 8:21
FloHimselfFloHimself
6,71421419
andgrepaway those first and last marker lines
– Skaperen
Apr 7 '15 at 8:27
Be careful that length of first column may vary depending on the "name" value.
– apaul
Apr 7 '15 at 8:30
And start byte and length might vary. Well, this is more an example for usingcutto achieve what OP is asking for, based on the information the question offers, than an final solution.
– FloHimself
Apr 7 '15 at 8:34
add a comment |
If awk is not an substantial requirement, you could cut the file in pieces on fixed bytes (and grep away empty lines):
cut -b 37-47 data | grep -v '^$'
answered Apr 7 '15 at 8:21
FloHimselfFloHimself
6,71421419
If awk is not an substantial requirement, you could cut the file in pieces on fixed bytes (and grep away empty lines):
cut -b 37-47 data | grep -v '^$'
answered Apr 7 '15 at 8:21
FloHimselfFloHimself
6,71421419
answered Apr 7 '15 at 8:21
FloHimselfFloHimself
6,71421419
answered Apr 7 '15 at 8:21
FloHimselfFloHimself
6,71421419
answered Apr 7 '15 at 8:21
FloHimselfFloHimself
6,71421419
6,71421419
andgrepaway those first and last marker lines
– Skaperen
Apr 7 '15 at 8:27
Be careful that length of first column may vary depending on the "name" value.
– apaul
Apr 7 '15 at 8:30
And start byte and length might vary. Well, this is more an example for usingcutto achieve what OP is asking for, based on the information the question offers, than an final solution.
– FloHimself
Apr 7 '15 at 8:34
add a comment |
andgrepaway those first and last marker lines
– Skaperen
Apr 7 '15 at 8:27
Be careful that length of first column may vary depending on the "name" value.
– apaul
Apr 7 '15 at 8:30
And start byte and length might vary. Well, this is more an example for usingcutto achieve what OP is asking for, based on the information the question offers, than an final solution.
– FloHimself
Apr 7 '15 at 8:34
and
grep away those first and last marker lines– Skaperen
Apr 7 '15 at 8:27
and
grep away those first and last marker lines– Skaperen
Apr 7 '15 at 8:27
Be careful that length of first column may vary depending on the "name" value.
– apaul
Apr 7 '15 at 8:30
Be careful that length of first column may vary depending on the "name" value.
– apaul
Apr 7 '15 at 8:30
And start byte and length might vary. Well, this is more an example for using
cut to achieve what OP is asking for, based on the information the question offers, than an final solution.– FloHimself
Apr 7 '15 at 8:34
And start byte and length might vary. Well, this is more an example for using
cut to achieve what OP is asking for, based on the information the question offers, than an final solution.– FloHimself
Apr 7 '15 at 8:34
add a comment |
I'm no awk guru, but if your output is always the same (I mean, second line is headers, and third line contains results), you can use something like this:
cat /tmp/test.txt | awk 'NR==2 headers=$0; start=0; len=0 NR==3 start=index($0," "); len=length($2)+1; print substr(headers,start,len) ; print substr($0,start,len) NR==4 print substr($0,start,len)'
Since it's length delimited fields, you can get the starting index and length of your field by reading the "underline" line (NR==3).
If your SQL returns more than one line, so you'd have to use something like if( NR > 1 && NR <= x ).
edited 11 hours ago
Rui F Ribeiro
42.1k1484142
answered Apr 7 '15 at 8:05
apaulapaul
2,5101913
Can we have an example which does not contain , in awk command? as I have to write this command in csv file.
– snoop
Apr 7 '15 at 8:14
@snoop : sorry, I'm not able to make it without comma. Can't you define another field separator for your CSV file? Otherway, are you really required to useawkonly as @FloHimself specified?
– apaul
Apr 7 '15 at 9:24
add a comment |
I'm no awk guru, but if your output is always the same (I mean, second line is headers, and third line contains results), you can use something like this:
cat /tmp/test.txt | awk 'NR==2 headers=$0; start=0; len=0 NR==3 start=index($0," "); len=length($2)+1; print substr(headers,start,len) ; print substr($0,start,len) NR==4 print substr($0,start,len)'
Since it's length delimited fields, you can get the starting index and length of your field by reading the "underline" line (NR==3).
If your SQL returns more than one line, so you'd have to use something like if( NR > 1 && NR <= x ).
edited 11 hours ago
Rui F Ribeiro
42.1k1484142
answered Apr 7 '15 at 8:05
apaulapaul
2,5101913
Can we have an example which does not contain , in awk command? as I have to write this command in csv file.
– snoop
Apr 7 '15 at 8:14
@snoop : sorry, I'm not able to make it without comma. Can't you define another field separator for your CSV file? Otherway, are you really required to useawkonly as @FloHimself specified?
– apaul
Apr 7 '15 at 9:24
add a comment |
I'm no awk guru, but if your output is always the same (I mean, second line is headers, and third line contains results), you can use something like this:
cat /tmp/test.txt | awk 'NR==2 headers=$0; start=0; len=0 NR==3 start=index($0," "); len=length($2)+1; print substr(headers,start,len) ; print substr($0,start,len) NR==4 print substr($0,start,len)'
Since it's length delimited fields, you can get the starting index and length of your field by reading the "underline" line (NR==3).
If your SQL returns more than one line, so you'd have to use something like if( NR > 1 && NR <= x ).
edited 11 hours ago
Rui F Ribeiro
42.1k1484142
answered Apr 7 '15 at 8:05
apaulapaul
2,5101913
I'm no awk guru, but if your output is always the same (I mean, second line is headers, and third line contains results), you can use something like this:
cat /tmp/test.txt | awk 'NR==2 headers=$0; start=0; len=0 NR==3 start=index($0," "); len=length($2)+1; print substr(headers,start,len) ; print substr($0,start,len) NR==4 print substr($0,start,len)'
Since it's length delimited fields, you can get the starting index and length of your field by reading the "underline" line (NR==3).
If your SQL returns more than one line, so you'd have to use something like if( NR > 1 && NR <= x ).
edited 11 hours ago
Rui F Ribeiro
42.1k1484142
answered Apr 7 '15 at 8:05
apaulapaul
2,5101913
edited 11 hours ago
Rui F Ribeiro
42.1k1484142
edited 11 hours ago
Rui F Ribeiro
42.1k1484142
edited 11 hours ago
Rui F Ribeiro
42.1k1484142
42.1k1484142
answered Apr 7 '15 at 8:05
apaulapaul
2,5101913
answered Apr 7 '15 at 8:05
apaulapaul
2,5101913
answered Apr 7 '15 at 8:05
apaulapaul
2,5101913
2,5101913
Can we have an example which does not contain , in awk command? as I have to write this command in csv file.
– snoop
Apr 7 '15 at 8:14
@snoop : sorry, I'm not able to make it without comma. Can't you define another field separator for your CSV file? Otherway, are you really required to useawkonly as @FloHimself specified?
– apaul
Apr 7 '15 at 9:24
add a comment |
Can we have an example which does not contain , in awk command? as I have to write this command in csv file.
– snoop
Apr 7 '15 at 8:14
@snoop : sorry, I'm not able to make it without comma. Can't you define another field separator for your CSV file? Otherway, are you really required to useawkonly as @FloHimself specified?
– apaul
Apr 7 '15 at 9:24
Can we have an example which does not contain , in awk command? as I have to write this command in csv file.
– snoop
Apr 7 '15 at 8:14
Can we have an example which does not contain , in awk command? as I have to write this command in csv file.
– snoop
Apr 7 '15 at 8:14
@snoop : sorry, I'm not able to make it without comma. Can't you define another field separator for your CSV file? Otherway, are you really required to use
awk only as @FloHimself specified?– apaul
Apr 7 '15 at 9:24
@snoop : sorry, I'm not able to make it without comma. Can't you define another field separator for your CSV file? Otherway, are you really required to use
awk only as @FloHimself specified?– apaul
Apr 7 '15 at 9:24
add a comment |
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-awk, linux, sql
"This is first line" and "Output Ends" are in the table?
– yeti
Apr 7 '15 at 7:59
"This is first line" and "Output Ends" should not be visible in output.
– snoop
Apr 7 '15 at 8:07