Ttyjfyk

Are babies of evil humanoid species inherently evil?

How does one describe somebody who is bi-racial?

Accepted offer letter, position changed

What's the "normal" opposite of flautando?

Filtering SOQL results with optional conditionals

Makefile strange variable substitution

Counting all the hearts

Virginia employer terminated employee and wants signing bonus returned

Can one live in the U.S. and not use a credit card?

How strictly should I take "Candidates must be local"?

In the late 1940’s to early 1950’s what technology was available that could melt a LOT of ice?

How do I express some one as a black person?

'The literal of type int is out of range' con número enteros pequeños (2 dígitos)

Hotkey (or other quick way) to insert a keyframe for only one component of a vector-valued property?

Examples of a statistic that is not independent of sample's distribution?

How can I get players to stop ignoring or overlooking the plot hooks I'm giving them?

How are showroom/display vehicles prepared?

Can Mathematica be used to create an Artistic 3D extrusion from a 2D image and wrap a line pattern around it?

An alternative proof of an application of Hahn-Banach

Conservation of Mass and Energy

Declaring and defining template, and specialising them

Should I tell my boss the work he did was worthless

Does a warlock using the Darkness/Devil's Sight combo still have advantage on ranged attacks against a target outside the Darkness?

Latex does not go to next line

How do I remove leading and trailing spaces AND underscores?

0

I have the spaces part working but is there a quick way to tag the underscores removal to it?

echo "" & [applescript string input] & "" | xargs

Context:

Applescript:

on trim(i)
 return (do shell script "echo "" & i & "" | xargs")
end trim

set input to " _someString "
set output to trim(input)

• Current output: "_some_String", as expected.


• Desired output: "some_String"

shell-script

share|improve this question

edited 3 hours ago

user3101259

asked 3 hours ago

user3101259user3101259

11

New contributor

user3101259 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Can you give some examples of expected input and output?
  
  – drewbenn
  3 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  What's the context you're doing this in? Where does the input come from, and what do you want to do with it? I'm also not sure what you're doing here in the command shown; xargs would remove whitespace in the input, but you're giving it a quoted string, and it doesn't remove the whitespace inside the quotes...
  
  – ilkkachu
  3 hours ago
  
  

  
  
  
  

add a comment | 

0

I have the spaces part working but is there a quick way to tag the underscores removal to it?

echo "" & [applescript string input] & "" | xargs

Context:

Applescript:

on trim(i)
 return (do shell script "echo "" & i & "" | xargs")
end trim

set input to " _someString "
set output to trim(input)

• Current output: "_some_String", as expected.


• Desired output: "some_String"

shell-script

share|improve this question

edited 3 hours ago

user3101259

asked 3 hours ago

user3101259user3101259

11

New contributor

user3101259 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Can you give some examples of expected input and output?
  
  – drewbenn
  3 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  What's the context you're doing this in? Where does the input come from, and what do you want to do with it? I'm also not sure what you're doing here in the command shown; xargs would remove whitespace in the input, but you're giving it a quoted string, and it doesn't remove the whitespace inside the quotes...
  
  – ilkkachu
  3 hours ago
  
  

  
  
  
  

add a comment | 

I have the spaces part working but is there a quick way to tag the underscores removal to it?

echo "" & [applescript string input] & "" | xargs

Context:

Applescript:

on trim(i)
 return (do shell script "echo "" & i & "" | xargs")
end trim

set input to " _someString "
set output to trim(input)

• Current output: "_some_String", as expected.


• Desired output: "some_String"

shell-script

share|improve this question

edited 3 hours ago

user3101259

asked 3 hours ago

user3101259user3101259

11

New contributor

user3101259 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

echo "" & [applescript string input] & "" | xargs

on trim(i)
 return (do shell script "echo "" & i & "" | xargs")
end trim

set input to " _someString "
set output to trim(input)

share|improve this question

edited 3 hours ago

user3101259

asked 3 hours ago

user3101259user3101259

11

New contributor

user3101259 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

share|improve this question

edited 3 hours ago

user3101259

asked 3 hours ago

user3101259user3101259

11

New contributor

user3101259 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

asked 3 hours ago

user3101259user3101259

11

New contributor

user3101259 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

asked 3 hours ago

user3101259user3101259

11

1 Answer
1

active

oldest

votes

0

Remove all spaces and underscores occurring before any other characters on the line:

sed 's/^[ _]*//'

• 
  ^ matches the beginning of the line


• 
  [] means match any of the characters within the brackets


• 
  * means 0 or more matches: does nothing if there are no matches (no leading spaces or underscores) but will match however many spaces and underscores there are.


• 
  / is a separator: sed will replace everything in the first section with everything in the second section (here, the second section is the empty set so the matched characters are simply removed)

Remove all spaces and underscores occurring after all other characters:

sed 's/[ _]*$//'

• 
  $ matches the end of the line

Put it all together:

$ echo ' a b c_ _'
 a b c_ _
$ echo ' a b c_ _' | sed -e 's/^[ _]*//' -e 's/[ _]*$//'
a b c

If you use it often, you could create an alias (though you'd have to be careful never to give it another argument or sed will complain) or, better, a function, like this:

$ foo() sed -e 's/^[ _]*//' -e 's/[ _]*$//' ; 
$ echo ' a b c_ _' | foo
a b c

share|improve this answer

answered 3 hours ago

drewbenndrewbenn

5,31051936

add a comment | 

Your Answer

StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "106"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);

else
createEditor();

);

function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);



);

user3101259 is a new contributor. Be nice, and check out our Code of Conduct.

draft saved

draft discarded

Sign up or log in

StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);

Sign up using Google

Sign up using Facebook

Sign up using Email and Password

Post as a guest

Name

Email

Required, but never shown

StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2funix.stackexchange.com%2fquestions%2f505741%2fhow-do-i-remove-leading-and-trailing-spaces-and-underscores%23new-answer', 'question_page');

);

Post as a guest

Name

Email

Required, but never shown

0

Remove all spaces and underscores occurring before any other characters on the line:

sed 's/^[ _]*//'

• 
  ^ matches the beginning of the line


• 
  [] means match any of the characters within the brackets


• 
  * means 0 or more matches: does nothing if there are no matches (no leading spaces or underscores) but will match however many spaces and underscores there are.


• 
  / is a separator: sed will replace everything in the first section with everything in the second section (here, the second section is the empty set so the matched characters are simply removed)

Remove all spaces and underscores occurring after all other characters:

sed 's/[ _]*$//'

• 
  $ matches the end of the line

Put it all together:

$ echo ' a b c_ _'
 a b c_ _
$ echo ' a b c_ _' | sed -e 's/^[ _]*//' -e 's/[ _]*$//'
a b c

If you use it often, you could create an alias (though you'd have to be careful never to give it another argument or sed will complain) or, better, a function, like this:

$ foo() sed -e 's/^[ _]*//' -e 's/[ _]*$//' ; 
$ echo ' a b c_ _' | foo
a b c

share|improve this answer

answered 3 hours ago

drewbenndrewbenn

5,31051936

add a comment | 

0

Remove all spaces and underscores occurring before any other characters on the line:

sed 's/^[ _]*//'

• 
  ^ matches the beginning of the line


• 
  [] means match any of the characters within the brackets


• 
  * means 0 or more matches: does nothing if there are no matches (no leading spaces or underscores) but will match however many spaces and underscores there are.


• 
  / is a separator: sed will replace everything in the first section with everything in the second section (here, the second section is the empty set so the matched characters are simply removed)

Remove all spaces and underscores occurring after all other characters:

sed 's/[ _]*$//'

• 
  $ matches the end of the line

Put it all together:

$ echo ' a b c_ _'
 a b c_ _
$ echo ' a b c_ _' | sed -e 's/^[ _]*//' -e 's/[ _]*$//'
a b c

If you use it often, you could create an alias (though you'd have to be careful never to give it another argument or sed will complain) or, better, a function, like this:

$ foo() sed -e 's/^[ _]*//' -e 's/[ _]*$//' ; 
$ echo ' a b c_ _' | foo
a b c

share|improve this answer

answered 3 hours ago

drewbenndrewbenn

5,31051936

add a comment | 

Remove all spaces and underscores occurring before any other characters on the line:

sed 's/^[ _]*//'

• 
  ^ matches the beginning of the line


• 
  [] means match any of the characters within the brackets


• 
  * means 0 or more matches: does nothing if there are no matches (no leading spaces or underscores) but will match however many spaces and underscores there are.


• 
  / is a separator: sed will replace everything in the first section with everything in the second section (here, the second section is the empty set so the matched characters are simply removed)

Remove all spaces and underscores occurring after all other characters:

sed 's/[ _]*$//'

• 
  $ matches the end of the line

Put it all together:

$ echo ' a b c_ _'
 a b c_ _
$ echo ' a b c_ _' | sed -e 's/^[ _]*//' -e 's/[ _]*$//'
a b c

If you use it often, you could create an alias (though you'd have to be careful never to give it another argument or sed will complain) or, better, a function, like this:

$ foo() sed -e 's/^[ _]*//' -e 's/[ _]*$//' ; 
$ echo ' a b c_ _' | foo
a b c

share|improve this answer

answered 3 hours ago

drewbenndrewbenn

5,31051936

sed 's/^[ _]*//'

sed 's/[ _]*$//'

$ echo ' a b c_ _'
 a b c_ _
$ echo ' a b c_ _' | sed -e 's/^[ _]*//' -e 's/[ _]*$//'
a b c

$ foo() sed -e 's/^[ _]*//' -e 's/[ _]*$//' ; 
$ echo ' a b c_ _' | foo
a b c

share|improve this answer

answered 3 hours ago

drewbenndrewbenn

5,31051936

answered 3 hours ago

drewbenndrewbenn

5,31051936

answered 3 hours ago

drewbenndrewbenn

5,31051936