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How do I get all objects in a nested array after performing a calculation in JavaScript?

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6

I have two different array objects and have a function which uses the objects and performs calculations. I would like to know how to perform calculations and get all the nested array objects in JavaScript as shown below (expected output).

var obj = [
 
 name: "insta",
 fee: "2",
 rate: "2.00"
 ,
 
 name: "transfer",
 fee: "1",
 rate: "3.00"
 
],
var query = 
 
 country: "SG",
 sourceamount: "4,000"
 
function config(objectdata, querydata)
 let send_amount = querydata.sourceamount.replace(/,/g,"");
 let fee = objectdata.fee;
 let rate = objectdata.rate;
 let amount_to_convert = send_amount - fee;
 let receive_amount = amount_to_convert * rate;
 let result_data = send: send_amount, fees: fee, ratevalue: rate, amountvalue :amount_to_convert, receive: receive_amount
 return result_data;


result = config(obj, query);

Expected Output:
result = [
 
 name: "insta",
 fees: "2",
 ratevalue: "2.00",
 amountvalue: "3998",
 receive: "7976"
 country: "SG",
 sourceamount: "4,000"
 ,

 name: "transfer",
 fees: "1",
 ratevalue: "3.00",
 amountvalue: "3997",
 receive: "11,991"
 country: "SG",
 sourceamount: "4,000"
 
]

javascript jquery arrays object

share|improve this question

edited Mar 27 at 22:08

Boann

37.4k1290122

asked Mar 27 at 9:24

SenthilSenthil

615

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  where did you iterate it?
  
  – M.Hemant
  Mar 27 at 9:31
  

  
  
  
  

add a comment | 

6

I have two different array objects and have a function which uses the objects and performs calculations. I would like to know how to perform calculations and get all the nested array objects in JavaScript as shown below (expected output).

var obj = [
 
 name: "insta",
 fee: "2",
 rate: "2.00"
 ,
 
 name: "transfer",
 fee: "1",
 rate: "3.00"
 
],
var query = 
 
 country: "SG",
 sourceamount: "4,000"
 
function config(objectdata, querydata)
 let send_amount = querydata.sourceamount.replace(/,/g,"");
 let fee = objectdata.fee;
 let rate = objectdata.rate;
 let amount_to_convert = send_amount - fee;
 let receive_amount = amount_to_convert * rate;
 let result_data = send: send_amount, fees: fee, ratevalue: rate, amountvalue :amount_to_convert, receive: receive_amount
 return result_data;


result = config(obj, query);

Expected Output:
result = [
 
 name: "insta",
 fees: "2",
 ratevalue: "2.00",
 amountvalue: "3998",
 receive: "7976"
 country: "SG",
 sourceamount: "4,000"
 ,

 name: "transfer",
 fees: "1",
 ratevalue: "3.00",
 amountvalue: "3997",
 receive: "11,991"
 country: "SG",
 sourceamount: "4,000"
 
]

javascript jquery arrays object

share|improve this question

edited Mar 27 at 22:08

Boann

37.4k1290122

asked Mar 27 at 9:24

SenthilSenthil

615

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  where did you iterate it?
  
  – M.Hemant
  Mar 27 at 9:31
  

  
  
  
  

add a comment | 

I have two different array objects and have a function which uses the objects and performs calculations. I would like to know how to perform calculations and get all the nested array objects in JavaScript as shown below (expected output).

var obj = [
 
 name: "insta",
 fee: "2",
 rate: "2.00"
 ,
 
 name: "transfer",
 fee: "1",
 rate: "3.00"
 
],
var query = 
 
 country: "SG",
 sourceamount: "4,000"
 
function config(objectdata, querydata)
 let send_amount = querydata.sourceamount.replace(/,/g,"");
 let fee = objectdata.fee;
 let rate = objectdata.rate;
 let amount_to_convert = send_amount - fee;
 let receive_amount = amount_to_convert * rate;
 let result_data = send: send_amount, fees: fee, ratevalue: rate, amountvalue :amount_to_convert, receive: receive_amount
 return result_data;


result = config(obj, query);

Expected Output:
result = [
 
 name: "insta",
 fees: "2",
 ratevalue: "2.00",
 amountvalue: "3998",
 receive: "7976"
 country: "SG",
 sourceamount: "4,000"
 ,

 name: "transfer",
 fees: "1",
 ratevalue: "3.00",
 amountvalue: "3997",
 receive: "11,991"
 country: "SG",
 sourceamount: "4,000"
 
]

javascript jquery arrays object

share|improve this question

edited Mar 27 at 22:08

Boann

37.4k1290122

asked Mar 27 at 9:24

SenthilSenthil

615

var obj = [
 
 name: "insta",
 fee: "2",
 rate: "2.00"
 ,
 
 name: "transfer",
 fee: "1",
 rate: "3.00"
 
],
var query = 
 
 country: "SG",
 sourceamount: "4,000"
 
function config(objectdata, querydata)
 let send_amount = querydata.sourceamount.replace(/,/g,"");
 let fee = objectdata.fee;
 let rate = objectdata.rate;
 let amount_to_convert = send_amount - fee;
 let receive_amount = amount_to_convert * rate;
 let result_data = send: send_amount, fees: fee, ratevalue: rate, amountvalue :amount_to_convert, receive: receive_amount
 return result_data;


result = config(obj, query);

Expected Output:
result = [
 
 name: "insta",
 fees: "2",
 ratevalue: "2.00",
 amountvalue: "3998",
 receive: "7976"
 country: "SG",
 sourceamount: "4,000"
 ,

 name: "transfer",
 fees: "1",
 ratevalue: "3.00",
 amountvalue: "3997",
 receive: "11,991"
 country: "SG",
 sourceamount: "4,000"
 
]

share|improve this question

edited Mar 27 at 22:08

Boann

37.4k1290122

asked Mar 27 at 9:24

SenthilSenthil

615

share|improve this question

edited Mar 27 at 22:08

Boann

37.4k1290122

asked Mar 27 at 9:24

SenthilSenthil

615

edited Mar 27 at 22:08

Boann

37.4k1290122

edited Mar 27 at 22:08

Boann

37.4k1290122

asked Mar 27 at 9:24

SenthilSenthil

615

asked Mar 27 at 9:24

SenthilSenthil

615

3 Answers
3

active

oldest

votes

3

You can use .map to loop your array and construct all your object.

var obj = [
 name: "insta",
 fee: "2",
 rate: "2.00"
 ,
 
 name: "transfer",
 fee: "1",
 rate: "3.00"
 
 ];
 var query = 
 country: "SG",
 sourceamount: "4,000"
 

function config(objectdata, querydata) 
 return objectdata.map(function(obj) 
 let send_amount = +querydata.sourceamount.replace(/,/g, "");
 let fee = +obj.fee;
 let rate = +obj.rate;
 let amount_to_convert = send_amount - fee;
 let receive_amount = amount_to_convert * rate;
 return 
 name: obj.name,
 fees: fee,
 ratevalue: rate,
 amountvalue: amount_to_convert,
 receive: receive_amount,
 ...querydata
 
 );



result = config(obj, query);

console.log(result)

share|improve this answer

edited Mar 27 at 9:59

answered Mar 27 at 9:34

R3tepR3tep

8,18382962

• 
  
  
  

  
  3
  

  
  
  
  
  
  

  
  
  doesnot match the expected output..
  
  – Maheer Ali
  Mar 27 at 9:38
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Still doesnot match expected output.
  
  – Maheer Ali
  Mar 27 at 9:51
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  From where send property come. And sourceamount which is expected output and 4000 should be "4,000"
  
  – Maheer Ali
  Mar 27 at 9:57
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @MaheerAli Come from the OP example code. And thanks for "4,000"
  
  – R3tep
  Mar 27 at 10:04
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I mistyped sourceamount there was send property in old code. But now its fine so +1
  
  – Maheer Ali
  Mar 27 at 10:06
  
  

  
  
  
  

add a comment | 

7

You need to map through the obj array and construct your output.

NOTE: You need to parse the fee-rate-sourceamount values if you want to perform arithmetic operations.

var obj = [
 name: "insta",
 fee: "2",
 rate: "2.00"
, 
 name: "transfer",
 fee: "1",
 rate: "3.00"
];

var query = 
 country: "SG",
 sourceamount: "4,000"
;

function config(objectdata, querydata) 

 let result_data = objectdata.map(function(obj) 

 let send_amount = parseInt(querydata.sourceamount.replace(/,/g, ""));
 let fee = parseInt(obj.fee);
 let rate = parseInt(obj.rate);
 
 let amount_to_convert = send_amount - fee;
 let receive_amount = amount_to_convert * rate;

 return 
 name: obj.name,
 fees: fee,
 ratevalue: rate,
 amountvalue: amount_to_convert,
 receive: receive_amount,
 country: querydata.country,
 sourceamount: send_amount,
 
 );

 return result_data;


console.log(config(obj, query));

share|improve this answer

edited Mar 27 at 11:13

answered Mar 27 at 9:34

Zakaria AcharkiZakaria Acharki

56.9k134471

add a comment | 

3

const array = [
 name: "insta",
 fee: "2",
 rate: "2.00"
, 
 name: "transfer",
 fee: "1",
 rate: "3.00"
]
const query = country: "SG", sourceamount: "4,000" 

function config (data, querydata) 
 const send_amount = querydata.sourceamount.replace(/,/g,"")
 
 return data.map(( fee, rate, ...rest ) => ( 
 fees: fee, 
 ratevalue: rate, 
 amountvalue: +send_amount - +fee, 
 receive: (+send_amount - +fee) * +rate,
 ...rest,
 ...querydata
 ))


result = config(array, query)

console.log(result)

share|improve this answer

edited Mar 27 at 9:54

answered Mar 27 at 9:49

Francis LeighFrancis Leigh

956313

add a comment | 

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3

You can use .map to loop your array and construct all your object.

var obj = [
 name: "insta",
 fee: "2",
 rate: "2.00"
 ,
 
 name: "transfer",
 fee: "1",
 rate: "3.00"
 
 ];
 var query = 
 country: "SG",
 sourceamount: "4,000"
 

function config(objectdata, querydata) 
 return objectdata.map(function(obj) 
 let send_amount = +querydata.sourceamount.replace(/,/g, "");
 let fee = +obj.fee;
 let rate = +obj.rate;
 let amount_to_convert = send_amount - fee;
 let receive_amount = amount_to_convert * rate;
 return 
 name: obj.name,
 fees: fee,
 ratevalue: rate,
 amountvalue: amount_to_convert,
 receive: receive_amount,
 ...querydata
 
 );



result = config(obj, query);

console.log(result)

share|improve this answer

edited Mar 27 at 9:59

answered Mar 27 at 9:34

R3tepR3tep

8,18382962

• 
  
  
  

  
  3
  

  
  
  
  
  
  

  
  
  doesnot match the expected output..
  
  – Maheer Ali
  Mar 27 at 9:38
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Still doesnot match expected output.
  
  – Maheer Ali
  Mar 27 at 9:51
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  From where send property come. And sourceamount which is expected output and 4000 should be "4,000"
  
  – Maheer Ali
  Mar 27 at 9:57
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @MaheerAli Come from the OP example code. And thanks for "4,000"
  
  – R3tep
  Mar 27 at 10:04
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I mistyped sourceamount there was send property in old code. But now its fine so +1
  
  – Maheer Ali
  Mar 27 at 10:06
  
  

  
  
  
  

add a comment | 

3

You can use .map to loop your array and construct all your object.

var obj = [
 name: "insta",
 fee: "2",
 rate: "2.00"
 ,
 
 name: "transfer",
 fee: "1",
 rate: "3.00"
 
 ];
 var query = 
 country: "SG",
 sourceamount: "4,000"
 

function config(objectdata, querydata) 
 return objectdata.map(function(obj) 
 let send_amount = +querydata.sourceamount.replace(/,/g, "");
 let fee = +obj.fee;
 let rate = +obj.rate;
 let amount_to_convert = send_amount - fee;
 let receive_amount = amount_to_convert * rate;
 return 
 name: obj.name,
 fees: fee,
 ratevalue: rate,
 amountvalue: amount_to_convert,
 receive: receive_amount,
 ...querydata
 
 );



result = config(obj, query);

console.log(result)

share|improve this answer

edited Mar 27 at 9:59

answered Mar 27 at 9:34

R3tepR3tep

8,18382962

• 
  
  
  

  
  3
  

  
  
  
  
  
  

  
  
  doesnot match the expected output..
  
  – Maheer Ali
  Mar 27 at 9:38
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Still doesnot match expected output.
  
  – Maheer Ali
  Mar 27 at 9:51
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  From where send property come. And sourceamount which is expected output and 4000 should be "4,000"
  
  – Maheer Ali
  Mar 27 at 9:57
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @MaheerAli Come from the OP example code. And thanks for "4,000"
  
  – R3tep
  Mar 27 at 10:04
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I mistyped sourceamount there was send property in old code. But now its fine so +1
  
  – Maheer Ali
  Mar 27 at 10:06
  
  

  
  
  
  

add a comment | 

You can use .map to loop your array and construct all your object.

var obj = [
 name: "insta",
 fee: "2",
 rate: "2.00"
 ,
 
 name: "transfer",
 fee: "1",
 rate: "3.00"
 
 ];
 var query = 
 country: "SG",
 sourceamount: "4,000"
 

function config(objectdata, querydata) 
 return objectdata.map(function(obj) 
 let send_amount = +querydata.sourceamount.replace(/,/g, "");
 let fee = +obj.fee;
 let rate = +obj.rate;
 let amount_to_convert = send_amount - fee;
 let receive_amount = amount_to_convert * rate;
 return 
 name: obj.name,
 fees: fee,
 ratevalue: rate,
 amountvalue: amount_to_convert,
 receive: receive_amount,
 ...querydata
 
 );



result = config(obj, query);

console.log(result)

share|improve this answer

edited Mar 27 at 9:59

answered Mar 27 at 9:34

R3tepR3tep

8,18382962

var obj = [
 name: "insta",
 fee: "2",
 rate: "2.00"
 ,
 
 name: "transfer",
 fee: "1",
 rate: "3.00"
 
 ];
 var query = 
 country: "SG",
 sourceamount: "4,000"
 

function config(objectdata, querydata) 
 return objectdata.map(function(obj) 
 let send_amount = +querydata.sourceamount.replace(/,/g, "");
 let fee = +obj.fee;
 let rate = +obj.rate;
 let amount_to_convert = send_amount - fee;
 let receive_amount = amount_to_convert * rate;
 return 
 name: obj.name,
 fees: fee,
 ratevalue: rate,
 amountvalue: amount_to_convert,
 receive: receive_amount,
 ...querydata
 
 );



result = config(obj, query);

console.log(result)

var obj = [
 name: "insta",
 fee: "2",
 rate: "2.00"
 ,
 
 name: "transfer",
 fee: "1",
 rate: "3.00"
 
 ];
 var query = 
 country: "SG",
 sourceamount: "4,000"
 

function config(objectdata, querydata) 
 return objectdata.map(function(obj) 
 let send_amount = +querydata.sourceamount.replace(/,/g, "");
 let fee = +obj.fee;
 let rate = +obj.rate;
 let amount_to_convert = send_amount - fee;
 let receive_amount = amount_to_convert * rate;
 return 
 name: obj.name,
 fees: fee,
 ratevalue: rate,
 amountvalue: amount_to_convert,
 receive: receive_amount,
 ...querydata
 
 );



result = config(obj, query);

console.log(result)

var obj = [
 name: "insta",
 fee: "2",
 rate: "2.00"
 ,
 
 name: "transfer",
 fee: "1",
 rate: "3.00"
 
 ];
 var query = 
 country: "SG",
 sourceamount: "4,000"
 

function config(objectdata, querydata) 
 return objectdata.map(function(obj) 
 let send_amount = +querydata.sourceamount.replace(/,/g, "");
 let fee = +obj.fee;
 let rate = +obj.rate;
 let amount_to_convert = send_amount - fee;
 let receive_amount = amount_to_convert * rate;
 return 
 name: obj.name,
 fees: fee,
 ratevalue: rate,
 amountvalue: amount_to_convert,
 receive: receive_amount,
 ...querydata
 
 );



result = config(obj, query);

console.log(result)

share|improve this answer

edited Mar 27 at 9:59

answered Mar 27 at 9:34

R3tepR3tep

8,18382962

answered Mar 27 at 9:34

R3tepR3tep

8,18382962

answered Mar 27 at 9:34

R3tepR3tep

8,18382962

7

You need to map through the obj array and construct your output.

NOTE: You need to parse the fee-rate-sourceamount values if you want to perform arithmetic operations.

var obj = [
 name: "insta",
 fee: "2",
 rate: "2.00"
, 
 name: "transfer",
 fee: "1",
 rate: "3.00"
];

var query = 
 country: "SG",
 sourceamount: "4,000"
;

function config(objectdata, querydata) 

 let result_data = objectdata.map(function(obj) 

 let send_amount = parseInt(querydata.sourceamount.replace(/,/g, ""));
 let fee = parseInt(obj.fee);
 let rate = parseInt(obj.rate);
 
 let amount_to_convert = send_amount - fee;
 let receive_amount = amount_to_convert * rate;

 return 
 name: obj.name,
 fees: fee,
 ratevalue: rate,
 amountvalue: amount_to_convert,
 receive: receive_amount,
 country: querydata.country,
 sourceamount: send_amount,
 
 );

 return result_data;


console.log(config(obj, query));

share|improve this answer

edited Mar 27 at 11:13

answered Mar 27 at 9:34

Zakaria AcharkiZakaria Acharki

56.9k134471

add a comment | 

7

You need to map through the obj array and construct your output.

NOTE: You need to parse the fee-rate-sourceamount values if you want to perform arithmetic operations.

var obj = [
 name: "insta",
 fee: "2",
 rate: "2.00"
, 
 name: "transfer",
 fee: "1",
 rate: "3.00"
];

var query = 
 country: "SG",
 sourceamount: "4,000"
;

function config(objectdata, querydata) 

 let result_data = objectdata.map(function(obj) 

 let send_amount = parseInt(querydata.sourceamount.replace(/,/g, ""));
 let fee = parseInt(obj.fee);
 let rate = parseInt(obj.rate);
 
 let amount_to_convert = send_amount - fee;
 let receive_amount = amount_to_convert * rate;

 return 
 name: obj.name,
 fees: fee,
 ratevalue: rate,
 amountvalue: amount_to_convert,
 receive: receive_amount,
 country: querydata.country,
 sourceamount: send_amount,
 
 );

 return result_data;


console.log(config(obj, query));

share|improve this answer

edited Mar 27 at 11:13

answered Mar 27 at 9:34

Zakaria AcharkiZakaria Acharki

56.9k134471

add a comment | 

You need to map through the obj array and construct your output.

NOTE: You need to parse the fee-rate-sourceamount values if you want to perform arithmetic operations.

var obj = [
 name: "insta",
 fee: "2",
 rate: "2.00"
, 
 name: "transfer",
 fee: "1",
 rate: "3.00"
];

var query = 
 country: "SG",
 sourceamount: "4,000"
;

function config(objectdata, querydata) 

 let result_data = objectdata.map(function(obj) 

 let send_amount = parseInt(querydata.sourceamount.replace(/,/g, ""));
 let fee = parseInt(obj.fee);
 let rate = parseInt(obj.rate);
 
 let amount_to_convert = send_amount - fee;
 let receive_amount = amount_to_convert * rate;

 return 
 name: obj.name,
 fees: fee,
 ratevalue: rate,
 amountvalue: amount_to_convert,
 receive: receive_amount,
 country: querydata.country,
 sourceamount: send_amount,
 
 );

 return result_data;


console.log(config(obj, query));

share|improve this answer

edited Mar 27 at 11:13

answered Mar 27 at 9:34

Zakaria AcharkiZakaria Acharki

56.9k134471

var obj = [
 name: "insta",
 fee: "2",
 rate: "2.00"
, 
 name: "transfer",
 fee: "1",
 rate: "3.00"
];

var query = 
 country: "SG",
 sourceamount: "4,000"
;

function config(objectdata, querydata) 

 let result_data = objectdata.map(function(obj) 

 let send_amount = parseInt(querydata.sourceamount.replace(/,/g, ""));
 let fee = parseInt(obj.fee);
 let rate = parseInt(obj.rate);
 
 let amount_to_convert = send_amount - fee;
 let receive_amount = amount_to_convert * rate;

 return 
 name: obj.name,
 fees: fee,
 ratevalue: rate,
 amountvalue: amount_to_convert,
 receive: receive_amount,
 country: querydata.country,
 sourceamount: send_amount,
 
 );

 return result_data;


console.log(config(obj, query));

var obj = [
 name: "insta",
 fee: "2",
 rate: "2.00"
, 
 name: "transfer",
 fee: "1",
 rate: "3.00"
];

var query = 
 country: "SG",
 sourceamount: "4,000"
;

function config(objectdata, querydata) 

 let result_data = objectdata.map(function(obj) 

 let send_amount = parseInt(querydata.sourceamount.replace(/,/g, ""));
 let fee = parseInt(obj.fee);
 let rate = parseInt(obj.rate);
 
 let amount_to_convert = send_amount - fee;
 let receive_amount = amount_to_convert * rate;

 return 
 name: obj.name,
 fees: fee,
 ratevalue: rate,
 amountvalue: amount_to_convert,
 receive: receive_amount,
 country: querydata.country,
 sourceamount: send_amount,
 
 );

 return result_data;


console.log(config(obj, query));

var obj = [
 name: "insta",
 fee: "2",
 rate: "2.00"
, 
 name: "transfer",
 fee: "1",
 rate: "3.00"
];

var query = 
 country: "SG",
 sourceamount: "4,000"
;

function config(objectdata, querydata) 

 let result_data = objectdata.map(function(obj) 

 let send_amount = parseInt(querydata.sourceamount.replace(/,/g, ""));
 let fee = parseInt(obj.fee);
 let rate = parseInt(obj.rate);
 
 let amount_to_convert = send_amount - fee;
 let receive_amount = amount_to_convert * rate;

 return 
 name: obj.name,
 fees: fee,
 ratevalue: rate,
 amountvalue: amount_to_convert,
 receive: receive_amount,
 country: querydata.country,
 sourceamount: send_amount,
 
 );

 return result_data;


console.log(config(obj, query));

share|improve this answer

edited Mar 27 at 11:13

answered Mar 27 at 9:34

Zakaria AcharkiZakaria Acharki

56.9k134471

answered Mar 27 at 9:34

Zakaria AcharkiZakaria Acharki

56.9k134471

answered Mar 27 at 9:34

Zakaria AcharkiZakaria Acharki

56.9k134471

3

const array = [
 name: "insta",
 fee: "2",
 rate: "2.00"
, 
 name: "transfer",
 fee: "1",
 rate: "3.00"
]
const query = country: "SG", sourceamount: "4,000" 

function config (data, querydata) 
 const send_amount = querydata.sourceamount.replace(/,/g,"")
 
 return data.map(( fee, rate, ...rest ) => ( 
 fees: fee, 
 ratevalue: rate, 
 amountvalue: +send_amount - +fee, 
 receive: (+send_amount - +fee) * +rate,
 ...rest,
 ...querydata
 ))


result = config(array, query)

console.log(result)

share|improve this answer

edited Mar 27 at 9:54

answered Mar 27 at 9:49

Francis LeighFrancis Leigh

956313

add a comment | 

3

const array = [
 name: "insta",
 fee: "2",
 rate: "2.00"
, 
 name: "transfer",
 fee: "1",
 rate: "3.00"
]
const query = country: "SG", sourceamount: "4,000" 

function config (data, querydata) 
 const send_amount = querydata.sourceamount.replace(/,/g,"")
 
 return data.map(( fee, rate, ...rest ) => ( 
 fees: fee, 
 ratevalue: rate, 
 amountvalue: +send_amount - +fee, 
 receive: (+send_amount - +fee) * +rate,
 ...rest,
 ...querydata
 ))


result = config(array, query)

console.log(result)

share|improve this answer

edited Mar 27 at 9:54

answered Mar 27 at 9:49

Francis LeighFrancis Leigh

956313

add a comment | 

const array = [
 name: "insta",
 fee: "2",
 rate: "2.00"
, 
 name: "transfer",
 fee: "1",
 rate: "3.00"
]
const query = country: "SG", sourceamount: "4,000" 

function config (data, querydata) 
 const send_amount = querydata.sourceamount.replace(/,/g,"")
 
 return data.map(( fee, rate, ...rest ) => ( 
 fees: fee, 
 ratevalue: rate, 
 amountvalue: +send_amount - +fee, 
 receive: (+send_amount - +fee) * +rate,
 ...rest,
 ...querydata
 ))


result = config(array, query)

console.log(result)

share|improve this answer

edited Mar 27 at 9:54

answered Mar 27 at 9:49

Francis LeighFrancis Leigh

956313

const array = [
 name: "insta",
 fee: "2",
 rate: "2.00"
, 
 name: "transfer",
 fee: "1",
 rate: "3.00"
]
const query = country: "SG", sourceamount: "4,000" 

function config (data, querydata) 
 const send_amount = querydata.sourceamount.replace(/,/g,"")
 
 return data.map(( fee, rate, ...rest ) => ( 
 fees: fee, 
 ratevalue: rate, 
 amountvalue: +send_amount - +fee, 
 receive: (+send_amount - +fee) * +rate,
 ...rest,
 ...querydata
 ))


result = config(array, query)

console.log(result)

const array = [
 name: "insta",
 fee: "2",
 rate: "2.00"
, 
 name: "transfer",
 fee: "1",
 rate: "3.00"
]
const query = country: "SG", sourceamount: "4,000" 

function config (data, querydata) 
 const send_amount = querydata.sourceamount.replace(/,/g,"")
 
 return data.map(( fee, rate, ...rest ) => ( 
 fees: fee, 
 ratevalue: rate, 
 amountvalue: +send_amount - +fee, 
 receive: (+send_amount - +fee) * +rate,
 ...rest,
 ...querydata
 ))


result = config(array, query)

console.log(result)

const array = [
 name: "insta",
 fee: "2",
 rate: "2.00"
, 
 name: "transfer",
 fee: "1",
 rate: "3.00"
]
const query = country: "SG", sourceamount: "4,000" 

function config (data, querydata) 
 const send_amount = querydata.sourceamount.replace(/,/g,"")
 
 return data.map(( fee, rate, ...rest ) => ( 
 fees: fee, 
 ratevalue: rate, 
 amountvalue: +send_amount - +fee, 
 receive: (+send_amount - +fee) * +rate,
 ...rest,
 ...querydata
 ))


result = config(array, query)

console.log(result)

share|improve this answer

edited Mar 27 at 9:54

answered Mar 27 at 9:49

Francis LeighFrancis Leigh

956313

answered Mar 27 at 9:49

Francis LeighFrancis Leigh

956313

answered Mar 27 at 9:49

Francis LeighFrancis Leigh

956313