QGIS - filter by polygon sizeWhich GIS Software is Right for small manufacturing trends analysis?How can I determine which raster attribute covers the highest area of a polygon?QGIS page setup SizeSimplifying boundaries of divisions of country using QGIS?Polygon in specific sizeImport CSV and join with another table to add geometry in QGISHow to combine/merge attribute data from 1 layer to another, polygon to point, merge attributes and wrap/carriage return attributesFilter features from a polygon shapefile in QGISClustering based on eqaul populationsHow to create circles around points
GFCI outlets - can they be repaired? Are they really needed at the end of a circuit?
Why is the sentence "Das ist eine Nase" correct?
Create test of text direction (luatex)
Sums of two squares in arithmetic progressions
Does int main() need a declaration on C++?
Are British MPs missing the point, with these 'Indicative Votes'?
Is it possible to map the firing of neurons in the human brain so as to stimulate artificial memories in someone else?
In Bayesian inference, why are some terms dropped from the posterior predictive?
Mathematica command that allows it to read my intentions
Machine learning testing data
Why did early computer designers eschew integers?
How to calculate the right interval for a timelapse on a boat
Does the Idaho Potato Commission associate potato skins with healthy eating?
Pact of Blade Warlock with Dancing Blade
Connect points with lines QGIS
How to find if SQL server backup is encrypted with TDE without restoring the backup
What was Prahlada's age when his father was killed?
How can a day be of 24 hours?
How badly should I try to prevent a user from XSSing themselves?
What is this scratchy sound on the acoustic guitar called?
Do creatures with a speed 0ft., fly 30ft. (hover) ever touch the ground?
What historical events would have to change in order to make 19th century "steampunk" technology possible?
Could the museum Saturn V's be refitted for one more flight?
What is the most common color to indicate the input-field is disabled?
QGIS - filter by polygon size
Which GIS Software is Right for small manufacturing trends analysis?How can I determine which raster attribute covers the highest area of a polygon?QGIS page setup SizeSimplifying boundaries of divisions of country using QGIS?Polygon in specific sizeImport CSV and join with another table to add geometry in QGISHow to combine/merge attribute data from 1 layer to another, polygon to point, merge attributes and wrap/carriage return attributesFilter features from a polygon shapefile in QGISClustering based on eqaul populationsHow to create circles around points
I'm very new to this so bear with me.
Hopefully a relatively simple query.
I have a city map with property boundaries and I am wanting to filter the boundaries by lot size. i.e just show lots (or polygons) of a certain size, or between two sizes. i.e. lots over 700m2, or lots between 800 and 900m2.
The information I have pulled in doesn't have an area column associated with it so thinking I will need to add my own expression?
Any help would be greatly apprecaited.
qgis
asked Mar 27 at 8:12
ThomasThomas
133
New contributor
Thomas is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
I'm very new to this so bear with me.
Hopefully a relatively simple query.
I have a city map with property boundaries and I am wanting to filter the boundaries by lot size. i.e just show lots (or polygons) of a certain size, or between two sizes. i.e. lots over 700m2, or lots between 800 and 900m2.
The information I have pulled in doesn't have an area column associated with it so thinking I will need to add my own expression?
Any help would be greatly apprecaited.
qgis
asked Mar 27 at 8:12
ThomasThomas
133
New contributor
Thomas is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
I'm very new to this so bear with me.
Hopefully a relatively simple query.
I have a city map with property boundaries and I am wanting to filter the boundaries by lot size. i.e just show lots (or polygons) of a certain size, or between two sizes. i.e. lots over 700m2, or lots between 800 and 900m2.
The information I have pulled in doesn't have an area column associated with it so thinking I will need to add my own expression?
Any help would be greatly apprecaited.
qgis
asked Mar 27 at 8:12
ThomasThomas
133
New contributor
Thomas is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
I'm very new to this so bear with me.
Hopefully a relatively simple query.
I have a city map with property boundaries and I am wanting to filter the boundaries by lot size. i.e just show lots (or polygons) of a certain size, or between two sizes. i.e. lots over 700m2, or lots between 800 and 900m2.
The information I have pulled in doesn't have an area column associated with it so thinking I will need to add my own expression?
Any help would be greatly apprecaited.
qgis
qgis
asked Mar 27 at 8:12
ThomasThomas
133
New contributor
Thomas is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked Mar 27 at 8:12
ThomasThomas
133
New contributor
Thomas is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked Mar 27 at 8:12
ThomasThomas
133
New contributor
Thomas is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked Mar 27 at 8:12
ThomasThomas
133
asked Mar 27 at 8:12
ThomasThomas
133
133
New contributor
Thomas is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Thomas is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Thomas is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
Just dig into the field calculator, the hints on each function are rather helpful. What you're looking for is $area, which gives you the area of a polygon in square meters - provided your CRS is a projected one (e.g. UTM).
Either you run the field calculator and then categorise your layer by the column containing the polygon size, or you directly tell the symbology to categorise based on $area (see screenshot).
answered Mar 27 at 8:19
ErikErik
3,364322
Thanks Erik! I've had a play around there and managed to get it to filter as I was after. My next question then: I am looking to filter data by information from two separate layers. i.e. by area from my boundaries layer, then by suburb location from my street address layer. Can this be done without combining them into one set of data?
– Thomas
Mar 27 at 9:01
It would be better if you asked this in a separate question, though I think there have been similar questions already.
– Erik
Mar 27 at 9:06
1
Ok will have a look around and repost if can't work it out. Thanks.
– Thomas
Mar 27 at 9:09
add a comment |
Your Answer
StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "79"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);
else
createEditor();
);
function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);
);
Thomas is a new contributor. Be nice, and check out our Code of Conduct.
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fgis.stackexchange.com%2fquestions%2f316807%2fqgis-filter-by-polygon-size%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Just dig into the field calculator, the hints on each function are rather helpful. What you're looking for is $area, which gives you the area of a polygon in square meters - provided your CRS is a projected one (e.g. UTM).
Either you run the field calculator and then categorise your layer by the column containing the polygon size, or you directly tell the symbology to categorise based on $area (see screenshot).
answered Mar 27 at 8:19
ErikErik
3,364322
Thanks Erik! I've had a play around there and managed to get it to filter as I was after. My next question then: I am looking to filter data by information from two separate layers. i.e. by area from my boundaries layer, then by suburb location from my street address layer. Can this be done without combining them into one set of data?
– Thomas
Mar 27 at 9:01
It would be better if you asked this in a separate question, though I think there have been similar questions already.
– Erik
Mar 27 at 9:06
1
Ok will have a look around and repost if can't work it out. Thanks.
– Thomas
Mar 27 at 9:09
add a comment |
Just dig into the field calculator, the hints on each function are rather helpful. What you're looking for is $area, which gives you the area of a polygon in square meters - provided your CRS is a projected one (e.g. UTM).
Either you run the field calculator and then categorise your layer by the column containing the polygon size, or you directly tell the symbology to categorise based on $area (see screenshot).
answered Mar 27 at 8:19
ErikErik
3,364322
Thanks Erik! I've had a play around there and managed to get it to filter as I was after. My next question then: I am looking to filter data by information from two separate layers. i.e. by area from my boundaries layer, then by suburb location from my street address layer. Can this be done without combining them into one set of data?
– Thomas
Mar 27 at 9:01
It would be better if you asked this in a separate question, though I think there have been similar questions already.
– Erik
Mar 27 at 9:06
1
Ok will have a look around and repost if can't work it out. Thanks.
– Thomas
Mar 27 at 9:09
add a comment |
Just dig into the field calculator, the hints on each function are rather helpful. What you're looking for is $area, which gives you the area of a polygon in square meters - provided your CRS is a projected one (e.g. UTM).
Either you run the field calculator and then categorise your layer by the column containing the polygon size, or you directly tell the symbology to categorise based on $area (see screenshot).
answered Mar 27 at 8:19
ErikErik
3,364322
Just dig into the field calculator, the hints on each function are rather helpful. What you're looking for is $area, which gives you the area of a polygon in square meters - provided your CRS is a projected one (e.g. UTM).
Either you run the field calculator and then categorise your layer by the column containing the polygon size, or you directly tell the symbology to categorise based on $area (see screenshot).
answered Mar 27 at 8:19
ErikErik
3,364322
answered Mar 27 at 8:19
ErikErik
3,364322
answered Mar 27 at 8:19
ErikErik
3,364322
answered Mar 27 at 8:19
ErikErik
3,364322
3,364322
Thanks Erik! I've had a play around there and managed to get it to filter as I was after. My next question then: I am looking to filter data by information from two separate layers. i.e. by area from my boundaries layer, then by suburb location from my street address layer. Can this be done without combining them into one set of data?
– Thomas
Mar 27 at 9:01
It would be better if you asked this in a separate question, though I think there have been similar questions already.
– Erik
Mar 27 at 9:06
1
Ok will have a look around and repost if can't work it out. Thanks.
– Thomas
Mar 27 at 9:09
add a comment |
Thanks Erik! I've had a play around there and managed to get it to filter as I was after. My next question then: I am looking to filter data by information from two separate layers. i.e. by area from my boundaries layer, then by suburb location from my street address layer. Can this be done without combining them into one set of data?
– Thomas
Mar 27 at 9:01
It would be better if you asked this in a separate question, though I think there have been similar questions already.
– Erik
Mar 27 at 9:06
1
Ok will have a look around and repost if can't work it out. Thanks.
– Thomas
Mar 27 at 9:09
Thanks Erik! I've had a play around there and managed to get it to filter as I was after. My next question then: I am looking to filter data by information from two separate layers. i.e. by area from my boundaries layer, then by suburb location from my street address layer. Can this be done without combining them into one set of data?
– Thomas
Mar 27 at 9:01
Thanks Erik! I've had a play around there and managed to get it to filter as I was after. My next question then: I am looking to filter data by information from two separate layers. i.e. by area from my boundaries layer, then by suburb location from my street address layer. Can this be done without combining them into one set of data?
– Thomas
Mar 27 at 9:01
It would be better if you asked this in a separate question, though I think there have been similar questions already.
– Erik
Mar 27 at 9:06
It would be better if you asked this in a separate question, though I think there have been similar questions already.
– Erik
Mar 27 at 9:06
1
1
Ok will have a look around and repost if can't work it out. Thanks.
– Thomas
Mar 27 at 9:09
Ok will have a look around and repost if can't work it out. Thanks.
– Thomas
Mar 27 at 9:09
add a comment |
Thomas is a new contributor. Be nice, and check out our Code of Conduct.
Thomas is a new contributor. Be nice, and check out our Code of Conduct.
Thomas is a new contributor. Be nice, and check out our Code of Conduct.
Thomas is a new contributor. Be nice, and check out our Code of Conduct.
Thanks for contributing an answer to Geographic Information Systems Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fgis.stackexchange.com%2fquestions%2f316807%2fqgis-filter-by-polygon-size%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
-qgis
